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Test: Physics - 2 - MCAT MCQ


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15 Questions MCQ Test - Test: Physics - 2

Test: Physics - 2 for MCAT 2024 is part of MCAT preparation. The Test: Physics - 2 questions and answers have been prepared according to the MCAT exam syllabus.The Test: Physics - 2 MCQs are made for MCAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Physics - 2 below.
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Test: Physics - 2 - Question 1

Force acting on an object is given as
F = Xx-1(Where x is the distance by which the body is displaced due to the applied force)
Q. What would be the dimensional formula for X?

Detailed Solution for Test: Physics - 2 - Question 1

From dimensional analysis we know that dimensional formula of the left hand side of an expression should be the same as the dimensional formula of the individual quantities on the right hand side. Force has the SI unit of kgms-2 . Therefore, the dimensional formula of force becomes MLT-2. Dimensional formula of x is L. Hence, dimensional formula of x-1 becomes L-1. As said earlier, Xx1 should have the same dimensional formula as F. Therefore, it can be written as MLT-2 = X * L-1
X = ML2T-2
Therefore, E is the correct answer option.

Test: Physics - 2 - Question 2

If a block of wood weighs 1000 N, what would be its mass?

Detailed Solution for Test: Physics - 2 - Question 2

Weight of a body is given as
W = mg -------------- (1)
Putting the value of W and g in equation 1 we get
1000 = m x 9.8 m
= 102.04 kg
Therefore, A is the correct answer option.

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Test: Physics - 2 - Question 3

If a wheel is rotating with an angular velocity of 2.5 rad/s, what is the time taken by the wheel to complete one full rotation?

Detailed Solution for Test: Physics - 2 - Question 3

Time taken to complete one rotation is known as time period.
Angular velocity is related to time period as
ω = 2π/T ---------------- (1)
Putting the values of (π = 3.14) and ω in equation 1 we get
2.5 = (2 x 3.14)/T
T = 2.51 s
Therefore, B is the correct answer option.

Test: Physics - 2 - Question 4

A block of mass M, connected to a spring of spring constant k (a spring-mass system), is executing SHM with time period, T on Earth. If the same system executes SHM on the surface of Moon, what will be the new time period?

Detailed Solution for Test: Physics - 2 - Question 4

Time period is given as
 = 2π √(M/k) ---------------- (1)
At the surface of the Moon, acceleration due to gravity is (1/6)th of that on the surface of the Earth. As, there is no term related to acceleration due to gravity in equation 1, time period of the system will remain unaffected. Hence, time period of the system on the moon will be the same as that of the system on the Earth.
Therefore, C is the correct answer option.

Test: Physics - 2 - Question 5

What would be the specific gravity of a fluid having density of 944 kg/m3?

Detailed Solution for Test: Physics - 2 - Question 5

Specific gravity is a dimensionless quantity and is given as
SG = ρfluid/ ρwater ---------------- (1)
It is quite obvious from equation 1 that specific gravity is a unit less quantity.
Putting the values of densities in equation 1 we get
SG = 944 / 1000 Or SG = 0.944
herefore, C is the correct answer option.

Test: Physics - 2 - Question 6

What is the dipole moment between an electron and a proton separated by a distance of 1 nm?

Detailed Solution for Test: Physics - 2 - Question 6

Electric dipole moment between two charges of opposite polarity is given as
p = Qd ----------- (1)
The distance is in nm so we need to convert it into m. 1 nm = 10-9 m
Putting the values in equation 1 we get
P = 1.6 × 10-19 × 10-9
Or, 1.6 × 10-28 Cm
Hence, D is the correct answer option.

Test: Physics - 2 - Question 7

A long straight conductor carries a current of 2 A. What would be the magnetic field at a distance of 0.05 m from the axis of the conductor? (Permeability of free space is 4π × 10-7 WbA-1m-1 )

Detailed Solution for Test: Physics - 2 - Question 7

Magnetic field due toalong straight conductor is given as
B = [(μ0/4π)(2I/a)] -------------- (1)
Putting the values in equation 1 we get
B = (4π × 10-7 / 4π) x (2 x  2 / 0.05) B
= 8 × 10-6 T
Hence, A is the correct answer option.

Test: Physics - 2 - Question 8

Work function of Nickel is 5.01 eV. What is the threshold frequency for Nickel? (Planck’s constant = 6.6 × 10-34 Js)

Detailed Solution for Test: Physics - 2 - Question 8

Threshold frequency is the minimum frequency required to eject photoelectrons out of a material in photoelectric effect.
It is given as Φ = hvo -------------- (1)
Work function is given in eV.
So, we need to convert it into Joules.
1 eV = 1.6 x 10-19 J
5.01 eV = 8.02 x 10-19 J
Putting the values in equation 1 we get
8.02 x 10-19 = 6.6 x 10-34 x vo
vo = 1.21 × 1015 Hz
Therefore, A is the correct answer option.

