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Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  GATE Mock Test: Electrical Engineering (EE)- 4 - Electrical Engineering (EE) MCQ

GATE Mock Test: Electrical Engineering (EE)- 4 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test - GATE Mock Test: Electrical Engineering (EE)- 4

GATE Mock Test: Electrical Engineering (EE)- 4 for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The GATE Mock Test: Electrical Engineering (EE)- 4 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The GATE Mock Test: Electrical Engineering (EE)- 4 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for GATE Mock Test: Electrical Engineering (EE)- 4 below.
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GATE Mock Test: Electrical Engineering (EE)- 4 - Question 1
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Which of the following is the antonym of the word SILENCE?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 1
Silence refers to 'no speech'. Babble means continuous, and sometimes incoherent speech.
GATE Mock Test: Electrical Engineering (EE)- 4 - Question 2
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Let x < 0, 0 < y < 1, z > 1. Which of the following statement is false?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 2
Let us evaluate each option(b)Since0< /><1 and="" z="">1, yz can be < />

(c)Since both x and y are not equal to 0, xy will never be 0

(d)y is a positive number < 1="" and="" z="" is="" a="" positive="" number="" /> 1, hence (y2-z2) is always negative.

Now, x2 - z2 = (x-z)(x+z).(x-z) will be always negative but x+z can be negative or positive, depending upon the actual values of x and z.

So, option (A) is not true. Clearly the statement will be false for the case .

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GATE Mock Test: Electrical Engineering (EE)- 4 - Question 3
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Which of the following is the synonym of the word ADMONISH?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 3
Admonish means taking someone to task for wrong doing. This is similar to warning or cautioning someone for some wrong doing.
GATE Mock Test: Electrical Engineering (EE)- 4 - Question 4
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A dishonest dealer claims to sell a product at its cost price. He uses a counterfeit weight which is 20% less that the real weight. Further greed overtook him, and he added 20% impurities to the product. Find the net profit percentage to the dealer.
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 4

Now, due to false weight = Actual quantity = 100 × 80% = 80kg

Now, due to inpurity, Actual quantity = 80 × 4/5 = 64 kg

Now selling price = Rs. 100

And, cost price of 64 kg = Rs. 64

Hence, profit = 100 - 64 = Rs. 36

∴ Profit percentage = 36/64 × 100 = 56.25%

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 5
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Which of the following numbers indicates unmarried doctors who are not professors?
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 5
The required number should be present outside the square and circle, but present inside the triangle.
GATE Mock Test: Electrical Engineering (EE)- 4 - Question 6
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In a group, there are 32 people. All of them know at least one of the three languages : Hindi, English and Marathi. 25 people know Hindi, 20 know English and 15 know Marathi. 15 people know Hindi and English. 5 people know English and Marathi. If 3 people know all the three languages, then how many people know Hindi and Marathi?
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 6

People speaking at least one of three languages = 32

We must have:

32 = 25 + 20 + 15 – (15 + 5 + x) + 3

32 = 43 – x

x = 11

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 7
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is equal to
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 7
Remember that you can only add fractions with the same denominator.

Rearrange so that it can be added to . That is, try and turn into a fraction with 39 in the denominator.

Multiply by 3/3 to get

Solving,

Canceling out a factor of 3 gives,

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 8
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The number of triangles that can be formed by joining the vertices of a heptagon is
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 8
In a heptagon there are 7 vertices. Out of these we can make a triangle by selecting any 3 points.

Number of triangles that can be formed =

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 9
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What will be the sum of the factors of 3129?
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 9
N is a number such that N = ap bq cr ... where a, b, c are prime number and p, q, r are positive integers.

So, sum =

Here a = 3, p = 129,

So required sum =

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 10
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Read the argument given below and then answer the questions which follow the argument.

Canada’s commercial seal “hunt” is the largest mass slaughter of marine mammals in the world. This year, Canada will allow 270,000 harp seals to be killed. Canada’s 2006 quota for killing seals: 325,000 for the regular commercial “hunt” and an additional 10,000 harp seal allowance for new aboriginal initiatives, personal use, and Arctic hunts. As usual, the commercial quota was exceeded, resulting in over 330,000 seals being killed. During the previous three years, the government of Canada delivered the death sentence to over one million baby harp seals.

