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JEE Main 2022 June 25 Shift 1 Paper & Solutions - JEE MCQ


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30 Questions MCQ Test - JEE Main 2022 June 25 Shift 1 Paper & Solutions

JEE Main 2022 June 25 Shift 1 Paper & Solutions for JEE 2024 is part of JEE preparation. The JEE Main 2022 June 25 Shift 1 Paper & Solutions questions and answers have been prepared according to the JEE exam syllabus.The JEE Main 2022 June 25 Shift 1 Paper & Solutions MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main 2022 June 25 Shift 1 Paper & Solutions below.
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JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 1

If , then the relative error in Z will be:

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 1


In case of error,

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 2

is a vector quantity such that || = non-zero constant. Which of the following expressions is true for ?

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 2

For non zero vectors,  we can write
Scalar product,   and ,
Vector product, 
Now, if we take , then

Hence option (C) is the correct one.

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JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 3

Which of the following relations is true for two unit vectors  and  making an angle θ to each other?

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 3


JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 4

If force  acts on a particle having position vector , then the torque about the origin will be:

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 4

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 5

The height of any point P above the surface of earth is equal to diameter of earth. The value of acceleration due to gravity at point P will be:
(Given, g = acceleration due to gravity at the surface of earth)

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 5

Acceleration due to gravity,

The value of g is to be found at diameter from the surface = 2r
So, effective r = 2r + r = 3r

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 6

The terminal velocity (vt) of the spherical rain drop depends on the radius (r) of the spherical rain drop as:

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 6

The terminal velocity of the spherical drop is:

r is the radius of the sphere, η is the viscosity of the medium, ρp is the density of the sphere and ρ1 is the density of the medium.

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 7

The relation between root mean square speed (Vrms) and most probable speed (vp) for the molar mass M of oxygen gas molecule at the temperature of 300 K will be:

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 7

Root mean square speed,

Most probable speed,

So, by dividing Vrms and Vmp, we get
vrms = vmp

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 8

n the figure, a very large plane sheet of positive charge is shown. P1 and P2 are two points at distance l and 2l from the charge distribution. If σ is the surface charge density, then the magnitude of electric fields E1 and E2 at P1 and P2 respectively are:

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 8

Electric field due to a uniformly charged surface is:
E = σ/2 ∈o
Electric field due to uniformly charged surface does not depend on distance from the surface, so  will be same in both cases.
Thus, 

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 9

Match List-I with List-II.

Choose the correct answer from the options given below:-

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 9
  • An AC generator converts mechanical energy into electrical energy.
  • A galvanometer shows deflection when current passes through it, so it is used to show the presence of current in any wire.
  • A transformer is used to step up or step down the voltage.
  • A metals detector has inductor coils and uses the principle of induction and resonance in AC circuit.
JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 10

A long straight wire with a circular cross-section having radius R, is carrying a steady current I. The current I is uniformly distributed across this cross-section. Then the variation of magnetic field due to current I with distance r (r < R) from its centre will be

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 10

Use Amperes' Law:


Thus,
B ∝ r

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 11

If wattless current flows in the AC circuit, then the circuit is:

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 11

Purely inductive circuit:
θ = π/2
cosπ/2= 0
Average power = 0
Power dissipation becomes zero when there is only a capacitor or inducer in a circuit, even though there is still current flowing through it.

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 12

The electric field in an electromagnetic wave is given by E = 56.5 sinω(t - x/c) NC-1. Find the intensity of the wave if it is propagating along x-axis in the free space. (Given, ε0= 8.85 × 10-12 C2 N-1 m-2)

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 12

Intensity of the electromagnetic wave is:

Given, E = 56.5 sin (t - x/c) NC-1 and permittivity of free space = 8.85 × 10-12 C2 N-1 m-2
Putting these values in the formula:

= 4.24 Wm-2

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 13

The two light beams having intensities I and 9I interfere to produce a fringe pattern on a screen. The phase difference between the beams is π/2 at point P and π at point Q. Then the difference between the resultant intensities at P and Q will be:

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 13

The resultant intensity is:

= 10I - 6 I = 4I
∴ IP - IQ = 10I - 4I = 6I

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 14

A light wave is travelling linearly in a medium of dielectric constant 4, incident on the horizontal interface separating medium with air. The angle of incidence for which the total intensity of incident wave will be reflected back into the same medium will be (Given: relative permeability of medium μr= 1)

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 14

For total internal reflection, i > θC
Taking the sine function on both sides, we get

Permeability, 

From (1), sin i > 1/2
⇒  i > 30°, i = 60°

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 15

Given below are two statements:
Statement I: Davisson-Germer experiment establishes the wave nature of electrons.
Statement II: If electrons have wave nature, they can interfere and show diffraction.
In the light of the above statements, choose the correct answer from the options given below:

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 15

In Davisson-Germer experiment, electrons exhibit diffraction when they are passed through atomic crystals, hence proving that electrons have wave nature.
So, both Statement I and Statement II are true.

