BITSAT Chemistry Test - 2 - JEE MCQ

→ Phenelzine contains hydrazine(2-phenylethylhydrazine)

→ Chloroxylenol contains phenol(4-Chloro-3,5-dimethylphenol)

→ Uracil is the pyrimidine base(2,4-Dihydroxypyrimidine)

→ Ranitidine contains furan ring

During exercise muscle need energy hence consume more oxygen and produce more CO₂ and lactic acid gets accumulated as well. According to bohr's effect oxygen binding affinity is inversely proportional to CO₂ concentration and acidity. Thus favours the dissociation​ or release of O₂.

Pressure increase solubility also increase in accordance with the Henry's law and option B is the closest to this. Hence B is correct.

H+  H⁺ + F^–
pK_w = pK_a + pKb
[For conjugate Acid-Base]
⇒ pK_a = 14 – 10.87 = 3.17
K_a = 6.76 × 10^–4

Concentration of solution =C=1M
Dissociation is α=0.01
After dissociation, the concentration of H⁺ ions will be Cα=1×0.01=10⁻²
pH=−log[H⁺]=−log(10⁻²) = +2

OF₂ Fluorine is most electronegative atom with oxidation number = - 1
x - 2 = 0
x = + 2
H₂O₂   2 + 2x = 0 ⇒ x = - 1 

• ClO₃^- : A very reactive inorganic anion.
• The term chlorate can also be used to describe any compound containing the chlorate ion, normally chlorate salts. 
• Example: Potassium chlorate, KClO₃

Based on Fajans' rule,
Smaller the size of cation, larger the size of anion, larger the charge,
d-f-Aelectrons present then larger the polarising power, larger the covalent nature and larger the lattice energy.

By Fajans’ rule,
Smaller the size of cation, larger the size of anion, larger the charge, then larger the polarising power, larger the covalent nature, means low melting point.
Smaller the ionic nature, means low melting point 


Hence, most stable is LiF.

At 100°C and 1 atmosphere pressure H₂O (l) ⇋ H₂O(g) is at equilibrium. For equilibrium

∆S_X→Z = ∆S_X→Y + ∆S_Y→Z(Entropy is a state function, so it is additive)
W_X→Y→Z = WX→Y (work done in _y→z is zero as the process is isochoric)

For O.S:

X + 0 + 2(-1) = 1

X = 3

Coordination number is the number of molecules linked to the central atom.

Hence B is the correct answer.

Structure (a) = structure (c) and, structure (b) = structure (d)

α-carbon is achiral, hence retention of configuration at β-carbon.

Both CH₃S^- and I^- are weak bases but strong nucleophiles.

All alcohols react (1°, 2° and 3°) with cerric nitrate and a colour change from yellow to red is observed.

To determine the correct statement regarding the alcohol X with the molecular formula C66​H121​2O, we need to consider the clues given:

1. Immediate turbidity with cold, concentrated HCl without ZnCl₂: This suggests that the alcohol is a tertiary alcohol. Tertiary alcohols react immediately with Lucas reagent (conc. HCl + ZnCl₂), but even in the absence of ZnCl₂​, they can form a stable carbocation leading to turbidity.

2. Obtained by treatment of an ether with CH₃​MgBr followed by acid hydrolysis: This indicates that the ether must be symmetrical or such that it results in the formation of a tertiary alcohol upon Grignard reaction.

Given these conditions, let's evaluate the options:

1. 3-methyl-3-pentanol:

   • Structure: CH₃​-CH₂​-C(CH₃​)OH-CH₂​-CH₃​
   • This is a tertiary alcohol (immediate turbidity with HCl).
   • This alcohol can be formed from the ether 3-methyl-3-pentyl ether by Grignard reaction with CH₃​MgBr.

2. 2-methyl-3-pentanol:

   • Structure: CH₃​-CH₂​-CH(OH)-CH₂​-CH₃
   • This is a secondary alcohol (slow reaction with HCl in the presence of ZnCl₂).

3. 2-methyl-2-pentanol:

   • Structure: CH₃​-C(CH₃​)OH-CH₂​-CH₃​
   • This is a tertiary alcohol (immediate turbidity with HCl).
   • This alcohol can also be formed from the ether 2-methyl-2-pentyl ether by Grignard reaction with CH₃​MgBr.

Since we are looking for a tertiary alcohol that gives immediate turbidity with HCl, and can be formed by treating an ether with CH₃​MgBr followed by acid hydrolysis, the correct answers are: 3-methyl-3-pentanol and 2-methyl-2-pentanol

Therefore, the correct statement regarding X is:

Either (b) or (d) (2-methyl-3-pentanol is a mistake in the options; the correct pair is either 3-methyl-3-pentanol or 2-methyl-2-pentanol).

Diazonium reacts with phenols and napthols to form dyes.

In pyridine EAS take splace at 3 position.

As mentioned in mechanism, reaction proceed via carbocation intermediate. Hence, alcohol forming most stable carbocation reacts most easily. Alcohol (c) forms aromatic (highly stable) carbocation, hence most reactive.

ZnCI₂ is a Lewis acid, helps in the form ation of carbocation intermediate, hence catalyse the reaction.

Tetracycline is a bacteriostatic antibiotic. Bactericidal antibiotics are antibiotics which can kill bacteria and Bacteria-static are which can inhibit the growth of bacteria. Ofloxacin is bactericidal antibiotic. Ofloxacin is a fluoroquinolone carboxylic acid antibacterial showing bactericidal effects by inhibition of DNA gyrase.

Paracetamol is N-(4-hydroxyphenyl) ethanamide, which is a hydroxy group containing compound.

Phenacetin is N-(4-ethoxyphenyl) ethanamide, which is an amide and ethoxy group containing compound.

Aspirin is 2-acetoxybenzoic acid, which is an ester.

Antibiotics can be classified as bactericidal and bacteriostatic on the basis of the effect, it has on microbes. Bactericidal drugs have killing/destroying effect on microbes while, bacteriostatic have inhibiting effect on microbes. A few examples of the two types of antibiotics are as follows: Bactericidals are Penicillin, Aminoglycosides, Ofloxacin. Bacteriostatics are Erythromycin, Tetracycline, Chloramphenicol.

Chloramphenicol is a broad spectrum antibiotic. Norethindrone is an antifertility drug. Omeprazol is an antacid and Diphenhydramine is an antihistamine mainly used to treat allergies.

Tartrazine impart colour, it is artificial edible colour. It is used generally for yellow colour in food. It is stable compound because it contains 6 membered aromatic ring in which four atoms are nitrogen atoms, and it's chemical formula is C₂H₂N₄.

LSD and mescaline are psychedelic drugs.
These produce visual and auditory hallucinations.

Ranitidine is antacid; amoxicillin is an antibiotic while diphenhydramine is an antihistamine.
Antiseptics and disinfectants are also the chemicals which either kill or prevent the growth of microorganisms. Antiseptics are applied to the living tissues such as wounds, cuts, ulcers and diseased skin surfaces.  Hydrogen peroxide, iodoform and soframycin act as antiseptics.

A− Aspartame

B− Saccharine

C− Sucralose

D− Alitame

(i) A & D give positive test with ninhydrin because both have free carboxylic and amine groups.
(ii) C form precipitate with AgNO₃ in the Lassaigne extract of the sugar because it has chlorine atoms.
(iii) B & D give positive test with sodium nitroprusside because both have sulphur atoms