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Test: Scope and Hoisting - 1 - Software Development MCQ


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15 Questions MCQ Test - Test: Scope and Hoisting - 1

Test: Scope and Hoisting - 1 for Software Development 2024 is part of Software Development preparation. The Test: Scope and Hoisting - 1 questions and answers have been prepared according to the Software Development exam syllabus.The Test: Scope and Hoisting - 1 MCQs are made for Software Development 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Scope and Hoisting - 1 below.
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Test: Scope and Hoisting - 1 - Question 1

What is the scope of a variable in JavaScript?

Detailed Solution for Test: Scope and Hoisting - 1 - Question 1

The scope of a variable determines where it is accessible within the program. It defines the region of code where a variable can be referenced.

Test: Scope and Hoisting - 1 - Question 2

What is the global scope in JavaScript?

Detailed Solution for Test: Scope and Hoisting - 1 - Question 2

The global scope in JavaScript refers to the scope that is accessible from anywhere in the program, including inside functions.

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Test: Scope and Hoisting - 1 - Question 3

Which keyword is used to declare a block-scoped variable in JavaScript?

Detailed Solution for Test: Scope and Hoisting - 1 - Question 3

The "let" keyword is used to declare block-scoped variables in JavaScript. Block scope means the variable is accessible only within the block it is defined in.

Test: Scope and Hoisting - 1 - Question 4

What is hoisting in JavaScript?

Detailed Solution for Test: Scope and Hoisting - 1 - Question 4

Hoisting is a JavaScript behavior where variable declarations are moved to the top of their scope during the compilation phase, allowing variables to be accessed before they are declared.

Test: Scope and Hoisting - 1 - Question 5

What is the difference between var and let in terms of hoisting?

Detailed Solution for Test: Scope and Hoisting - 1 - Question 5

Variables declared with var are hoisted to the top of their scope, allowing them to be accessed before they are declared. On the other hand, let variables are not hoisted and cannot be accessed before their declaration.

Test: Scope and Hoisting - 1 - Question 6

What is the output of the following code?
console.log(x);
var x = 5;

Detailed Solution for Test: Scope and Hoisting - 1 - Question 6

In JavaScript, variable declarations (not assignments) are hoisted to the top of their scope. So, the variable "x" is hoisted, but its value is not assigned at that point, resulting in the output "undefined".

Test: Scope and Hoisting - 1 - Question 7

What is the output of the following code?
function example() {
  console.log(x);
  var x = 10;
}
example();

Detailed Solution for Test: Scope and Hoisting - 1 - Question 7

Similar to the previous question, the variable "x" is hoisted to the top of the function scope. However, its value is not assigned until the line "var x = 10;" is reached, resulting in the output "undefined".

Test: Scope and Hoisting - 1 - Question 8

What is the output of the following code?
console.log(a);
let a = 7;

Detailed Solution for Test: Scope and Hoisting - 1 - Question 8

In this code, the variable "a" is declared using let, which is block-scoped. Since let variables are not hoisted, trying to access "a" before its declaration results in a ReferenceError.

Test: Scope and Hoisting - 1 - Question 9

What is the output of the following code?
function example() {
  console.log(a);
  let a = 3;
}
example();

Detailed Solution for Test: Scope and Hoisting - 1 - Question 9

This question is similar to the previous one. The variable "a" is declared using let, which is block-scoped. Accessing "a" before its declaration results in a ReferenceError.

Test: Scope and Hoisting - 1 - Question 10

What is the output of the following code?
var x = 5;
(function () {
  console.log(x);
  var x = 10;
})();

Detailed Solution for Test: Scope and Hoisting - 1 - Question 10

In this code, the variable "x" is declared and assigned a value of 5. Inside the immediately invoked function expression (IIFE), a new variable "x" is declared using var and assigned a value of 10. Since the scope of the IIFE is separate from the outer scope, the console.log inside the IIFE prints "undefined" because the local "x" overshadows the outer "x".

Test: Scope and Hoisting - 1 - Question 11

What will be the value of "result" after executing the following code?
var x = 2;
(function () {
  x = 5;
})();
var result = x * 3;

Detailed Solution for Test: Scope and Hoisting - 1 - Question 11

The variable "x" is initially assigned a value of 2. Inside the IIFE, the value of "x" is changed to 5. After the IIFE, the value of "x" is 5, and the multiplication "x * 3" gives the result of 15.

Test: Scope and Hoisting - 1 - Question 12

What is the value of "sum" after executing the following code?
var sum = 0;
for (var i = 0; i < 5; i++) {
  sum += i;
}
console.log(i);

Detailed Solution for Test: Scope and Hoisting - 1 - Question 12

The variable "sum" is initialized as 0. The "for" loop iterates from 0 to 4, adding each value of "i" to "sum". After the loop, the value of "i" is accessible outside the loop and is equal to 5.

Test: Scope and Hoisting - 1 - Question 13

What will be the output of the following code?

Detailed Solution for Test: Scope and Hoisting - 1 - Question 13

Inside the IIFE, a new variable "x" is declared and assigned a value of 10. This "x" is local to the IIFE and does not affect the outer "x" with a value of 5. Therefore, the first console.log outputs 10, and the second console.log outputs 5.

Test: Scope and Hoisting - 1 - Question 14

What is the output of the following code?
function outer() {
  var x = 1;
  function inner() {
    console.log(x);
  }
  x = 2;
  return inner;
}
var fn = outer();
fn();

Detailed Solution for Test: Scope and Hoisting - 1 - Question 14

The outer function "outer" has a variable "x" assigned a value of 1. Inside the function, an inner function "inner" is defined, which accesses and logs the value of "x". Before returning the inner function, the value of "x" is changed to 2. When the returned "fn" function is invoked, it outputs the value of "x", which is 2.

Test: Scope and Hoisting - 1 - Question 15

What is the value of "result" after executing the following code?
function multiplyByTwo(num) {
  var result = num * 2;
  return function () {
    console.log(result);
  };
}
var multiplyByTwoFn = multiplyByTwo(5);
multiplyByTwoFn();

Detailed Solution for Test: Scope and Hoisting - 1 - Question 15

The "multiplyByTwo" function takes a number and returns an anonymous function. The anonymous function logs the value of the "result" variable, which is the input number multiplied by 2. When "multiplyByTwoFn" is invoked, it calls the returned anonymous function and outputs the value of "result", which is 10.

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