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SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical


MCQ Practice Test & Solutions: SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 (20 Questions)

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  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 20

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SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 1

Nisha and Deepak are a married couple and have a daughter named Tanya. Currently, Deepak is 5 years older than Nisha and Nisha is thrice the age of Tanya. If Tanya is 10 years old, what was her father’s age at the time of his daughter’s birth? (SSC CGL 2018)

Detailed Solution: Question 1

Tanya’s mother is thrice the age of her daughter
So, Tanya’s mother Nisha’s current age
= 3 x 10 = 30 years.
Tanya’s father Deepak’s current age
= 30 + 5 = 35 years.
So, Deepak’s age at the time of Tanya’s birth
= 35 – 10 = 25 years.

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 2

Which two signs should be interchanged in the following equation to make it correct?   (SSC CGL 2018)
8 x 2 + 5 – 16 ÷ 4 = 14

Detailed Solution: Question 2

8 x 2 + 5 – 16 ÷ 4 = 14
After changing ‘x’ and ‘+’,
we get
8 + 2 x 5 – 16÷ 4 = 8 + 10 – 4 = 14

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 3

The sum of the current ages of Shipra and Malini is 65 years.After 5 years, Shipra’s age will be 15 years more than Malini’s age. What is Malini’s curr ent age?        (SSC CGL 2018)

Detailed Solution: Question 3

Let Malini’s current age is x years, then Shipra’s current age is (65 - x) years.
ATQ,
(65 - x) + 5 - (x + 5) = 15
65 - 2x = 15
⇒ 2x = 50, x = 25 years
Hence, Malini’s current age = 25 years.

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 4

Which two signs should be interchanged to make th e followin g equation correct?   (SSC CGL 2018)
5 + 16 – 4 × 14 ÷ 2 = 59

Detailed Solution: Question 4

5 + 16 - 4 x 14 ¸ 2 = 59
changing ÷ and -,
we get
5 + 16 ÷ 4 x 14 - 2 = 59
5 + 4 x 14 - 2
= 5 + 56 - 2 = 59

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 5

Which two signs should be interchanged in the following equation to make it correct?    (SSC CHSL 2018)

15 + 15 – 2 × 10 ÷ 35 = 16

Detailed Solution: Question 5

The given expression: 15 + 15 – 2 × 10 ÷ 35 = 16
After exchanging ‘+’ and ‘÷’, we get 15 ÷ 15 – 2 × 10 + 35 = 16
1 – 20 + 35 = 16
36 – 20 = 16
16 = 16.

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 6

Which two signs should be interchanged to make the following equation correct?     (SSC Sub. Ins. 2018)
12 – 8 + 12 × 9 ÷ 3 = 9

Detailed Solution: Question 6

Correct answer is B.

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 7

Which two numbers should be interchanged to make the given equation correct?     (SSC Sub. Ins. 2018)

9 + 4 ÷ 2 - 6 x 3 = 4 ÷ 3 x 6 - 9 + 1

Detailed Solution: Question 7

From option (a) 9 + 4 ÷ 2 – 6 × 3 = 4 ÷ 3 × 6 – 9 + 1
⇒ 9 + 6 ÷ 2 – 4 × 3 = 6 ÷ 3 × 4 – 9 + 1
⇒ 9 + 6/2 - 4 x 3 = 6/3 x 4 -9 + 1
⇒ 9 + 3 – 4 × 3 = 2 × 4 – 9 + 1
⇒ 12 – 12 = 8 – 9 + 1
⇒ 0 = 0 (L. H. S. = R.H.S)
So, option (a) is correct answer.