The above statement assumes that
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 10
Option (a) is irrelevant to the argument as it assumes too much. Option (c) is very generic and the passage doesn’t directly comment on the cruelty done to seals. Hence option (c) can be eliminated. Option (d) is abstract ideas and cannot be assumptions. The reality that large scales of slaughter of seals are being undertaken in Canada every year points to the fact that it was commercially viable for the Canadians to carry out this activity. This leads us to option (b), making it the correct answer.
*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 4 - Question 11
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A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 4 - Question 12
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The nominal π -circuit of a 220 kV,three phase transmission line is shown in the figure below

If Z=50Ω and X=1600Ω, then surge impedance loading of the line is _____ MW.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 12

Surge impedance loading

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 4 - Question 13
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In the following circuit, the value of vs that will result in v1 = 0 is ____ V. (Key in the absolute value)

(Answer up to the nearest integer)

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 13
If v1 = 0, the dependent source is a short circuit

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 4 - Question 14
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To extend the range of PMMC type ammeter a resistance of 500mΩ is connected in shunt with the meter, internal resistance of meter being 9.5Ω . The original full scale deflection of meter is 5A. After connecting shunt resistor,the new full scale deflection is ______ A.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 14
Given

Rsh = 500mΩ = 0.5Ω

Rm = 9.5Ω

Meter full scale deflection, Im = 5 A

For PMMC ammeter, (where m= Multiplication factor)

∴ m = 20

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 15
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For the waveform shown in the figure, the equation is
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 15
At t = − 1, the slope of function changes from 0 to 3 for a change in slope of 3.

At t = 0, the slope of function changes from 3 to - 3 for a change in slope of – 6

At t = 1, the slope of function changes from - 3 to 0, for a change in slope of 0

Hence, the equation for x(t) is

x(t) = 3(t + 1)u(t + 1) − 6tu(t) + 3(t − 1)u(t − 1)

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 16
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A boost converter is operated from a source voltage 100 V. The load resistance is 200Ω . The internal resistance of inductor is 0.8Ω then the average output voltage is ________ V (D=0.4 )
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 16
Given

Vdc = 100 V

r = 0.8 Ω

R = 200 Ω

D = 0.4

Output voltage of boost converter with internal resistance,

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 17
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A discrete time signal x[n] is shown below:

The signal is
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 17

Similarly we can plot v[n].

*Multiple options can be correct
GATE Mock Test: Electrical Engineering (EE)- 4 - Question 18
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Matrix [A]nxm is a skew symmetric matrix then, which of the following statements is/are correct ?
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 18

If a matrix [A]nxm is a skew-symmetric matrix then,

1. A2n is a symmetric matrix

2. A2n+1 is a skew – symmetric matrix

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 19
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Wave winding is employed in a DC machine of
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 19
Wave windings are high-voltage rated, since the number of coils in series between commutator segments permits a high voltage to be built up more easily than with lap windings. Current rating of wave winding is taken low.
GATE Mock Test: Electrical Engineering (EE)- 4 - Question 20
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The value of integral where C is the square cut from the first quadrant by line x=2 and y=1 will be
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 20
Given

Integral I, is the form of , by greens theorems,

From the graph, x = 0 to 2 and y = 0 to 1

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 21
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In the single phase voltage controller circuit shown in the figure, for what range of triggering angle (α) is the output voltage (v0) not controllable?
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 21

Uncontrollable output voltage is obtained when firing angle of the above circuit satisfies the condition shown below:

where α = Firing angle.

= Circuit phase angle.

Range of firing angle α for uncontrollable output voltage is 0° ≤ α ≤ 45°.

