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GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test - GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23)

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) below.
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GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 1

Choose the sentence that is most clearly written and has the best construction.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 1
The verbs got and took agree in tense in option 1 only.
GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 2

In the question given below there are three statements followed by three conclusions. You have to read the given three statements and take them to be true even if they seem to be at variance from commonly known facts. Read the conclusions and then decide which of the conclusions logically follows from the given three statements, disregarding commonly known facts.

Statements :

(i) All airports are tidy.

(ii) Some departments are neat.

(iii) Some airports are departments.

Conclusions :

(i) Some departments are tidy.

(ii) Some airports are neat.

(iii) No neat is airport.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 2
Now let us first dissect the case. Look at the venn diagrams given in the explanation, we get two possibilities. Case 1, is that the set of neat is outside the set airports. Case 2, is that set of neat is enclosed in the set of airports as we are told that some airports are departments, hence set of departments may be inside the set of airports or it may just intersect the set of airports. It is clear from the diagram that (i) necessarity follows and out of (ii) and (iii), atleast one conclusion is necessarily true.

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GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 3

Directions: Indicate the meaning of the underlined part.

Our economy has been damaged to a large extent by some mealy mouthed politicians.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 3
'Mealy-mouthed' means 'not brave enough to say what one means directly and honestly'.The closest word in meaning to this is 'untrustworthy'.
GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 4

The following sentence has been divided into four parts indicated by a number. One of the parts contains a usage or grammar error. Mark that number indicating that part of the sentence as your answer.

Those who want to develop (A)/the rainforests have played (B)/down the impact of (C)/ his human inhabitants.(D)

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 4
Pronoun inconsistency.The pronoun should be ‘their’ instead of ‘his’ as it refers to rainforests.So, option (D) should be corrected.
GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 5

Given the sequence of terms, AD CG FK JP, the next term would be

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 5

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 6

The expression x2 + 2bx + 3b2 leaves a remainder 3 when divided by (x + b). The value of b is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 6
f(x) = x2 + 2bx + 3b 2

f(–b) = b2 – 2b2 + 3b2 = 3

2b2 = 3

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 7

A dishonest milkman mixes 20 litres of water with 80 litres of milk. After selling one-fourth of this mixture, he adds water to replenish the quantity that he had sold. What is the current proportion of water to milk?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 7
100 litres of mixture has 80 litres of milk and 20 litres of water.

When 25 litres of mixture is taken out, it contains 20 litres of milk and 5 litres of water.

So, milk left = 60 litres and water left = 15 litres.

If 25 litres of water is added, then ratio of water to milk = 40 : 60 = 2 : 3

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 8

Because of a leak, a tank which usually is filled in 3 hr, now takes 3.5 hr to be filled. The leak alone will empty the filled tank in

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 8
Alternately, in 3.5 hr the leak empties that mush part that is filled in 0.5 hr by inlet, i.e. one sixth of the tank (because it takes 3 hr to fill the entire tank, in 0.5 hr, one sixth of tank is filled). Thus, it takes 3.5✖6 hr to empty filled tank.
GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 9

Directions: In this question, the second figure of the problem figures bears a certain relationship to the first figure. Similarly, one of the figures in the answer figures bears the same relationship to the third problem figure. You have to select the figure from the set of answer figures which would replace the sign of question mark (?).

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 9
Just as problem figure 2 is the mirror image of problem figure 1, answer figure (c) is the mirror images of problem figure (3).

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 10

A speaks the truth in 70% cases and B in 80% cases. The probability that they will

contradict each other in describing a single event is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 10
Probability that A and B will contradict each other is that A speaks truth and B lies

and B speaks truth. Let the probability be P(x). Probability of A speaking truth is P(A) and probability of B speaking truth isP(B)

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 11

From Set A = {2, 3, 4, 5} and Set B = {11, 12, 13, 14, 15}, two numbers are randomly selected, one from each set. The probability that the sum of the two numbers equals 16 is ___. (Answer up to one decimal place)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 11
Set A = {2, 3, 4, 5}

Set B = {11, 12, 13, 14, 15}

Two numbers are chosen, one from set A and other from set B.