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 8

Which of the tollowing interchanges ot signs and numbers would make the given equation correct?   (SSC Sub. Ins. 2018)
12 ÷ 4 + 2 - 6 x 3 = 3 ÷ 12 + 6 x 2 - 4

Detailed Solution: Question 8

After interchanging signs and numbers,

12 ÷ 4 + 2 – 6 × 3 3 ÷ 12 + 6 × 2 - 4

× and ÷, 4 and 6 → 12× 6 + 2 - 4 ÷ 3 = 218/3 and 3 × 12 + 4 ÷ 2 – 6 = 32

÷ and +, 6 and 4 → 12 + 6 ÷ 2 - 4 × 3 = 3 and 3 + 12 ÷ 4 × 2 - 6 = 3

× and -, 4 and 6 → 12 ÷ 6 + 2 × 4 - 3 = 7 and 3 ÷ 12 + 4 - 2 × 6 = -31/4

- and +, 6 and 4 → 12 ÷ 6 - 2 + 4 × 3 = 12 and 3 ÷ 12 - 4 × 2 + 6 = -7/4

Hence, the correct answer is ÷ and +, 6 and 4.

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 9

If ‘A’ is replaced by ‘+’; if ‘B’ is replaced by ‘–’; ‘C’ is replaced by ‘÷’; and ‘D’ replaced by ‘x’,  then find the value of  the following equation.    (SSC Stenographer 2018)

20A15C3D8B9

Detailed Solution: Question 9

20 A 15 C 3 D 8 B 9
⇒ 20 + 15 ÷ 3 × 8 – 9
⇒ 20 + 5 × 8 – 9
​​​​​​​⇒ 20 + 40 – 9
​​​​​​​⇒ 60 – 9 = 51

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 10

Find out th e two signs to be inter ch anged for making following equation correct:    (SSC Stenographer 2018)
25 + 5 x 7 – 12 ÷ 3 = 26

Detailed Solution: Question 10

Interchanging the signs and using BODMAS rule,

Option 1 → + and –

The original equation is,

25 + 5 × 7 – 12 ÷ 3 = 26

Interchanging the signs,

25 – 5 × 7 + 12 ÷ 3 = 26

Using BODMAS rule,

25 – 5 × 7 + 4 = 26

25 – 35 + 4 = 26

29 – 35 is not equal to 26

Hence, option 1 is the correct answer.

Option 2 → + and ÷

The original equation is,

25 + 5 × 7 – 12 ÷ 3 = 26

Interchanging the signs,

25 ÷ 5 × 7 – 12 + 3 = 26

Using BODMAS rule,

5 × 7 – 12 + 3 = 26

35 – 12 + 3 = 26

38 – 12 = 26

26 = 26

Option 3 → + and ×

The original equation is,

25 + 5 × 7 – 12 ÷ 3 = 26

Interchanging the signs,

25 × 5 + 7 – 12 ÷ 3 = 26

Using BODMAS rule,

25 × 5 + 7 – 4 = 26

125 + 7 – 4 = 26

132 – 4 is not equal to 26

Option 4 → – and ÷

The original equation is,

25 + 5 × 7 – 12 ÷ 3 = 26

Interchanging the signs,

25 + 5 × 7 ÷ 12 – 3 = 26

Using BODMAS rule,

25 + 5 × 7/ 12 – 3 = 26

25 + 35/ 12 – 3 is not equal to 26

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 11

Find out th e two signs to be inter ch anged for making following equation correct.      (SSC Stenographer 2018)

5 + 3 x 4 – 12 ¸ 2 = –1

Detailed Solution: Question 11

5 + 3 × 4 – 12 ÷ 2 = – 1
⇒ 5 – 3 × 4 + 12 ÷ 2 = – 1
⇒ 5 – 12 + 6 =  – 1
⇒ 11 – 12 = – 1
⇒ –1 = – 1 (L.H.S. = R.H.S.)

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 12

If ‘A’ is replaced by ‘+’; if ‘B’ is replaced by ‘–’;  ‘C’ is replaced by ‘÷’; and ‘D’ replaced by ‘x’, find the value of the  following equation.     (SSC Stenographer 2018)

51C17D15A22B34

Detailed Solution: Question 12

51 C 17 D 15 A 22 B 34
⇒ 51 ÷ 17 × 15 + 22 – 34
⇒ 3 × 15 + 22 – 34
⇒ 45 + 22 – 34
= 67 – 34 = 33

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 13

Rakhi got engaged 10 years ago. Rakh i's presen t age is 5/3 of her age at the time of engagement. If the present age of Rakhi's mother is twice that of present age of Rakhi, then what was her mother's age (in years) at the time of her engagement. (SSC CGL 2017)

Detailed Solution: Question 13

Let present age of Rakhi = x years
Age of Rakhi at the time of engagement = (x – 10) years
According to question,

∴ Mother's age of Rakhi = 2 × 25 = 50 years.
∴ Mot her's age of Rakhi at the time of her engagement = 50 – 10 = 40 years.

