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Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Mechanical Engineering MCQ


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30 Questions MCQ Test - Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1)

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) below.
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Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 1

“The increased consumption of leafy vegetables in the recent months is a clear indication that the people in the state have begun to lead a healthy lifestyle”  Which of the following can be logically inferred from the information presented in the above statement?

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 1

As increased consumption of leafy vegetables is directly proportional to healthy lifestyle. So we can inferred that leading a healthy lifestyle is related to diet with leafy vegetables.
Hence, the correct option is (A). 

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 2

Five persons P, Q, R, S and T are sitting in a row not necessarily in the same order. Q and R are separated by one person, and S should not be seated adjacent to Q.
The number of distinct seating arrangements possible is

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 2

Step 1 : Make proper drafting of given information 

Step 2 : Possibilities of seating arrangements. 
Case 1 :
Q P R S T  
Q T R S P 
Q P R T S 
Q T R P S 
Case 2 :
P Q T R S  
T Q P R S 
Case 3 :
S P Q T R  
S T Q P R 
Case 4 :
R P Q T S
R T Q P S 
Case 5 :
S R P Q T
S R T Q P
Case 6 :
P S R T Q
T S R P Q 
S P R T Q
S T R P Q 

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Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 3

A jigsaw puzzle has 2 pieces. One of the pieces is shown below . Which one of the given options for the missing piece when assembled will form a rectangle? The piece can be moved, rotated or flipped to assemble with the above piece. 

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 3

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 4

Ms. X came out of a building through its front door to find her shadow due to the morning sun falling to her right side with the building to her back. From this, it can be inferred that building is facing_____

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 4


Hence, the correct option is (D).

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 5

If 
Then the value of the expression  Δ2⊕3Δ (( 4⊗2)∇4) =

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 5

As per the data new equation will be :  
Step 1 : +2−3 + ((4 ÷ 2) × 4)
Step 2 : 2 −3+ 8 = 7
Hence the correct option is (A). 

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 6

Oxpeckers and rhinos manifest a symbiotic relationship in the wild. The oxpeckers warn the rhinos about approaching poachers, thus possibly saving the lives of the rhinos. Oxpeckers also feed on the parasitic ticks found on rhinos.  In the symbiotic relationship described above, the primary benefits for oxpeckers and rhinos respectively are.

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 6

As per the data given in above statement, (A) Oxpeckers get food source, rhinos may be saved from the poachers.
Hence, the correct option is (A). 

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 7

Consider the following statements:  
(i) After his surgery, Raja hardly could walk. 
(ii)  After his surgery, Raja could barely walk.  
(iii) After his surgery, Raja barely could walk.  
(iv) After his surgery, Raja could hardly walk.

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 7

Grammatically correct statements are :  
(i) After his surgery, Raja could barely walk.
(ii) After his surgery, Raja could hardly walk.

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 8

The distribution of employees at the rank of executives, across different companies C1, C2, ….., C6 is presented in the chart given below . The ratio of executives with a management degree to those without a management degree in each of these companies is provided in the table above. The total number of executives across all companies is 10,000.  

The total number of management degree holders among the executives in companies C2 and C5 together is _________ . 

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 8

 Total number of employees = 10000 

∵ Management and without management degree ratio = C2 = 1: 4 and C5 = 9: 1
∵ Number of management degree executive of C2 and C5

Thus, number of management degree employees in C2 and C5 together = 1900 .  
Hence, the correct option is (C).

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 9

The number of hens, ducks and goats in farm P are 65, 91 and 169, respectively. The total number of hens, ducks and goats in a nearby farm Q is 416. The ratio of hens:ducks:goats in farm Q is 5:14:13. All the hens, ducks and goats are sent from farm Q to farm P.  
The new ratio of hens:ducks:goats in farm P is ________  

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 9

Farm P :
Hp = 65,Dp= 91 and Gp = 169
Farm Q : 
HQ +DQ+ GQ = 416    …(i) 


From equation (i), 
5x +14x+ 13x = 416
32x = 416
x = 416/32  = 13
HQ = 5x= 5 ×13 = 65
DQ =  14 14 13 182
GQ = 13x= 13 ×13 = 169
According to question, 

Hence, the correct option is (B). 

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 10

In the below figure, O is the center of the circle and, M and N lie on the circle. The area of the right triangle MON is 50 cm2 .

What is the area of the circle in cm2 ?

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 10

Area of triangle MNO = 50 cm2

Since, the radius of circle is OM = ON= r
Therefore, 
1/2 x r2 = 50
r2 = 100
r = 10
Then, the area of circle =πr2 =π(10)2 = 100π
Hence, the correct option is (C). 