Then,

Total = 4 × 5 = 20 cases

Favourable case: Sum of two numbers equals 16.

{(5, 11), (4, 12), (3, 13), (2, 14)}

i.e. Number of favourable cases = 4

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 12

The rectification efficiency of a single phase Half Wave Controlled Rectifier having a resistive load and the delay angle of π/2 is _______%. (correct upto two decimal places


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 12
Given

Single phase Half Wave Controlled Rectifier

Resistive load

∝= π/2

Rectification efficiency

,

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 13

The value of integral is . Find the value of x. (Answer up to the nearest integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 13
We have

Aliter 2. Use Walli's Rule

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 14

A single-phase transformer is rated 220/440 V,5 kVA, leakage reactance measured from the low-tension side is 0.05Ω . The per unit leakage reactance will be _______.

(Give up to four decimal places).


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 14

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 15

The probabilities of A, B and C solving a problem are 1/3, 2/7 and 3/8, respectively. If all three try to solve the problem simultaneously, then the probability that exactly one of them will solve it is x/56. Find the value of x. (Answer up to the nearest integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 15
Let E1, E2 and E3 be the events that the problem is solved by A, B and C, respectively. Then,

P(E1) = 1/3, P(E2) = 2/7 and P(E3) = 3/8

Exactly one of A, B and C can solve the problem in the following mutually exclusive ways.

(i) A solves and B and C do not solve.

(ii) B solves and A and C do not solve.

(iii) C solves and A and B do not solve.

Probability that only one will solve the problem

= P(A) and P(not B) and P(not C) + P(not A) and P(B) and P(not C) + P(not A) and P(not B) and P(C)

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 16

A 230 V,50 Hz,4-pole,single-phase induction motor is rotating (running) clockwise (forward) direction at a speed of 1425 rpm. If the rotor resistance at standstill is7.8Ω then the effective rotor resistance in the backward branch of the equivalent circuit will be.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 16
Given

Frequency = 50 Hz

Poles = 4

Speed = 1425 rpm

Rotor resistance r2 = 7.8Ω

Slip due to forward field, sf = (1500 - 1425)/1500 = 75/1500 = 0.05

Rotor resistance due to backward field

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 17

Let X1 and X2 be two independent exponentially distributed random variables with means 0.5 and 0.25, respectively. Then Y = min (X1, X2) is exponentially distributed with mean x/6 . Find the value of x. (Answer up to the nearest integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 17
We know that, if X1 and X2 are independent and exponential R. V's with

parameters λ1 and λ2 then X = min(X1, X2) is exponential R.V with parameter

Mean of Y = E(Y) = 1/6

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 18

A 420 V, 6 pole, 50 Hz star connected induction rotor has stator impedance of 0.07 + j 0.3 ohms and stand still impedance referred to stator is 0.08 + j 0.37 ohms. If the magnetizing current is neglected, the slip at maximum internal torque developed is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 18

For maximum slip,

s = 0.1187

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 19

Synchronous reactance is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 19
Both the magnetisation reactance and the leakage reactance are present at the same time.

It is rather difficult to separate one reactance from the other. For this reason, the two reactances are combined together and the sum is called synchronous reactance.

Xs = Xm + Xa

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 20

The value of contour integral in the complex plane , along the contour , taken counter clockwise is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 20
Given

(ii)Contour C is in counter clockwise direction

f(z) has pole of order two at z=1

The residue of f(z) at pole z=1 is,

Therefore, by cauchy’s residue theorem,

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 21

A radial transmission system with the ratings and reactances of the various components is shown in the following figure. A load of 60 MW at 0.9 power factor lagging is fed from the 66 kV substation which is to be maintained at 60 kV. The terminal voltage (line) of the synchronous machine (M) is __________kV. (Answer up to the nearest integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 21
Choose 100 MVA base and represent all quantities in pu, we get