Test: Physics - 2 - Question 9

Consider the figure and the statements given below.


(v is velocity and t is time)
The graph is for a body that is accelerating.
The graph is for a body that is falling freely.
The graph is for a body that has constant velocity.

Q. Which of the following statement(s) is true in accordance to the given figure?

Detailed Solution for Test: Physics - 2 - Question 9

The graph given in the question is between velocity and time. Slope of the velocity time graph is linear here. Therefore, velocity increases with each instant but change in velocity per unit time is constant throughout the travel. Thus, 3 is an incorrect statement and so is option C. Acceleration of a body is defined as the rate of change of velocity per unit time. As said earlier, for a linear slope between velocity and time, change in velocity is constant per unit time and thus, acceleration is constant for the entire travel. Therefore, statement 1 isincorrect and so is option B. A body falls freely under gravity only. A free falling body always experiences uniform acceleration throughout the travel. Thus, we can say that acceleration is constant for a free fall and the graph essentially represents the motion of free fall. Thus, statement 2 is correct and so A is the correct answer option. In view of the above discussion, options D and E are incorrect as well.

Test: Physics - 2 - Question 10

A force of 25 N is acting along the North direction and a force of 12 N is acting along the South direction on a body of mass 1.5 kg. What acceleration will the force bring in the body?

Detailed Solution for Test: Physics - 2 - Question 10

A body undergoes acceleration due to an unbalanced force. The unbalanced force here is given as
F = 25 - 12 Or F = 13N
According to Newton’s second law of motion
F = ma -------------- (1)
13 = 1.5 x a
a = 8.67 m/s2
Therefore, E is the correct answer option.

Test: Physics - 2 - Question 11

An object is to be lifted from the ground to a height of 5m in 25 seconds. If the energy consumed during the process is 2000 J, what is the power required?

Detailed Solution for Test: Physics - 2 - Question 11

Power is given as
P = W/t ---------------- (1)
Putting the values in equation 1 we get
P = 2000 / 25
P = 80 J/s or Watt
Hence, C is the correct answer option.

Test: Physics - 2 - Question 12

If the speeds of sound in solid, liquid and gas are arranged in increasing order, which of the following is a correct arrangement?

Detailed Solution for Test: Physics - 2 - Question 12

Thespeed of sound in solids like steel and iron is 5000 m/s and 5130 m/s.The speed of sound in liquidslike water at 0o C and 20o C is 1402 m/s and 1482 m/srespectively. The speed of sound in air (gas)at 0o C and 20o C is 331.5 m/s and 344 m/srespectively. Thus, from the above discussion it can be concluded that the speed of sound in solids is more than that in liquids and air. Therefore,thecorrect arrangementfor speeds of soundis air (gas) < liquids < solids. Thus, C is the correct answer option.

Test: Physics - 2 - Question 13

A sample of gas at 313 K occupies a volume of 10 m3. What would be its volume at 373 K?

Detailed Solution for Test: Physics - 2 - Question 13

This question can be solved by applying Charles’s law, which is given as
V1/ T1 = V2/ T2 -------------- (1)
Putting the values in equation 1 we get
10/313 = V2/373
V2 = 11.92 m3
Therefore, A is the correct answer option.

Test: Physics - 2 - Question 14

For a conductor having a cross section of 2 × 10-4 m2, average drift velocity of the electrons flowing through it is 10-3 m/s . If the density of free electrons in the conductor is 6 × 10-24 m-3, what is the current flowing through the conductor? (Charge on electron = 1.6 × 10-19 C)

Detailed Solution for Test: Physics - 2 - Question 14

Current flowing through the conductor is given as
I = neAvd --------------- (1)
Putting the values in equation 1 we get
I = 6 × 1024 1.6 × 10-19 × 2 × 10-4 × 10-3
I = 0.19A
Hence, E is the correct answer option.

Test: Physics - 2 - Question 15

A small water drop on a surface is viewed through a glass. If the real depth of the water drop is 15 cm, what will be the apparent depth of the water drop? (Refractive index of glass =1.5 and refractive index of air = 1)

Detailed Solution for Test: Physics - 2 - Question 15

The apparent depth is given as
glassμair = μglass / μair = real depth/ apparent depth ---------------- (1)
Putting the values in equation 1 we get
1.5/1 = 15 cm / apparent depth
apparent depth = 10 cm
Hence, E is the correct answer option.

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