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Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test - Test: GATE Electrical Engineering (EE) Previous Paper 2021

Test: GATE Electrical Engineering (EE) Previous Paper 2021 for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: GATE Electrical Engineering (EE) Previous Paper 2021 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: GATE Electrical Engineering (EE) Previous Paper 2021 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: GATE Electrical Engineering (EE) Previous Paper 2021 below.
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Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 1

Seven cars P, Q, R, S, T, U and V are parked in a row not necessarily in that order. The cars T and U should be parked next to each other. The cars S and V also should be parked next to each other, whereas P and Q cannot be parked next to each other. Q and S must be parked next to each other. R is parked to the immediate right of V. T is parked to the left of U.
Based on the above statements, the only INCORRECT option given below is:

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 1

S and V must be parked together and Q and S also must be parked together. These two condition possiible parkings are: Q S V ----------
V S Q ----------
We can observe that in all cases only one car can be parked in between Q and V which is car S.
Hence option (a) is incorrect.

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 2

In the figure shown above, each inside square is formed by joining the midpoints of the sides of the next larger square. The area of the smallest square (Shaded) as shown, in cm2 is

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 2

Side of outer first square = 10 cm
Side of outer second square = 

like wise

Side of outer third square = 

Hence,

side of smallest square = 

Area of smallest square = = 3.125

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Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 3

Which one of the following numbers is exactly divisible by (1113 + 1)?

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 3

Consider expression 

Now assuming similar expression 1152 - 1 = (1113)4 - (1)4

Hence, 1152 - 1 is divisible by 1113 + 1.

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 4

The people________were at the demonstration were from all section of society.

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 4

We cannot use ‘which' for people, ‘who’ is the only word which acts as a subject for the verb.

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 5

Let X be a continuous random variable denoting the temperature measured. The range of temperature is (0, 100) degree Celsius and let the probability density function of X be f{x) = 0.01 for 0 < X < 100. The mean of X i s _______ .

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 5

n is a continuous random variable for continuous random variable

From here,                      α = 0, β = 100

For continuous probability function mean

Alternate Solution:

Given:                  

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 6

For a regular polygon having 10 sides, the interior angle between the sides of the polygon, in degrees, is :

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 6

Sum of the interior angle = (n - 2) x 180 = 1440

The interior angle between two sides of polygon is 1440/10 = 144.

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 7

A transparent square sheet above is folded along the dotted line. The folded sheet will look l i k e ______ .

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 7

Upon rotation, we get the below figure.

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 8

The importance of sleep is often overlooked by students when they are preparing for exams. Research has consistently shown that sleep deprivation greatly reduces the ability to recall the material learn. Hence, cutting down on sleep to study longer hours can be counterproductive.
Which one of the following statements is the CORRECT inference from the above passage?

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 8

First statement is ridiculous, third and fourth are contradictory to what is given in the passage.

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 9

Oasis is to sand as island is t o ______ .
Which one of the following options maintains a similar logical relation in the above sentence?

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 9

Oasis is surrounded by sand as Island is surrounded by water.

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 10

The number of students passing or failing in an exam for a particular subject is presented in the bar chart above. Students who pass the exam cannot appear for the exam again. Students who fail the exam in the first attempt must appear for the exam in the following year. Students always pass the exam in their second attempt.
The number of students who took the exam for the first time in the year 2 and the year 3 respectively, are _______ .

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 10

Total number of student in the year-2

                                         = 60 + 5 = 65
Students who failed in the year and appeared in year-2 = 10

So the students who appeared first time in year-2 = 65 - 10 = 55

Similarly, Total number of students in year-3 = 53

Students who failed in the year-2 and appeared in year-3 = 5

So, the students who appeared first time in year-3

= 53 - 5 = 48

*Answer can only contain numeric values
Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 11

An alternator with internal voltage of 1∠δ1p.u. and synchronous reactance of 0.4 p.u. is connected by a transmission line of reactance 0.1 p.u. to a synchronous motor having synchronous reactance 0.35 p.u. and internal voltage of 0.85∠δ2 p.u. If the real power supplied by the alternator is 0.866 p.u, then (δ1 - δ2) is _____degrees. (ound off to 2 decimal places) (Machines are of non-salient type. Neglect resistances)


Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 11

 

Given real power in (p.u.), P = 0.866

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 12

Lef f[t) be an even function, i.e. f(-t) = f{t) for all t. Let the Fourier transform of f{t) be defined as = 1. Then

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 12

The following informations are given about f(t) 

By solving the above linear differential equations, (by mathematics)

*Answer can only contain numeric values
Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 13

Suppose the circle x2 + y2 = 1 and (x - 1 )2 + ( y - 1 )2 = r2 intersect each other orthogonally at the point (tv, v ). Then tv + tv = ______ .


Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 13

If two curves cut orthogonally then product of slopes = -1 

*Answer can only contain numeric values
Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 14

A 1 pC point charge is held at the origin of a Cartesian coordinate system. If a second point charge of 10 pC is moved from (0, 10, 0) to (5, 5, 5) and subsequently to (5, 0, 0), then the total work done i s ______ mJ. (Round off to 2 decimal places.) Take = 9 x 109 in SI units. All coordinates are in meters.


Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 14

In this case work done is independent of type of path but depends an intial and final point.

