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GATE Mock Test Mechanical Engineering (ME) - 3 - Mechanical Engineering MCQ


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30 Questions MCQ Test - GATE Mock Test Mechanical Engineering (ME) - 3

GATE Mock Test Mechanical Engineering (ME) - 3 for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The GATE Mock Test Mechanical Engineering (ME) - 3 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The GATE Mock Test Mechanical Engineering (ME) - 3 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for GATE Mock Test Mechanical Engineering (ME) - 3 below.
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GATE Mock Test Mechanical Engineering (ME) - 3 - Question 1

Find the wrong number in the series 7, 28, 63, 124, 215, 342, 511

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 1
Clearly, the correct sequence is

(2)3 -1, (3)3-1, (4)3 -1, (5)3-1, (6)3-1, (7)3-1 (8)3-1

∴ 28 is wrong and should be replaced by (33-1) = 26

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 2

Directions: There are two sets of figures namely the problem figures, containing five figures 1, 2, 3, 4 and 5, and the answer figures (a), (b), (c) and (d). You have to select one figure from the answer figures which will continue the same series as given in the problem figures.

 

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 2

Circle and Pentagon is moving by 2 places and 3 places respectively in clockwise direction. Shaded shape is moving by 4 and 2 places respectively in alternate shapes. Also, the arrow is moving by 90° and 180° clockwise in alternate steps.

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GATE Mock Test Mechanical Engineering (ME) - 3 - Question 3

The question given below consists of a pair of related words followed by four pain of words. Select the pair that best expresses the relation in the original pair.

LEGEND : MAP ::

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 3
(THINGE AND PURPOSE) A legend (meaning an explanatory list of symbols used in a map) explains the symbols used in a map; a glossary explains the technical terms used in a text.
GATE Mock Test Mechanical Engineering (ME) - 3 - Question 4

In a certain code, BRAIN is written as *%÷#× and TIER is written as $#+%. How is RENT written in that code?

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 4

The code for RENT is %+×$.

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 5

The average score of a cricketer in three matches is 22 runs and in two other matches it is 17 runs. Find the average in all the five matches.

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 5
Total runs scored in 3 matches = 22 x3 = 66

next two matches runs =17 x2 = 34

now, total runs = 100

average of total five matches = 100/5 = 20

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 6

Directions: The table lists the size of building lots in the Orange Grove subdivision and the people who are planning to build on those lots. For each lot, installation of utilities costs $12,516. The city charges impact fees of $3,879 per lot. There are also development fees of 16.15 cents per square foot of land.

How much land does Mr. Taylor own in the Orange Grove subdivision?

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 6
Look at the chart to see all of the land he owns

The total amount of land he owns is, 8023 + 9004 + 8269 + 6774 = 32070 square feet.

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 7

From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee in how many ways can it be done?

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 7
We may have (3 men and 2 women) or (4men and 1 women) or (5 men only) Required number of ways

= (525 + 210 + 21) = 756

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 8

Directions: There are two sets of figures, namely the Problem Figures (1, 2, 3 and 4) and the Answer Figures (A, B, C and D). You have to select one figure from the Answer Figures which will continue the same pattern as established by the Problem Figures.

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 8

In each step, the line inside the circle rotates 45° anticlockwise, while the arrow individually rotates 90° clockwise and also moves one side in the clockwise direction. Hence, Answer Figure (B) continues the series.

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 9

Team sports like baseball display strong socialist tendencies in their requirements of individual subordination to the authority of coaches and managers.

Which of the following conclusions may not be inferred from the above information?

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 9

The sentence does not contain cue words which could help the reader identify premises and a conclusion. However, two sets of arguments may be identified

  • All team sports have socialist tendencies
  • Baseball is a team sport
  • Baseball has socialist tendencies

and

  • Individual subordination to authority is a form of socialism
  • All players in team sports are subordinate to their coaches
GATE Mock Test Mechanical Engineering (ME) - 3 - Question 10

Walking at of his usual speed, a man reaches his destination two minutes early. What is the time taken by him to cover the same distance at his usual speed?

