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Gate Mock Test Civil Engineering (CE)- 5 - Civil Engineering (CE) MCQ


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30 Questions MCQ Test - Gate Mock Test Civil Engineering (CE)- 5

Gate Mock Test Civil Engineering (CE)- 5 for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Gate Mock Test Civil Engineering (CE)- 5 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Gate Mock Test Civil Engineering (CE)- 5 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Gate Mock Test Civil Engineering (CE)- 5 below.
Solutions of Gate Mock Test Civil Engineering (CE)- 5 questions in English are available as part of our course for Civil Engineering (CE) & Gate Mock Test Civil Engineering (CE)- 5 solutions in Hindi for Civil Engineering (CE) course. Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free. Attempt Gate Mock Test Civil Engineering (CE)- 5 | 65 questions in 180 minutes | Mock test for Civil Engineering (CE) preparation | Free important questions MCQ to study for Civil Engineering (CE) Exam | Download free PDF with solutions
Gate Mock Test Civil Engineering (CE)- 5 - Question 1
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A rectangular sheet made of cardboard has a size of 4cm x 2cm. If a circle of greatest diameter is cut from it what is the area of the remaining portion of the rectangular sheet in cm2 ?

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 1
Area of rectangular sheet = 4 x 2 = 8cm2

Circle of Maximum diameter is obtained when circle has diameter of the rectangle width = 2 cm

Area of circle = (π x 22)/4 = π cm2

Remaining area = (8 - π) cm2

Gate Mock Test Civil Engineering (CE)- 5 - Question 2
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Select the suitable figure from the answer figures that would replace the question mark (?).

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 2
As, second figure is mirror image of first one horizontally.

Similarly, figure given in answer figure (1) is the mirror image of third figure horizontally.

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Gate Mock Test Civil Engineering (CE)- 5 - Question 3
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Select the word or phrase which is close to the OPPOSITE in the meaning of the bold word or phrase.

The habit of squandering money should not be encouraged.

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 3
Squandering is opposite in meaning to saving
Gate Mock Test Civil Engineering (CE)- 5 - Question 4
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Directions: Fill in the blank with the most suitable option.

He is such a miser that he can never part ___________ his money.
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 4
'Part with' is a phrasal verb, which means 'to give up or let go of'. It fits in context of a 'miser' who does not give up his money.
Gate Mock Test Civil Engineering (CE)- 5 - Question 5
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There are Six friends Arya, Janvi, Pratik, Tirtha, Saloni and Divya, with distinct heights, compare their heights and make the following observations.

Observation I: Pratik is taller than Tirtha.

Observation II: Janvi is the shortest of all.

Observation III: Divya is taller than only one person.

Observation IV: Saloni is taller than Pratik but she is not the tallest

The number of persons that are taller than Tirtha is the same as the number of persons shorter than_________
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 5
Arya>Saloni>Pratik>Tirtha>Divya>Janvi
Gate Mock Test Civil Engineering (CE)- 5 - Question 6
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In a certain code, BUILDER is written as JVCKSFE. How is SEALING written in that code?
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 6

Gate Mock Test Civil Engineering (CE)- 5 - Question 7
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Nikhil aspires to buy a bike worth Rs. 200000 after 7 years. what is the minimum amount in Rupees that he should deposit now in a bank which offers 5.5% annual rate of interest, if the interest was compounded annually ?
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 7
CI = P(1 + r/100)n

200000 = P(1 + 5.5/100)7

P = 137487

Gate Mock Test Civil Engineering (CE)- 5 - Question 8
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Directions: Study the given graph carefully and answer the following question.

The graph below shows the numbers of students appearing for and qualifying in a scholarship exam from various schools:

Q. What is the difference between the average number of students appearing and qualifying in the exam from all the given schools?
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 8
Average number of students appearing for the exam from all the given schools,

= (3000 + 2250 + 3250 + 2500 + 3000)/5 = 2800

The average number of students qualifying in the exam from all the given schools,

= (1750 + 1250 + 2250 + 2000 + 2000)/5 = 1850

Difference = 2800 – 1850 = 950

Gate Mock Test Civil Engineering (CE)- 5 - Question 9
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Statements:

1. All boys are genius.

2. All girls are boys.

Conclusions:

I. All girls are genius.

II. Some boys are girls

Based on the above statements and conclusions, which one of the following options is logically CORRECT?
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 9

from the above imaginary diagram we can conclude that both conclusion I and II are follows

Gate Mock Test Civil Engineering (CE)- 5 - Question 10
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In the sequence of the terms AD CG FK JP, the next term is
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 10
Observe the first letters: A, C, F, J; the difference between each consecutive letter is incrementing by one letter. Or if we number the letters, the sequence is 1, 3, 6, 10 and the difference of the consecutive numbers in order is 2, 3, 4. Hence, the next difference is 5 and so the next number is 10 + 5 = 15, i.e. letter 'O'.