Work done (by external source) in moving O-charge (10 pC) in the presence of electric field E is

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 15

Consider a power system consisting of N number of buses. Buses in this power system are categorized into slack bus, PVbuses and PQ buses for load flow study. The number of PQ buses is NL. The balanced Newton-Raphson method is used to carry out load flow study in polar form. H, S, M, and R are sub-matrices of the Jacobian matrix J as shown below:

The dimensions of the sub-matrix is

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 15

For size of M

Row = No. of unknown variables of O = NL

Column = No. of variable which has δ = NL + (N - 1 - NL)

= N - 1
So,      size of M = NL x (N - 1)

*Answer can only contain numeric values
Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 16

The waveform shown in solid line is obtained by clipping a full-wave rectified sinusoid (shown dashed). The ratio of the RMS value of the full-wave rectified waveform to the RMS value of the clipped waveform i s _____ . (Round off to 2 decimal places.)


Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 16

We know,
RMS value of full wave rectified sine wave = 

 For clipped wave form

 wave form are identical

rms value of clipped wave = 

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 17

In the circuit, switch 'S' is in the closed position for a very long time. If the switch is opened at time t = 0, then iL(t) in amperes, for t > 0 is

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 17

At t = 0-

For t > 0

At t = ∞

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 18

For the closed-loop system shown, the transfer function is

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 18

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 19

In the open interval (0, 1), the polynomial p(x) = x4 - Ax3 + 2 has

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 19

It is clear that point of intersection of these graphs is solution (or) root of p(x) = 0

According to intermediate value theorem

P[0) and P{ 1) are having opposite signs

a root of p(x) = 0 in (0, 1)

and also from graph, there is only one point of intersection

Hence exactly one real root exists in (0, 1)

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 20

Inductance is measured by

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 21

For the network shown, the equivalent Thevenin voltage and Thevenin impedance as seen across terminals 'ab’ is

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 21

Given circuit can be resolved as shown below,

VTH = 15 + 50 = 65 V

Vx = 2 + 3 + 10 = 15 V

*Answer can only contain numeric values
Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 22

Two single-core power cables have total conductor resistances of 0.7 Q and 0.5 Q, respectively, and their insulation resistances (between core and sheath) are 600 MQ and 900 M£1 respectively, When the two cables are joined in series, the ratio of insulation resistance to conductor resistance i s _______ x 106.


Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 22

*Answer can only contain numeric values
Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 23

The Bode magnitude plot for the transfer function of the circuit is as shown. The value of R i s ______ Q. (Round off 2 decimal places)


Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 23

From response plot

From electrical network

*Answer can only contain numeric values
Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 24

Consider a continuous-time signal x{t) defined by for |t| ≤ 1. Let the Fourier transform of x(t) be defined as . The maximum magnitude of X (ω) is ____.


Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 24

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 25

A counter is constructed with three D flip-flops. The input-output pairs are named (D0, Q0), (D1 Q1 and (D2, Q2), where the subscript 0 denotes the least significant bit. The output sequence is desired to be the Gray-code sequence 000, 001,011,010,110,111, 101 and 100, repeating periodically. Note that the bits are listed in the G2Q1G0 format. The combinational logic expression for D1 is

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 25

*Answer can only contain numeric values
Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 26

Consider the buck-boost converter shown. Switch G is operating at 25 kHz and 0.75 duty-cycle. Assume diode and switch to be ideal. Under steady-state condition, the average current flowing through the inductor i s ______A.


Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 26

Assume continous conduction:

 

*Answer can only contain numeric values
Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 27

A belt-driven DC shunt generator running at 300 RPM delivers 100 kW to a 200 V DC grid. It continues to run as a motor when the belt breaks, taking 10 kW from the DC grid. The armature resistance is 0.025 Q, field resistance is 50 Q, and brush drop is 2 V. Ignoring armature reaction, the speed of the motor i s ______ RPM. (Round off 2 decimal places)


Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 27

Ia = 504 A

Eq =  V + Ia Ra + Brush drop

= 200 + 504 (0.025) + 2V

= 214.6 V

In motoring case : VI = 10kW, V = 200 V

If = 4A, Ia = IL - If

= 46 A

Eb = V - IaRa - Brush drop

= 200 - 46 (0.025) - 2 =196.85 V

Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 28

Let p(z) = z3 + (1 + j)z2 + (2 + j)z + 3, where z is a complex number. Which one of the following is true?

Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 28

Since sum of the roots is a complex number => absent one root is complex So all the roots cannot be real.

*Answer can only contain numeric values
Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 29

A signal generator having a source resistance of 50 Ω is set to generate a 1 kHz sinewave. Open circuit terminal voltage is 10 V peak-to-peak. Connecting a capacitor across the terminals reduces the voltage to 8 V peak-to-peak. The value of this capacitor i s _____ µF. (Round off to 2 decimal places).


Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 29

*Answer can only contain numeric values
Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 30

The power input to a 500 V, 50 Hz. 6-pole. 3-phase induction motor running at 975 RPM is 40 kW. The total stator losses are 1 kW. If the total friction and windage losses are 2.025 kW. then the efficiency i s ________ %.


Detailed Solution for Test: GATE Electrical Engineering (EE) Previous Paper 2021 - Question 30

 Stator loss = 1 kW, F and W =  2.025 kW

Stator o/p = 40 - 1 = 39 kW

Slip = = 0.025

Rotor o/p = Rotor i/p X (1 - S)

= 39 (1 - 0.025) = 38.025 kW

Motor o/p = 38.025 - 2.025 = 36 kW

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