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 22
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Consider the two port network shown in figure below,

The transmission parameter matrix is,
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 22
Given circuit is shown below

For network 1, that is T-network

The Z-parameter matrix is,

Similarly for network 2, that the Z-parameters matrix is [Z2]

From the relationship between Z-parameters and T-parameters,

For the cascade connection, the overall T-parameters is the product of T-parameters of the individual networks,

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 23
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It is desired to measure the parameters of 230V/115V, 2kVA, single phase transformer. The following wattmeters are available in a laboratory.

W1: 250 V, 10 A, Low Power Factor

W2: 250 V, 5 A, Low Power Factor

W3: 150 V, 10 A, High Power Factor

W4: 150 V, 5 A, High Power Factor

The wattmeters used in open circuit test and short circuit test of the transformer will respectively be
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 23

The current is of 4 to 8% of full load current ≌ 1.4 A, and is of low power factor ≌ 0.2.

∴ W2 is required.

For short circuit test [on HV side],

The current is full load current ≌ 8.7 A.

The power factor is high ≌ 0.5 to 0.6.

∴ W3 is required.

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 24
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Consider circuit shown in below figure,

Here, R’ is used as feedback resistance, the input impedance of the circuit after feedback compared to without feedback
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 24
Consider circuit shown below

Output and feedback taken from different points so sampling is of current type. At input side the mixing is happening in shunt type. So it is current – shunt type of feedback topology. Input impedance with feedback,

Input Impedance decreases.

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 25
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In an oscilloscope, two Lissajous figures (X) and (Y) are observed. The ratios of vertical input signal frequency to that of horizontal input frequency for X and Y are
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 25

We can obtain the frequency ratio as following

fy/fx = 6/4 = 3/2

fy/fx = 3/2

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 26
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Substation is supplying a load which consumes a complex power of 50+j50 MVA. A reactive power controlled capacitor bank is connected across load with a range of 0≤QC≤40MVAr . This QC controller adopts step wise control with each step of 5 MVAr. To improve overall power factor close to 0.9 lag, the number of steps connected will be________. (by considering step number ‘0’ for Qc = 0MVAr )
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 26

Given

Complex power = 50 + j50MVA

Assume that C-bank injecting Qc amount of reactive power.

Let number of steps = n

So, Qc = 5nMVAr )

Now real and reactive power supplied by source Ps = 50MW

Qs = Q1-Qc = 50 - 5n

Overall power factor,

It is given that

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 4 - Question 27
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A 500 kVA, 3-phase transformer has iron losses of 300 W and full load copper losses of 600 W. The percentage load at which the transformer is expected to have maximum efficiency is (Answer up to one decimal place)

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 27
Given that transformer rating is 500 kVA,

Iron losses = 300 W

Full load copper losses = 600 W

Maximum efficiency condition is

Wi = X2Wc

So,

= √1/2

Efficiency % = 0.707 x 100 = 70.7%

GATE Mock Test: Electrical Engineering (EE)- 4 - Question 28
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Consider the following Boolean function with four variables f(w,x,y,z) = Σ(1,3,4,6,9,11,12,14).

The function is :
Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 28
Given

4-variable function is,

f(w,x,y,z) = Σm(1,3,4,6,9,11,12,14).

Solving above function using K-map in SOP form as,

The minimized function of above K-map is,

So,F depends upon only 2-variables x and z and independent of other 2-variables w and y .

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 4 - Question 29
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A 240 V, dc shunt motor draws 15 A while supplying the rated load at a speed of 80 rad/s. The armature resistance is 0.5 and the field winding resistance is 80 . The external resistance to be added in the armature circuit to limit the armature current to 125% of its rated value is (Answer up to one decimal place)

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 29

Or, -234 = 240-15(R + 0.5)

∴ R = 31.1Ω

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 4 - Question 30
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In a power network, the supply voltage is Vㄥδ and receiving end voltage is Vㄥ00 . If the impedance of transmission line is , then for maximum power transfer the value of X should be

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 - Question 30
Given

Supply voltage = Vㄥδ

Receiving end voltage = Vㄥ00

Impedance of transmission line =

For maximum power transfer Ө = δ

X = 3Ω

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