*Answer can only contain numeric values
Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 11

Robot Ltd. wishes to maintain enough safety stock during the lead time period between starting a new production run and its completion such that the probability of satisfying the customer demand during the lead time period is 95%. The lead time period is 5 days and daily customer demand can be assumed to follow the Gaussian (normal) distribution with mean 50 units and a standard deviation of 10 units.
Using φ−1 (0.95)= 1.64 where φ represents the cumulative distribution function of the standard normal random variable, the amount of safety stock that must be maintained by Robot Ltd. to achieve this demand fulfillment probability for the lead time period is units (round off to two decimal places).


Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 11

Given :
Service level = 95%  
For 95% service level  
Z (95%) = 1.64  
Lead time = 5 days    
Mean, X = 50 units
Standard deviation, σ = 10 units

Safety stock, S.S. = Zσ = 1.64× 10 = 16.4 units
Therefore, the probability for the lead time period is 16.4 units. 

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 12

The loading and unloading response of a metal is shown in figure. The elastic and plastic strains corresponding to 200 MPa stress, respectively, are 

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 12


Plastic/Permanent strain = OB = 0.01  
Elastic strain = BC = 0.03 – 0.01 = 0.02  
Hence, the correct option is (C). 

*Answer can only contain numeric values
Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 13

The figure shows an arrangement of a heavy propeller shaft in a ship. The combined polar mass moment of inertia of the propeller and the shaft is 100 kg.m2 . The propeller rotates at ω= 12 rad/s . The waves acting on the ship hull induces a rolling motion as shown in the figure with an angular velocity of 5 rad/s. The gyroscopic moment generated on the shaft due to the motion described is ________N.m (round off to the nearest integer). 


Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 13

Given :
I = 100 kgm2
ω= 12 rad/s
ωp= 5rad/s
Gyroscopic couple 100 x12 x 5 = 6000 Nm

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 14

Shear stress distribution on the cross-section of the coil wire in a helical compression spring is shown in the figure. This shear stress distribution represents  

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 14

Spring is subjected to : 
1. Direct shear stress due to load.  
2. Torsional shear stress due to load.  
3. Shear stress due to curvature at inside edge of coil.
Hence, the correct option is (B). 

*Answer can only contain numeric values
Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 15

In the vicinity of the triple point, the equation of liquid-vapour boundary in the P – T phase diagram for ammonia is ln P = 24.38− 3063 /T , where P is pressure (in Pa) and T is temperature (in K). Similarly, the solid-vapour boundary is given by ln P = 27.92− 3754 /T . The temperature at the triple point is _______K (round off to one decimal place). 


Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 15

Given: Triple point regime for ammonia (NH3)
Triple point of any substance, all the three phases coexist with each other in phase equation.
∴ By equating (i) and (ii),  

T = 195.19 K

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 16

A cantilever beam of length, L, and flexural rigidity, EI, is subjected to an end moment, M, as shown in the figure. The deflection of the beam at x = L/2 is

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 16

Applying moment-area method,

Deflection,  


Hence, the correct option is (C). 

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 17

Consider a two degree of freedom system as shown in the figure, where PQ is a rigid uniform rod of length, b and mass, m .

Assume that the spring deflects only horizontally and force F is applied horizontally at Q . For this system, the Lagrangian, L is

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 17

Lagrangian, L = Kinetic Energy – Potential Energy
Kinetic Energy of mass

Potential Energy of rod = 
Kinetic Energy for rod:  
In this system,

Rod travels distance x and also rotated at an angle θ . We will take a small element dy at distance y of small mass dm (rod). 

So, total displacement of rod  = x + y sin θ
  And velocity =

( ⸪ θ is small so cos2 θ will become 1)


On putting value of dm, we get 

On integrating, 

Total Kinetic Energy = ( K .E)Total = ( K.E)M+ ( K .E)rod


Total Potential Energy = ( P.E)Total = ( P.E )Spring +  ( P.E)rod


 Lagrangian, L = (Kinetic Energy)Total – (Potential Energy)Total


Hence, the correct option is (C). 

*Answer can only contain numeric values
Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 18

A cantilever beam of rectangular cross-section is welded to a support by means of two fillet welds as shown in figure. A vertical load of 2 kN acts at free end of the beam  

Considering that  the allowable shear stress in weld is 60 N/mm2 , the minimum size (leg) of the weld required is ________mm (round off to one decimal place).


Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 18


Given :  Allowable shear stress,τp =  60 N/mm2


At = 40t + 40t = 80t mm2

(i) Primary shear stress ( τ') , 

(ii) Maximum bending stress (σb)max

h = 6.655 mm

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 19

The relative humidity of ambient air at 300 K is 50% with a partial pressure of water vapour equal to pv . The saturation pressure of water at 300 K is psat. The correct relation for the air-water mixture is 

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 19

Given : Relative humidity = 50% 
Relative humidity = pv / psat


Hence, the correct option is (C). 

*Answer can only contain numeric values
Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 20

A cylindrical jet of water (density = 1000 kg/m3) impinges at the center of a flat, circular plate and spreads radially outward, as shown in figure. The plate is resting on a linear spring with a spring constant k = l kN/m. The incoming jet diameter is D = 1cm. 

