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JAMB Exam  >  JAMB Tests  >  Test: Variation - 2 - JAMB MCQ

Test: Variation - 2 - JAMB MCQ


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10 Questions MCQ Test - Test: Variation - 2

Test: Variation - 2 for JAMB 2024 is part of JAMB preparation. The Test: Variation - 2 questions and answers have been prepared according to the JAMB exam syllabus.The Test: Variation - 2 MCQs are made for JAMB 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Variation - 2 below.
Solutions of Test: Variation - 2 questions in English are available as part of our course for JAMB & Test: Variation - 2 solutions in Hindi for JAMB course. Download more important topics, notes, lectures and mock test series for JAMB Exam by signing up for free. Attempt Test: Variation - 2 | 10 questions in 8 minutes | Mock test for JAMB preparation | Free important questions MCQ to study for JAMB Exam | Download free PDF with solutions
Test: Variation - 2 - Question 1
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If y varies directly with x and y = 10 when x = 5, what is the value of y when x = 8?

Detailed Solution for Test: Variation - 2 - Question 1

Since y varies directly with x, we can use the formula y = kx, where k is the constant of variation. To find k, we can use the given values: 10 = k * 5, which gives us k = 2. Now, we can substitute x = 8 into the formula to find y: y = 2 * 8 = 16.

Test: Variation - 2 - Question 2
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If y varies inversely with the square of x and y = 6 when x = 2, what is the value of y when x = 4?

Detailed Solution for Test: Variation - 2 - Question 2

If y varies inversely with the square of x, we can use the formula y = k/x2, where k is the constant of variation. To find k, we can use the given values: 6 = k/(22), which gives us k = 24. Now, we can substitute x = 4 into the formula to find y: y = 24/(42) = 3.

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Test: Variation - 2 - Question 3
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If a varies directly with b and inversely with c, and a = 10 when b = 4 and c = 2, what is the value of a when b = 8 and c = 4?

Detailed Solution for Test: Variation - 2 - Question 3

Since a varies directly with b and inversely with c, we can use the formula a = (k * b) / c, where k is the constant of variation. To find k, we can use the given values: 10 = (k * 4) / 2, which gives us k = 5. Now, we can substitute b = 8 and c = 4 into the formula to find a: a = (5 * 8) / 4 = 20.

Test: Variation - 2 - Question 4
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If y varies directly as the square of x and y = 25 when x = 5, what is the value of y when x = 10?
Detailed Solution for Test: Variation - 2 - Question 4

Since y varies directly as the square of x, we can use the formula y = kx2, where k is the constant of variation. To find k, we can use the given values: 25 = k * 52, which gives us k = 1. Now, we can substitute x = 10 into the formula to find y: y = 1 * 102 = 100.

Test: Variation - 2 - Question 5
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If y varies directly as the cube of x and y = 64 when x = 2, what is the value of y when x = 3?
Detailed Solution for Test: Variation - 2 - Question 5

Since y varies directly as the cube of x, we can use the formula y = kx3, where k is the constant of variation. To find k, we can use the given values: 64 = k * 23, which gives us k = 4. Now, we can substitute x = 3 into the formula to find y: y = 4 * 33 = 72.

Test: Variation - 2 - Question 6
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If y varies inversely with x and y = 15 when x = 5, what is the value of y when x = 10?
Detailed Solution for Test: Variation - 2 - Question 6

If y varies inversely with x, we can use the formula y = k/x, where k is the constant of variation. To find k, we can use the given values: 15 = k/5, which gives us k = 75. Now, we can substitute x = 10 into the formula to find y: y = 75/10 = 7.5.

Test: Variation - 2 - Question 7
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If y varies directly as the square root of x and y = 4 when x = 16, what is the value of y when x = 9?
Detailed Solution for Test: Variation - 2 - Question 7

Since y varies directly as the square root of x, we can use the formula y = k√x, where k is the constant of variation. To find k, we can use the given values: 4 = k√16, which gives us k = 1. Now, we can substitute x = 9 into the formula to find y: y = 1√9 = 3.

Test: Variation - 2 - Question 8
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If y varies directly as the cube root of x and y = 10 when x = 27, what is the value of y when x = 64?
Detailed Solution for Test: Variation - 2 - Question 8

Since y varies directly as the cube root of x, we can use the formula y = k∛x, where k is the constant of variation. To find k, we can use the given values: 10 = k∛27, which gives us k = 10/3. Now, we can substitute x = 64 into the formula to find y: y = (10/3)∛64 ≈ 15.

Test: Variation - 2 - Question 9
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If y varies inversely with the cube root of x and y = 20 when x = 8, what is the value of y when x = 27?
Detailed Solution for Test: Variation - 2 - Question 9

If y varies inversely with the cube root of x, we can use the formula y = k/∛x, where k is the constant of variation. To find k, we can use the given values: 20 = k/∛8, which gives us k = 20∛8. Now, we can substitute x = 27 into the formula to find y: y = (20∛8)/∛27 ≈ 10.

Test: Variation - 2 - Question 10
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If y varies directly with x and inversely with z, and y = 12 when x = 4 and z = 3, what is the value of y when x = 8 and z = 6?
Detailed Solution for Test: Variation - 2 - Question 10

Since y varies directly with x and inversely with z, we can use the formula y = (k * x) / z, where k is the constant of variation. To find k, we can use the given values: 12 = (k * 4) / 3, which gives us k = 9. Now, we can substitute x = 8 and z = 6 into the formula to find y: y = (9 * 8) / 6 = 12.

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