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 14

In the following question , correct the equation by interchanging two signs.   (SSC CGL 2017)

9 × 3 + 8 ÷ 4 – 7 = 28

Detailed Solution: Question 14

Given Equation ⇒ 9 × 3 + 8 ÷ 4 – 7 = 28

After interchanging,

1) × and –

⇒ 9 – 3 + 8 ÷ 4 × 7 = 28

⇒ 5 + 2 × 7 = 28

→ 19 = 28 (LHS ≠ RHS) (False)

2) + and –

⇒ 9 × 3 – 8 ÷ 4 + 7 = 28

⇒ 27 – 2 + 7 = 28

→ 33 = 28 (LHS ≠ RHS) (False)
 

3) × and ÷

⇒ 9 ÷ 3 + 8 × 4 – 7 = 28

⇒ 3 + 32 – 7 = 28

⇒ 28 = 28 (True) 

4) ÷ and +

⇒ 9 × 3 ÷ 8 + 4 – 7 = 28

⇒ 3.375 – 3 = 28

→ 0.375 = 28 (LHS ≠ RHS) (False)

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 15

If 4 * 5 % 3 = 8000 and 2 * 3 % 2 = 36, then 4 * 3 % 3 = ?     (SSC CGL 2017) 

Detailed Solution: Question 15

As, 4 * 5 % 3 = 8000
⇒ (4 × 5)3 = 8000
and 2 * 5 % 2 = 36
⇒ (2 × 3)2 = 36
Similarly, 4 * 3 % 3 = ?
(4 × 3)3 = 1728

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 16

Nine years later, age of B will be equal to the present age of A. Sum of A's age 3 years later and B's age 4 years ago is 76.If C is half of the present age of B, then what will be C's age (in year s) after 10 years?   (SSC CGL 2017)

Detailed Solution: Question 16

Let A’s present age be x
B’s age = x – 9
A’s age 3 year later = x + 3
B’s age 4 year ago = x – 9 – 4
A/c to the question x + 3 + x – 9 – 4 = 76
2x = 86 x = 43
B’s present age = 43 – 9 = 34
C’s present age = B's/2
Hence age of C after 10 year = 34/2 = 17 + 10 = 27

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 17

In the following question , correct the equation by interchanging two signs. (SSC CGL 2017)

4 × 3 – 6 ÷ 2 + 7 = 8

Detailed Solution: Question 17

option (a),
4 × 3 + 6 ¸ 2 – 7 = 8
15 – 7 = 8
So, option (a) is correct.

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 18

If 3 # 4 % 8 = 6 and 9 % 4 # 3 = 12, then 12 % 6 # 24 = ?        (SSC CGL 2017)

Detailed Solution: Question 18

As, 3 # 4% 8 =  6
3 ÷ 4 x 8 = 6
3/4 x 8 = 6
and 9% 4 # 3 = 12
9 x 4 ÷ 3 = 12
9 x 4/3 = 12
Similarly, 
12 % 6 # 24 = ?
12  x 6 ÷ 24 = 3
12 x 6/24 = 3
So, answer is 3.

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 19

In the following question, by using which math ematical operator will the expression become correct?        (SSC CGL 2017)

18 ? 6 ? 9 ? 27

Detailed Solution: Question 19

From option (b). 18 ÷ 6 × 9 = 27
18/6 x 9  = 27
So, option (b) is correct.

SSC CGL Previous Year Questions: Mathematical Operation and Arithmetical Reasoning - 1 - Question 20

If 18 (9) 3 and 36 (30) 5, then what is the value of  A in 19 (A) 18?   (SSC CGL 2017)

Detailed Solution: Question 20

As,


Similarly,

So, value of A is 57.

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