Observe the second letters: D, G, K, P; if we number these letters, they are 4, 7, 11, 16 and the difference of the consecutive numbers in order is 3, 4, 5. Hence, the next difference is 6 and so the next number is 16 + 6 = 22, i.e. letter 'V'.

Hence, the next term is 'OV'.

Gate Mock Test Civil Engineering (CE)- 5 - Question 11
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Zero hardness of water is achieved by
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 11
Zero hardness, other than ion exchange or base exchange or zeolite method, leaves behind a substantial amount of hardness or alkalinity. Zero hardness of water can be achieved only by means of zeolite process.
Gate Mock Test Civil Engineering (CE)- 5 - Question 12
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The value of is
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 12

Gate Mock Test Civil Engineering (CE)- 5 - Question 13
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There is a free overfall at the end of a long open channel. For a given flow rate, the critical depth is less than the normal depth. What gradually varied flow profile will occur in the channel for this flow rate?
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 13

Here, yn > yc . So, the mild sloped channel.

For free flow at the end of long channel on the mild sloped surface. There will be draw down and depth of flow decreases from yn tp yc but not below the yc . So, appropriate answer will be M2 only.

Gate Mock Test Civil Engineering (CE)- 5 - Question 14
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The solution at x = 1, t = 1 of the partial differential equation subject to initial conditions of u(0) = 3x and = 3 is ____________.
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 14
By D Alembert's formula

Solution to IVP for wave equation

utt = C2Uxx

u(x, 0) = f(x)

ut (x, 0) = g(x)

Given: f(x) = 3x

g(x) = 3 & c2 = 1/25

= 3x + 3t

At x = 1, t = 1; u(x, t) = 6

Gate Mock Test Civil Engineering (CE)- 5 - Question 15
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Match the following:
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 15
Rainfall intensity versus time is provided by a hydrograph.

Rainfall excess: Provides the direct run-off hydrograph over the infiltration index.

Rainfall average: Isohyets provide the time on the map having equal rainfall depth and used to measure the average rainfall across a particular area.

Mass curve is a mass curve of inflow or mass curve is a plot of accumulated flow in a stream against time. Cumulative rainfall is denoted by mass curve.

Gate Mock Test Civil Engineering (CE)- 5 - Question 16
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The slenderness ratio of a column is zero when its length is
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 16
Slenderness ratio means the ratio of the length of a column to the least radius of gyration of its cross-section. It is denoted by λ.

The slenderness ratio of a column is zero when its length is between the points of zero moments.

Gate Mock Test Civil Engineering (CE)- 5 - Question 17
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For a saturated sand deposit, the void ratio and the specific gravity of solids are 0.70 and 2.67, respectively. The critical (upward) hydraulic gradient for the deposit would be
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 17

e = 0.70, G = 2.67

Critical hydraulic gradient causes effective stress to zero and

Gate Mock Test Civil Engineering (CE)- 5 - Question 18
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For concreting of shallow sections with vibrations, the workability should be ______.
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 18

For concreting of shallow sections with vibrations, the workability should be very low.

Gate Mock Test Civil Engineering (CE)- 5 - Question 19
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To provide safety against piping failure, with a factor of safety of 5, what should be the maximum permissible exit gradient for soil with a specific gravity of 2.5 and porosity of 0.35?
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 19
Exit gradient = seepage pressure per unit volume

Critical ic = when n = 0.35

= (G - 1)(1 - n)

= (2.5 - 1)(1 - 0.35) = 0.975

Maximum possible exit gradient with factor of safety

of 5 = 0.975/5 = 0.195

Gate Mock Test Civil Engineering (CE)- 5 - Question 20
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The solution of the equation xdy/dx+ y = 0 passing through the point (1, 1) is
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 20

= loge (c/x)

