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Test: Combinatorics - 2 - Software Development MCQ


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15 Questions MCQ Test - Test: Combinatorics - 2

Test: Combinatorics - 2 for Software Development 2025 is part of Software Development preparation. The Test: Combinatorics - 2 questions and answers have been prepared according to the Software Development exam syllabus.The Test: Combinatorics - 2 MCQs are made for Software Development 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Combinatorics - 2 below.
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Test: Combinatorics - 2 - Question 1

How many permutations are possible for a set of n elements?

Detailed Solution for Test: Combinatorics - 2 - Question 1

The number of permutations possible for a set of n elements is given by n!. It represents the factorial of n, which is the product of all positive integers from 1 to n.

Test: Combinatorics - 2 - Question 2

In how many ways can you arrange the letters in the word "COMBINATORICS"?

Detailed Solution for Test: Combinatorics - 2 - Question 2

The word "COMBINATORICS" has 12 letters. To find the number of ways to arrange these letters, we calculate 12!.

Test: Combinatorics - 2 - Question 3

How many different 3-digit numbers can be formed using the digits 1, 2, 3, 4, 5 without repetition?

Detailed Solution for Test: Combinatorics - 2 - Question 3

We have 5 digits to choose from, and we need to form a 3-digit number without repetition. The number of ways to do this is given by 5P3 = 5! / (5 - 3)! = 5! / 2! = 60 / 2 = 120.

Test: Combinatorics - 2 - Question 4

How many subsets can be formed from a set with n elements?

Detailed Solution for Test: Combinatorics - 2 - Question 4

The number of subsets that can be formed from a set with n elements is 2^n. Each element in the set has two choices: either it can be included in a subset or not.

Test: Combinatorics - 2 - Question 5

How many ways can you choose a president, vice president, and treasurer from a group of 10 people?

Detailed Solution for Test: Combinatorics - 2 - Question 5

To choose a president, vice president, and treasurer, we have 10 choices for the president, then 9 choices for the vice president (after the president is chosen), and 8 choices for the treasurer (after the president and vice president are chosen). The total number of ways is 10 * 9 * 8 = 720.

Test: Combinatorics - 2 - Question 6

What will be the output of the following code?
#include <iostream>
using namespace std;

int main() {
   int n = 5;
   int result = 1;
   
   for (int i = n; i >= 1; i--) {
       result *= i;
   }
   
   cout << result << endl;
   
   return 0;
}

Detailed Solution for Test: Combinatorics - 2 - Question 6

The code calculates the factorial of the number 5. It initializes the variable "result" to 1 and then multiplies it with each number from 5 to 1. The final value of "result" is 5 * 4 * 3 * 2 * 1 = 120.

Test: Combinatorics - 2 - Question 7

What will be the output of the following code?

#include <iostream>
using namespace std;

int main() {
   int n = 4;
   int result = 1;
   
   for (int i = 1; i <= n; i++) {
       result *= i;
   }
   
   cout << result << endl;
   
   return 0;
}

Detailed Solution for Test: Combinatorics - 2 - Question 7

The code calculates the factorial of the number 4. It initializes the variable "result" to 1 and then multiplies it with each number from 1 to 4. The final value of "result" is 1 * 2 * 3 * 4 = 24.

Test: Combinatorics - 2 - Question 8

What will be the output of the following code?
#include <iostream>
using namespace std;

int main() {
   int n = 6;
   int r = 3;
   int result = 1;
   
   for (int i = n; i >= n - r + 1; i--) {
       result *= i;
   }
   
   cout << result << endl;
   
   return 0;
}

Detailed Solution for Test: Combinatorics - 2 - Question 8

The code calculates the value of nPr (n permutation r) for n = 6 and r = 3. It initializes the variable "result" to 1 and then multiplies it with each number from 6 to 4. The final value of "result" is 6 * 5 * 4 = 120.

Test: Combinatorics - 2 - Question 9

What will be the output of the following code?
#include <iostream>
using namespace std;

int main() {
   int n = 5;
   int r = 2;
   int result = 1;
   
   for (int i = n; i >= n - r + 1; i--) {
       result *= i;
   }
   
   cout << result << endl;
   
   return 0;
}

Detailed Solution for Test: Combinatorics - 2 - Question 9

The code calculates the value of nPr (n permutation r) for n = 5 and r = 2. It initializes the variable "result" to 1 and then multiplies it with each number from 5 to 4. The final value of "result" is 5 * 4 = 20.

Test: Combinatorics - 2 - Question 10

What will be the output of the following code?
#include <iostream>
using namespace std;

int main() {
   int n = 5;
   int r = 3;
   int result = 1;
   
   for (int i = 1; i <= r; i++) {
       result *= n;
       n--;
   }
   
   cout << result << endl;
   
   return 0;
}

Detailed Solution for Test: Combinatorics - 2 - Question 10

The code calculates the value of nPr (n permutation r) using a different approach. It initializes the variable "result" to 1 and then multiplies it with n in each iteration, decreasing n by 1. The final value of "result" is 5 * 4 * 3 = 60.

Test: Combinatorics - 2 - Question 11

Consider the following problem: "Given a string of lowercase English letters, count the number of substrings that start and end with the same letter." What will be the output for the input "aba"?

Detailed Solution for Test: Combinatorics - 2 - Question 11

The substrings that start and end with the same letter in "aba" are "a", "b", and "aba".

Test: Combinatorics - 2 - Question 12

Ayoub's function is defined as follows:
int Ayoub(int n) {
    if (n == 1) {
        return 1;
    }
    return Ayoub(n - 1) + n;
}
What will be the output of Ayoub(4)?

Detailed Solution for Test: Combinatorics - 2 - Question 12

Ayoub(4) will recursively call Ayoub(3), Ayoub(2), and Ayoub(1). The function returns 1 for Ayoub(1). Therefore, the sum will be 1 + 2 + 3 + 4 = 10.

Test: Combinatorics - 2 - Question 13

The inverse factorial function is defined as follows:
int inverseFactorial(int x) {
    int fact = 1;
    int i = 1;
    while (fact < x) {
        i++;
        fact *= i;
    }
    if (fact == x) {
        return i;
    } else {
        return -1;
    }
}
What will be the output of inverseFactorial(120)?

Detailed Solution for Test: Combinatorics - 2 - Question 13

The inverseFactorial function finds the value of i such that i! is equal to the input x. In this case, 5! = 120, so the function will return i = 5.

Test: Combinatorics - 2 - Question 14

Consider the following problem: "There is a parking lot with n parking spaces. You can park your car in any vacant spot, but you cannot park next to another car. How many ways are there to park your car in the lot?" What will be the output for the input n = 3?

Detailed Solution for Test: Combinatorics - 2 - Question 14

For n = 3, there are two possible ways to park the car without parking next to another car: (1) _ _ _ and (2) _ _ _. Therefore, the output is 2.

Test: Combinatorics - 2 - Question 15

The Super Pow function is defined as follows:
int superPow(int a, vector<int>& b) {
    int result = 1;
    int mod = 1337;
    for (int i = 0; i < b.size(); i++) {
        result = (pow(result, 10) % mod * pow(a, b[i]) % mod) % mod;
    }
    return result;
}
What will be the output of superPow(2, {1, 0})?

Detailed Solution for Test: Combinatorics - 2 - Question 15

The superPow function calculates the result of a^b[i] for each element in b and performs modular arithmetic. In this case, 2^1 % 1337 = 2.

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