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 10
The ratio of speeds before and after is 10 : 11. The ratio of time will be 11 : 10.

or,

He takes 1 unit less time now which is given as 2 minutes. The time taken will be 22 minutes at his usual speed.

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 11

Which among the following non-traditional machining process has the lowest specific power requirement?

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 11
  • EDM has the lowest specific power requirement and can achieve sufficient accuracy
  • ECM has the highest metal removal rate
  • USM and AJM have low MRR and combined with high tool wear, are used for non-metal cutting
  • LBM and EBM have high penetration rates with low MRR and therefore, are commonly used for micro-drilling and sheet cutting.
GATE Mock Test Mechanical Engineering (ME) - 3 - Question 12

Coriolis component acceleration exists whenever a point moves along a path that has:

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 12
The total acceleration of a point with respect to another point in a rigid link is the vector sum of its normal (radial) and tangential components. This holds true when two bodies are in rolling contact, the point in one body that contacts the other body is instantaneously at rest relative to that body.

It implies velocity relative to that body is zero. If the point is no longer at rest relative to it, but rotates or slides, the total acceleration will contain one additional component called the Coriolis acceleration component.

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 13

Mild steel fails in a pronounced cup-cone fracture. If the percentage of carbon in steel is increased

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 13
As percentage of carbon increases, the depth of cup becomes shallower until for high carbon steel it may completely disappear.
GATE Mock Test Mechanical Engineering (ME) - 3 - Question 14

Match List - I (Properties of fluids) with List - II (Definition/Result) and select the correct answer using the codes given below:

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 14

*Multiple options can be correct
GATE Mock Test Mechanical Engineering (ME) - 3 - Question 15

What is/are the main conditions to perform optimality test?

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 15

For performing optimality test initial solution must be non-degenerate. For non-degenerate solution, total number of allocations must be exactly equal to (m + n - 1) and all of these allocations must be at independent positions.

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 16

Consider two metal plates pressed against each other. Other things being equal, which of the measures below will cause the thermal contact resistance to increase?

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 16
When two metal plates are pressed against each other, the peaks form good material contact but the valleys form voids filled with air in most cases. As a result, an interface contains numerous air gaps of varying sizes that act as insulation because of the low thermal conductivity of air. Thus, an interface offers some resistance to heat transfer and this resistance for a unit interface area is called the thermal contact resistance. This resistance is observed to increase with increase in contact area by cleaning the surfaces to make them shinier.
GATE Mock Test Mechanical Engineering (ME) - 3 - Question 17

A flywheel has mean kinetic energy of rotation equal to 100 Nm. If coefficient of fluctuation of speed is 0.012, the maximum fluctuation of energy in flywheel is

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 17
Maximum fluctuation of energy in flywheel,

= Iω2 x CS

E = 1/2 Iω2

ΔE = 2E x CS

= 2 x 100 x 0.012

= 2.4 Nm

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 18

The singularity of esinz at z = ∞ is

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 18
Since, |sin z| ≤ 1, the only singularity of esin z is at z = ∞. Thus, it is isolated essential singularity.
GATE Mock Test Mechanical Engineering (ME) - 3 - Question 19

A hollow sphere has inner and outer surface areas of 2 m2 and 8 m2 respectively for a given temperature difference and heat flow across the surface. Considering the material of the sphere as a plane wall of the same thickness, the equivalent mean area normal to the direction of heat flow is

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 19
Mean area for the sphere is geometric mean of inside and outside area.

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 20

Which of the following statements are correct?

  1. Steel and cast iron are multiphase alloys.

  2. Ferrite is a single phase interstitial solid solution of carbon in iron.

  3. Wrought iron is a highly refined iron with a small amount of slag which gives resistance to progressive corrosion.

  4. Satellite contains large amounts of metals like cobalt and tungsten resulting in high hardness.

Select the correct answer using the codes that follow.

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 20
  • Steel and cast iron may contain ferrite and cementite; hence, they are multiphase alloys.

  • Ferrite is a single phase material which contains carbon at the interstitial site of iron atom, thus forming interstitial solid solution.

  • Wrought iron is a highly refined iron with uniformly distributed quantity of slag. The non-corrosive slag constituents causes wrought iron to be resistance to progressive corrosion.

