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SSC CGL Exam  >  SSC CGL Tests  >  SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - SSC CGL MCQ

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - SSC CGL MCQ


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30 Questions MCQ Test - SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 for SSC CGL 2024 is part of SSC CGL preparation. The SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 questions and answers have been prepared according to the SSC CGL exam syllabus.The SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 below.
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SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 1
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Which is greater        (SSC CHSL 2013)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 1

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 2
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The value of  is       (SSC CHSL 2013)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 2

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SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 3
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The greatest among the following numbers       is:       (SSC Sub. Ins. 2013)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 3

LCM of 3, 2 and 6 = 6

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 4
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The value of  is:      (SSC Sub. Ins. 2013)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 4


= 4.4 + 0.44 + 0.044 + 0.0044 = 4.8884

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 5
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The value of  is:         (SSC Sub. Ins. 2013)
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SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 6
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 equals        (SSC Multitasking 2013)
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SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 7
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The simplified value of  is        (SSC Multitasking 2013)
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SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 8
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If 21 is added to a number, it becomes 7 less than thrice of the number. Then the number is       (SSC CGL 2012)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 8

If the number be x, then
x + 21 = 3x – 7
⇒ 3x – x = 21 + 7
⇒ 2x = 28
⇒ x = 14

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 9
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The simplest value of  is       (SSC CGL 2012)
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∴ Expression

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 10
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 is equal to       (SSC CGL 2012)
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SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 11
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If then the value of x is:       (SSC CGL 2nd Sit. 2012)
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SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 12
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By what least number should 675 be multiplied to obtain a number which is a perfect cube?        (SSC CGL 2012)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 12

675 = 5 × 5 × 3 × 3 × 3
= 33 × 52
∴ Required number = 5

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 13
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A farmer divides his herd of n cows among his four sons, so that the first son gets one–half the herd, the second one– fourth, the third son 1/5 and the fourth son 7 cows. Then thevalue of n is       (SSC CGL 2012)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 13

According to the question,

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 14
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 is equal to        (SSC CGL 2012)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 14

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 15
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If  then the value of x is        (SSC CGL 2012)
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SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 16
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The value of  is equal to       (SSC CGL 1st Sit. 2012)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 16


On squaring,

⇒ x2 = 6 + x
⇒ x2 – x – 6 = 0
⇒ x2 – 3x + 2x – 6 = 0
⇒ x (x – 3) + 2 (x –3) = 0
⇒ (x – 3) (x + 2) = 0
⇒ x = 3 because x ≠ -2
By trick 3 x 2 = 6

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 17
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From 9.00 AM to 2.00 PM, the temperature rose at a constant rate from 21ºC to 36ºC. What was the temperature at noon ?       (SSC CHSL 2012)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 17

Time difference between 9.00 A.M & 2.00 P.M = 5 hours
Temperature difference between 21°C & 36°C = 36 – 21 = 15°C
Now, Time difference between 9.00 A.M & 12.00 Noon = 3 hrs.
In 5 hours 
So, In 3 hours 
So, temperature at noon = 21 + 9 = 30°C

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 18
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If  then the value of n is:       (SSC CHSL 2012)
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Comparing, n/3 = 3
x = 9

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 19
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If  then the value  is :      (SSC CHSL 2012)
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SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 20
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The value of  is       (SSC Sub. Ins. 2012)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 20


= 63 x 2 = 126

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 21
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What is the value of        (SSC Sub. Ins. 2012)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 21

Expression is = 4.41 × 0.21 = 0.9261

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 22
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Last year my age was a perfect square number. Next year it will be a cubic number. What is my present age?       (SSC Sub. Ins. 2012)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 22

By going options, 26 years is the present age. Present age be 26, then last year age was 25 which represents a perfect square and next year age would be 27 which represents a cubic number.

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 23
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A student was asked to divide a number by 6 and add 12 to the quotient. He, however, first added 12 to the number and then divided it by 6, getting 112 as the answer. The correct answer should have been       (SSC CGL 2nd Sit. 2011)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 23

Let the number be x

⇒ x + 12 = 672
⇒ x = 672 – 12 = 660
∴ Correct answer = (660/6) + 12 = 110 + 12 = 122

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 24
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The value of  is       (SSC CGL 2nd Sit. 2011)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 24


SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 25
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If  then the value of x is        (SSC CGL 2nd Sit. 2011)
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SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 26
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If  then the values of a and b arerespectively       (SSC CGL 2nd Sit. 2011)
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By Rationalising

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 27
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Find a number, one–seventh of which exceeds its eleventh part by 100.        (SSC CGL 2nd Sit. 2011)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 27

Let the number be x.

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 28
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If the sum of two numbers be multiplied by each number separately, the products so obtained are 247 and 114. The sum of the numbers is        (SSC CGL 2nd Sit. 2011)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 28

Let the numbers be x and y.
∴ x (x + y) = 247
and y (x + y) = 114
⇒ x2 + xy = 247 and xy + y2 = 114
On adding;
x2 + xy + xy + y2 = 247 + 114
⇒ x2 + 2xy + y2 = 361
⇒ (x + y)2 = 192 ⇒  x + y = 19

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 29
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 is equal to       (SSC CGL 2nd Sit. 2011)
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SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 30
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If  then x = ?       (SSC CGL 2011)
Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 3 - Question 30


∴ x = 3

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