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 16

The ratio for the speed of the electron in the 3rd orbit of He+ to the speed of the electron in the 3rd orbit of hydrogen atom will be:

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 16

Velocity of an electron is directly proportional to the ratio of atomic number (Z) to constant n.
 (n = constant)
Atomic number of He = 2
Atomic number of H = 1
⇒ 

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 17

The photodiode is used to detect the optical signals. These diodes are preferably operated in reverse biased mode because

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 17

A photodiode is used to detect optical signals.
Very small change in minority charge carriers produces high value of reverse bias current.

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 18

A signal of 100 THz frequency can be transmitted with maximum efficiency by:

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 18

The range of an optical fibre is 1 THz to 1,000 THz.

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 19

The difference of speed of light in the two media A and B (vA - vB) is 2.6 × 107 m/s. If the refractive index of medium B is 1.47, then the ratio of refractive index of medium B to medium A is: (Given: Speed of light in vacuum, c = 3 × 108 ms-1)

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 19

Speed of light in a medium,

c is the speed of light and μ is the refractive index.
⇒ 
= 2.04 × 108 = 20.4 × 107 m/s
∴ vA - vB = 2.6 × 107 m/s
∴ vA = (20.4 + 2.6) × 107 = 23 × 107 m/s
∴  

JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 20

A teacher in his physics laboratory allotted an experiment to determine the resistance (G) of a galvanometer. Students took the observations for 1/3 deflection in the galvanometer. Which of the below is true for measuring value of G?

Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 20

In the galvanometer, ass G and S are parallel;
⇒ (I - Ig) S = Ig G


⇒  S + G = 3S
⇒ G = 2S
G equals twice the shunt resistance.

*Answer can only contain numeric values
JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 21

A uniform chain of 6 m length is placed on a table such that a part of its length is hanging over the edge of the table. The system is at rest. The coefficient of static friction between the chain and the surface of the table is 0.5, the maximum length of the chain hanging from the table is _________ m.


Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 21

Mass per unit length = λ
N = mg = λ(L - x)g
fsmax = μSN

fsmax = (0.5)(λ)(L - x)g
Also, fsmax = mxg
0.5λ(L - x)g = λxg
L - x / 2 = x
So,

*Answer can only contain numeric values
JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 22

A 0.5 kg block moving at a speed of 12 ms-1 compresses a spring through a distance 30 cm when its speed is halved. The spring constant of the spring will be _______________ Nm-1.


Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 22

We know,
Ui + Ki = Uf + Kf

⇒ 0.5(122 - 62) = K(0.3)2
K = 600 N/m

*Answer can only contain numeric values
JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 23

The velocity of upper layer of water in a river is 36 kmh-1. Shearing stress between horizontal layers of water is 10-3 Nm-2. Depth of the river is __________ m. (Coefficient of viscosity of water is 10-2 Pa.s)


Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 23


⇒ 
= 100 m

*Answer can only contain numeric values
JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 24

A steam engine intakes 50 g of steam at 100°C per minute and cools it down to 20°C. If latent heat of vaporization of steam is 540 cal g-1, then the heat rejected by the steam engine per minute is _______ × 103 cal.


Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 24

Heat rejected = mLf + mSΔT
= (50 × 540) + 50(1)(100 - 20)
= 31,000 cal
= 31 × 103 cal

*Answer can only contain numeric values
JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 25

The first overtone frequency of an open organ pipe is equal to the fundamental frequency of a closed organ pipe. If the length of the closed organ pipe is 20 cm, the length of the open organ pipe is _____ cm.


Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 25


Given, f1 = f2

l1 = 4l2 = 80 cm

*Answer can only contain numeric values
JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 26

The equivalent capacitance between points A and B in below shown figure will be ________ μF.


Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 26

Two capacitors are short circuited.

So, equivalent capacitance

= 6 μF

*Answer can only contain numeric values
JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 27

A resistor develops 300 J of thermal energy in 15 s, when a current of 2 A is passed through it. If the current increases to 3 A, the energy developed in 10 s is ___________ J.


Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 27

Energy or heat,
H = i2Rt
300 = 22 × R × 15
⇒ R = 300/60 = 5Ω
Now, for i = 3 A, t = 10 s, R = 5Ω
H = 32 × 5 × 10 = 450 J

*Answer can only contain numeric values
JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 28

The total current supplied to the circuit as shown in figure by the 5 V battery is __________ A.


Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 28



So, current supplied by the 5 V battery
= 5V / 2.5Ω
= 2A

*Answer can only contain numeric values
JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 29

The current in a coil of self inductance 2.0 H is increasing according to I = 2sin(t2)A. The amount of energy spent during the period when current changes from 0 to 2 A is _______ J.


Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 29

I = 2sin(t2) ⇒ dI = 4tsin(t2) dt
So, if I = 0 ⇒ t = 0
and I = 2 ⇒ 2 = 2 sin t2

= 2[-cosπ + cos 0] = 4

*Answer can only contain numeric values
JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 30

A force on an object of mass 100 g is  N. The position of that object at t = 2 s is  N. The position of that object at t = 2 s is  m after starting from rest. The value of a/b will be ____________.


Detailed Solution for JEE Main 2022 June 25 Shift 1 Paper & Solutions - Question 30


Given, m = 100 g = 0.1 kg

a = 200, b = 100
∴ a /b  = 2

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