⇒ y = c/x

(1, 1) ⇒ c = 1

∴ y = 1/x = x-1

Gate Mock Test Civil Engineering (CE)- 5 - Question 21
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A stable channel is to be designed for a discharge of Q m3/s with silt factor f as per Lacey's method. The mean flow velocity (m/s) in the channel is obtained by
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 21
According to Lacey’s, the design formulas to build a canal is as follows:
  1. Silt factor ⇒ f = size of particle(mm)
  2. Velocity of flow ⇒
  3. Hydraulic mean depth ⇒
  4. Wetted perimeter ⇒
  5. Bed slope ⇒

Hence, the correct relationship between the parameter given in the option as per Lacey’s silt theory is the velocity of flow,

Gate Mock Test Civil Engineering (CE)- 5 - Question 22
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In the formula a + bk used in the calculation of the net effective section of single angles in tension connected by one leg only, the value of k is
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 22
In the calculation of the net effective section of single angles in tension connected by one leg only, the formula used is a + bk, in which the value of k is .
Gate Mock Test Civil Engineering (CE)- 5 - Question 23
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From among the following sewage treatment options, largest land requirements for a given discharge will be needed for
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 23
Oxidation pond - Standing pond with minimum depth, so the sunlight can penetrate into the tank for photosynthesis at the bottom of the tank and provide oxygen for aerobic oxidation. For less depth, more surface area and large detention time is required.
Gate Mock Test Civil Engineering (CE)- 5 - Question 24
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Neglecting gravitational effects, for steady, fully developed flow inside a straight pipe of diameter 2.24 m, the pressure drop is 80 kPa. If the wall shear stress τw is 250 N/m2, then the length of the pipe will be _____________ m.
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 24
Wall shear stress is

Gate Mock Test Civil Engineering (CE)- 5 - Question 25
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The presence of hardness in excess of permissible limit causes
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 25
Hardness of water means the presence of carbonate and bicarbonate of Ca and Mg in water as such does not cause any health related problem, but on precipitation when reacting with fatty acid (soap) and scale formation in boiler. So, hardness will increase the expenses on laundry materials like soap and shampoo, etc.
Gate Mock Test Civil Engineering (CE)- 5 - Question 26
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The queue length (in number of vehicles) versus time (in seconds) plot for an approach to a signalized intersection with the cycle length of 96 seconds is shown in the figure (not drawn to scale).

At time t = 0, the light has just turned red. The effective green time is 36 seconds, during which vehicles discharge at the saturation flow rate, s (in vph). Vehicles arrive at a uniform rate, v (in vph), throughout the cycle. Which one of the following statements is TRUE?
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 26
Vehicle arrived up to 60 sec (Red time) = 10

Arrival rate = 1060 × 3600 = 600 V/hV = 600 V/h

Departure at vehicle starts at 60 seconds and ends at 90 seconds.

So, between 60 second to 90 second

Total vehicle departed = Vehicle arrived up to 60 sec + Vehicle arriving between 60 sec and 90 sec = 10 + 600/3600 × 30 = 10 + 5 = 15

So, departure rate = saturation flow = S = 1530 × 3600

S = 1800 vph

Average delay time is given by: td = (C/2(1 − gc)2)/(1 − V/S)C = 96 seconds

g = 96 - 60 = 36 seconds

V = 600 vph

S = 1800 vph

td = 96/2(1 − 36/96)21 − 600/1800

td = 28.125 seconds

Gate Mock Test Civil Engineering (CE)- 5 - Question 27
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The shape of the cross section which has the largest shape factor is
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 27
Largest shape factor also depends upon lowest value of section modulus and diamond section of equal area will have least section modulus (Z). Hence, diamond has shape factor as 2, whereas circle has 1.7, Rectangle-1.3.
*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 5 - Question 28
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If the sleeper density for a B.G. track is n + 5 and the length of one rail is 12.8 m, then number of sleepers required per km length of the track is (Answer up to the nearest integer)

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 28

Length of one rail is 12.8 m ≈ 13 m

Sleeper density is n + 5 = 13 + 5 = 18

Number of sleepers required is

Gate Mock Test Civil Engineering (CE)- 5 - Question 29
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If xSin (a + y) = Sin y, then dy/dx is equal to
Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 29

Differentiating w.r.t. y, we have.

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 5 - Question 30
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The extra widening required in a 6 lane carriage when the length of the vehicle is 10 m, radius of curve is 450 m and speed is 72 kmph is ________ m. (Answer up to three decimal places)

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 5 - Question 30
Given: n = 6, l = 10 m, R = 450 m and V = 72 km/h

Extra widening is given by

= 1.006 m

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