Reactance of the first transformer XT1 = 0.1 pu

Reactance of the second transformer XT2 = 0.08 pu

Reactance of transmission line XL = 150 x 100/(200)2 = 0.31 pu

Load in pu 60/100 = 0.6 pu MW;0.9 pf lagging

Generator terminal voltage

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 22

Consider the circuit shown below, the ratio of is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 22
Given circuit is shown below,

Now from figure :

… (i)

From equations (i) and (ii),

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 23

The closed loop transfer function of a system is

The number of poles in LHP, RHP, and on axis are

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 23
Routh table is as shown below

No sign change exist from the s4 row down to the s0 row. Thus, the even polynomial does not have RHP poles. Therefore because of symmetry all four poles must be on jω-axis.

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 24

Consider the open loop transfer function of a closed loop negative feedback system given by

The value of K at the respective break points are

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 24
Given

Calculation of break points

∴ s = -6, s = -12 are break points

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 25

A student has made a 3-bit binary down counter and connected to the R-2R ladder type DAC [Gain = ] as shown in the figure to generate a staircase waveform. The output achieved is different as shown in the figure.

What could be the possible cause of this error?

(d)The R and 2R resistances are interchanged.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 25
The general circuit diagram of the DAC is as follow

Here LSB and MSB are not correct. The interconnection from the counter to DAC is not proper. The lines corresponding to bits D2 and D0 are interchanged due to the output conditions as given below:

*Multiple options can be correct
GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 26

A digit counter timer is set in the frequency mode of operation with gating time of 2 sec. For a specific input, reading obtained is 10000. The counter-timer is changed to operate in period mode with 2μsec scale without disconnecting the input.

Which of the following statement(s) is/are correct?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 26

Given

In frequency mode,

Gating time = 2sec

Reading = 10000

In period mode,

Time scale(ts) =2μsec .

In frequency mode of operation,

In period mode of operation,

Reading = Number of pulses = Tin/Ts

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 27

Thermal runaway in a transistor biased in the active region is due to

1. Heating of the transistor

2. Change in β due to increase in temperature

3. Change in reverse collector saturation current due to rise in temperature

4. Base emitter voltage VBE which decreases with rise in temperature

Which of the above statements is/are correct?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 27
When an input signal is applied, the output signal should not move the transistor either to saturation or to cut-off. However, this unwanted shift still might occur, due to the following reasons

1. Parameters of transistors depend on junction temperature. As junction temperature increases, leakage current due to minority charge carriers (ICBO) increases. As ICBO increases, ICEO also increases, causing an increase in collector current IC. This produces heat the collector junction. This process repeats, and, finally, the Q-point may shift into the saturation region. Sometimes, the excess heat produced at the junction may even burn the transistor. This is known as thermal runaway.

2. When a transistor is replaced by another of the same type, the Q-point may shift, due to changes in parameters of the transistor, such as current gain (β) which varies slightly for each unique transistor and also temperature dependent.

3. Thermal runaway in a transistor biased in the active region is due to change in reverse collector saturation current due to rise in temperature.

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 28

The time period (in sec) of the signal x(n) = (j+1)n/2 (in integer) is________.


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 28
Given signal is, x(n) = (j+1)n/2

Fundamental frequency,

The time period of the signal is N = 16sec .

GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 29

Four memory chips of 16 ✖ 4 size have their address buses connected together. This system will be of size

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 29
Since all chips have the same address, so the capacity of word will be increased.

16 x 24 = 16 x 16

*Multiple options can be correct
GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 30

A 230 V, 50 Hz one pulse SCR converter is triggered at a firing angle of 400and the load current extinguishes at an angle of 2100. If R =5Ω, L = 2mH and E = 110V, Then which of the following statement(s) is/are correct.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 6 (30-01-23) - Question 30

Given:

One pulse SCR converter

α = 400

β = 2100

R = 5Ω

L = 2mH

E = 110 V

230 V, 50 Hz supply

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