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Test: Discrete Mathematics - 1 - Computer Science Engineering (CSE) MCQ


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10 Questions MCQ Test - Test: Discrete Mathematics - 1

Test: Discrete Mathematics - 1 for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Test: Discrete Mathematics - 1 questions and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus.The Test: Discrete Mathematics - 1 MCQs are made for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Discrete Mathematics - 1 below.
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Test: Discrete Mathematics - 1 - Question 1

Which of the following statement is a proposition?

Detailed Solution for Test: Discrete Mathematics - 1 - Question 1

Only this statement has got the truth value which is false.

Test: Discrete Mathematics - 1 - Question 2

Which of the following option is true?

Detailed Solution for Test: Discrete Mathematics - 1 - Question 2

Hypothesis is false, thus the whole statement is true.

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Test: Discrete Mathematics - 1 - Question 3

Let P: I am in Bangalore.; Q: I love cricket.; then q -> p(q implies p) is?

Detailed Solution for Test: Discrete Mathematics - 1 - Question 3

Q is hypothesis and P is conclusion. So the compound statement will be if hypothesis then conclusion.

Test: Discrete Mathematics - 1 - Question 4

Let P: I am in Delhi.; Q: Delhi is clean.; then q ^ p(q and p) is?

Detailed Solution for Test: Discrete Mathematics - 1 - Question 4

Connector should be ‘and’, that is q and p.

Test: Discrete Mathematics - 1 - Question 5

Let
P: We should be honest.,
Q: We should be dedicated.,
R: We should be overconfident.
Then
‘We should be honest or dedicated but not overconfident.’ is best represented by?

Detailed Solution for Test: Discrete Mathematics - 1 - Question 5

The third part of the statement is negated, hence negation operator is used, for (‘or’ –V) is used and for(’but’- ∧).

Test: Discrete Mathematics - 1 - Question 6

The compound propositions p and q are called logically equivalent if ________ is a tautology.

Detailed Solution for Test: Discrete Mathematics - 1 - Question 6

Definition of logical equivalence.

Test: Discrete Mathematics - 1 - Question 7

p ∨ q is logically equivalent to ________

Detailed Solution for Test: Discrete Mathematics - 1 - Question 7

(p ∨ q) ↔ (¬p → q) is tautology.

Test: Discrete Mathematics - 1 - Question 8

p ∧ q is logically equivalent to ________

Detailed Solution for Test: Discrete Mathematics - 1 - Question 8

(p ∧ q) ↔ (¬(p → ¬q)) is tautology.

Test: Discrete Mathematics - 1 - Question 9

p ↔ q is logically equivalent to ________

Detailed Solution for Test: Discrete Mathematics - 1 - Question 9

(p ↔ q) ↔ ((p → q) ∧ (q → p)) is tautology.

Test: Discrete Mathematics - 1 - Question 10

¬ (p ↔ q) is logically equivalent to

Detailed Solution for Test: Discrete Mathematics - 1 - Question 10

(¬ (p ↔ q)) ↔ (p ↔ ¬q) is tautology.

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