  • The presence of slag produces a structure which diminishes the effect of fatigue caused by shock and vibration.

Co-based cast alloy is of trade name "Stellite".

It typically has the following composition:

Co: (38 – 52%)

Cr: (30 – 32%)

W: (10 – 12%)

C: (2%)

Its structure is composed of Co-matrix, in which W-Cr carbides are embedded with volume ratio of 25–30%. It has high hardness in the range of 58–64 HRC.

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 21

Which of the following method is sensitive to starting value, when solving an algebraic equation?

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 21
Newton-Raphson method is sensitive to the starting value. If the initial guess is not sufficiently close to the root, then the method may not converge to the root.
GATE Mock Test Mechanical Engineering (ME) - 3 - Question 22

A gating ratio of 1 : 2 : 5 is used to design the gating system for aluminium alloy casting.

The gating ratio 1 : 2 : 5 represents:

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 22
Gating Ratio is defined as the ratio of sprue base area, followed by the total runner area and the total ingate area. The sprue base area is taken as unity.

So, 1 : 2 : 5 = Sprue base area : Runner area : Total ingate area.

*Answer can only contain numeric values
GATE Mock Test Mechanical Engineering (ME) - 3 - Question 23

If a random variable follows Poisson distribution with mean 3, then V(2X + 5) = _________.


Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 23
Given mean = 3

⇒ Variance = 3 (∵ X follows Poisson distribution)

∴ V(2X + 5) = 4V (X)

= 4 x 3 =12

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 24

The clearance in blanking operation is provided

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 24
Blanking is the operation of cutting a flat shape from a sheet metal. In blanking, the slug is the part and rest is scrap. In blanking operation, the die size is taken as the blank size and the punch is made smaller giving the necessary clearance between the die and the punch.

Die size = blank size

Punch size = blank size – 2 x clearance

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 25

A plane cantilever truss is loaded a shown in the figure. If a positive sign denotes tension and a negative sign denotes compression, the axial force in the member 1 is

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 25

ΣMA = R1 x 12 - P x 4 - P x 8 - P x 12 = 0

∴ = 2P

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 26

Consider the figure as shown. Which of the following are the required shear force and bending-moment diagrams for the beam and loading?

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 26
First calculate the reactions at A and B

- 0.72RA + (0.48) (120) + (0.24) (120) - 2 (120) (0.06) = 0

– (0.24) (120) – (0.48) (120) – 2 (120) (0.06) + 0.72RB = 0

RB = 140 N

Shear:

A to C, V = 100 N

C to D, V = 100 – 120 = – 20 N

D to B, V = – 20 – 120 = – 140 N

Areas under shear diagram:

Bending moments:

*Answer can only contain numeric values
GATE Mock Test Mechanical Engineering (ME) - 3 - Question 27

A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)


Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 27
Given data: d = 500 mm, P = 5 N/mm2

Syt = 400 N/mm2 , FOS = 4

∴ Allowable stress = = Syt/FOS = 400/4 = 100 N/mm2

For minimum thickness,

Pd/2tη = 100 N/mm2

GATE Mock Test Mechanical Engineering (ME) - 3 - Question 28

Match List - I with List - II and select the correct answer using the codes given below the lists:

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 28

*Multiple options can be correct
GATE Mock Test Mechanical Engineering (ME) - 3 - Question 29

The CORRECT statement about buoyancy force is

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 29

All the statements given above about buoyancy are correct.

*Answer can only contain numeric values
GATE Mock Test Mechanical Engineering (ME) - 3 - Question 30

A circular beam is subjected to a shear force of 10 kN. Calculate the value of maximum shear stress in N/mm2. [Take area = 176 cm2]. (Answer up to two decimal places)


Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 3 - Question 30
Given Area (A) = 176 cm2 = 17600 mm2

Shear Force (F) = 10 kN = 10000 N

For circular cross section, the maximum shear stress is equal to 4/3 times of average shear stress.

Maximum shear force = (4/3) × (F/A) = (4/3) × (10000/17600) = 0.76 N/mm2

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