If the spring shows a steady deflection of 1 cm upon impingement of jet, then the velocity of the incoming jet is _________ m/s. (round off to one decimal place ) 


Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 20

Given : ρ= 1000 kg/m3 , k = 1kN/m
D = 1cm , x = 1cm and V = ?

Draw FBD of plate,

Balancing the force,
kx = mv1

v1 = 11.283 m/s

*Answer can only contain numeric values
Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 21

A machine part in the form of cantilever beam is subjected to fluctuating load as shown in the figure. The load varies from 800 N to 1600 N. The modified endurance, yield and ultimate strengths of the material are 200 MPa. 500 MPa and 600 MPa, respectively. 

The factor of safety of the beam using modified Goodman criterion is_________ (round off to one decimal place). 


Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 21

Given : σe = 200MPa
Syt = 500 MPa
Sut = 600MPa


Goodman criterion,


N ≤ 2
N ≈ 2
Langer,

According to modified Goodman criteria, we will select the smaller value of factor of safety from the above two values. So, factor of safety will be 2. 

*Answer can only contain numeric values
Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 22

Consider a single degree of freedom system comprising a mass M, supported on a spring and a dashpot as shown in the figure 

If the amplitude of free vibration response reduces from 8 mm to 1.5 mm in 3 cycles, that damping ratio of the system is _________. (round off to three decimal places). 


Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 22

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 23

Customers arrive at a shop according to the Poisson distribution with a mean of 10 customers/hour. The manager notes that no customer arrives for the first 3 minutes after the shop opens. The probability that a customer arrives within the next 3 minutes is 

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 23

Given: λ= 10 customer/hours, t = 3 minutes = 3/60 hour
n = 1 (for one customer to arrive) 
The probability that a customer arrive within the next 3 minutes is, 


P (1, 3) = 0.303
Since, the nearest option is D.
Hence, the correct option is (D) 

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 24

An infinitely long pin fin, attached to an isothermal hot surface, transfers heat at a steady rate of  to the ambient air. If the thermal conductivity of the fin material is doubled, while keeping everything else constant, the rate of steady-state heat transfer from the fin becomes . The ratio is   

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 24

Heat transfer with long fin is Q1 (conductivity = K) 

Heat transfer with long fin Q2 (conductivity = 2K) 

Hence, the correct option is (A). 

*Answer can only contain numeric values
Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 25

Two smooth identical spheres each of radius 125 mm and weight 100 N rest in a horizontal channel having vertical walls. The distance between vertical walls of the channel is 400 mm.  

The reaction at the point of contact between two spheres is _____ N (round off to one decimal place). 


Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 25



θ = 53.13o
FBD of body A,

N sin 53.13 = 100

= 125 N

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 26

The correct sequence of machining operations to be performed to finish a large diameter through hole is  

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 26

Drilling → Boring → Reaming

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 27

The Dirac-delta function (δ(t − t0 )) for t ,t0 ∈ R, has the following property 

The Laplace transform of the Dirac-delta function δ (t−a) for  a > 0;  
L{δ(t− a )} = F(s) is

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 27

δ(t − t0) = ∞, t = t0
δ(t − t0) = 0, t ≠ t0


For δ(t − t0) , Laplace transform will be, 
Laplace transform 

(for 0 < a< ∞ ) 
Hence, the correct option is (D). 

*Answer can only contain numeric values
Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 28

A short shoe drum (radius 260 mm) brake is shown in the figure. A force of 1 kN is applied to the lever. The coefficient of friction is 0.4. 

The magnitude of the torque applied by the brake is _______ N.m (round off to one decimal place). 


Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 28



In FBD of lever :  
Taking moment about O, ΣMO= 0
(1000 ×1000)− ( N × 500) − (0.4N × 50) = 0
N = 1923.0768 N
Braking torque,TB = μN x r 0.4 x 1923.076 x 0.26
TB = 200 Nm

Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 29

A right solid circular cone standing on its base on a horizontal surface is of height H and base radius R. The cone is made of a material with specific weight w and elastic modulus E. The vertical deflection at the mid-height of the cone due to self-weight is given by 

Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 29


Axial force = –weight of shaded region 

Displacement of mid point (δB )

Hence, the correct option is (B). 

*Answer can only contain numeric values
Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 30

A resistance spot welding of two 1.55 mm thick metal sheets is performed using welding current of 10000 A for 0.25 second. The contact resistance at the interface of the metal sheets is 0.0001Ω. The volume of weld nugget formed after welding is 70 mm3. Considering the heat required to melt unit volume of metal is 12 J/mm3, the thermal efficiency of the welding process is_________ %  (round off to one decimal place). 


Detailed Solution for Past Year Paper - Mechanical Engineering GATE : 2021 (Session - 1) - Question 30

Given :
t = 1.55 mm ,
I = 10000 A
T = 0.25 sec ,
R = 0.0001Ω
V = 70 mm3
Specific heat required for melting = 12 J/mm3

=  33.6%

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