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Test: ESE Electrical - 4 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test - Test: ESE Electrical - 4

Test: ESE Electrical - 4 for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: ESE Electrical - 4 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: ESE Electrical - 4 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: ESE Electrical - 4 below.
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Test: ESE Electrical - 4 - Question 1

 For the circuit shown below, the current through the 1 Ω resistor is

Detailed Solution for Test: ESE Electrical - 4 - Question 1

Using source transformation, the current source is converted to a voltage source as shown below.

Applying nodal analysis at node (x), we get 

Test: ESE Electrical - 4 - Question 2

 The value of V in volts for the circuit shown below is

Detailed Solution for Test: ESE Electrical - 4 - Question 2

The equivalent resistance across the 5 A current source is

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Test: ESE Electrical - 4 - Question 3

The value of dependent source for the circuit shown below is

Detailed Solution for Test: ESE Electrical - 4 - Question 3

Applying KVL in the loop,
5 = 2i — 2i + i or i = 5 A
∴ Value of dependent source
= 2i = 2 x 5 = 10 volt

Test: ESE Electrical - 4 - Question 4

The circuit shown in fig is in steady state with switch open. At t = 0 the switch is closed. Theoutput voltage vt (c) for t > 0 is

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Test: ESE Electrical - 4 - Question 5

The switch of the circuit shown in fig. is opened at t = 0 after long time. The v(t) , for t > 0 is

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A2 = -4

Test: ESE Electrical - 4 - Question 6

In the circuit of fig.the switch is opened at t = 0 after long time. The current iL(t) for t > 0 is

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Test: ESE Electrical - 4 - Question 7

The circuit is as shown in fig

i2(t) = ?

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Test: ESE Electrical - 4 - Question 8

The y-parameters of a 2-port network are 

A resistor of 1 ohm is connected across as shown in fig. The new y –parameter would be

  ​ ​ ​

Detailed Solution for Test: ESE Electrical - 4 - Question 8

y-parameter of 1Ω resistor network are

New y-parameter

Test: ESE Electrical - 4 - Question 9

A three-phase balanced delta connected load of (4 + j8) Ω is connected across a 400V, 3 – Ø balanced supply. Determine the phase current IR. Assume the phase sequence to be RYB.

Detailed Solution for Test: ESE Electrical - 4 - Question 9

Taking the line voltage VRY = V∠0⁰ as a reference VRY = 400∠0⁰V, VYB = 400 ∠ -120 ⁰V and VBR = 400∠-240⁰V. Impedance per phase = (4 + j8) Ω = 8.94∠63.4⁰Ω. Phase current IR = (400∠0o)/(8.94∠63.4o )= 44.74 ∠ -63.4⁰A.

Test: ESE Electrical - 4 - Question 10

The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Find the line current I3.

Detailed Solution for Test: ESE Electrical - 4 - Question 10

The line current I3 is the difference of IB and IY. So the line current I3 is I3 = IB – IY = (-24.646 - j20) A.

Test: ESE Electrical - 4 - Question 11

Find the force of interaction between 60 stat coulomb and 37.5 stat coulomb spaced 7.5cm apart in transformer oil(εr=2.2) in 10-4 N,

Detailed Solution for Test: ESE Electrical - 4 - Question 11

1 stat coulomb = 1/(3 X 109) C
F = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2)2)
= 1.815 X 10-4 N.

Test: ESE Electrical - 4 - Question 12

Find the force between two charges when they are brought in contact and separated by 4cm apart, charges are 2nC and -1nC, in μN.

Detailed Solution for Test: ESE Electrical - 4 - Question 12

Before the charges are brought into contact, F = 11.234 μN.
After charges are brought into contact and then separated, charge on each sphere is, (q1 + q2)/2 = 0.5nC
On calculating the force with q1 = q2 = 0.5nC, F = 1.404μN.

Test: ESE Electrical - 4 - Question 13

What is the width of the main lobe of the frequency response of a rectangular window of length M-1?

Detailed Solution for Test: ESE Electrical - 4 - Question 13

The width of the main lobe width is measured to the first zero of W(ω)) is 4π/M.

Test: ESE Electrical - 4 - Question 14

Which of the following windows has a time domain sequence   

Detailed Solution for Test: ESE Electrical - 4 - Question 14

Explanation: The Bartlett window which is also called as triangular window has a time domain sequence as
, 0≤n≤M-1.

Test: ESE Electrical - 4 - Question 15

f a signal f(t) has energy ‘E’ the energy of the signal f(2t) is equal to:

Detailed Solution for Test: ESE Electrical - 4 - Question 15


and 

⇒  

Test: ESE Electrical - 4 - Question 16

A function f(t) is an even function, if for all values of (t)
(T is the time-period of the function)

Detailed Solution for Test: ESE Electrical - 4 - Question 16

For even function, f(t) = f(-t)

For odd function, f(t) = -f(-t)

Test: ESE Electrical - 4 - Question 17

The transfer function of a system is given as

The h[n] is

Detailed Solution for Test: ESE Electrical - 4 - Question 17

So system is both stable and causal. ROC includes z = 1.

Test: ESE Electrical - 4 - Question 18

The transfer function of a system is given as

Consider the two statements

Statement(i) : System is causal and stable.
Statement(ii) : Inverse system is causal and stable.

The correct option is:

Detailed Solution for Test: ESE Electrical - 4 - Question 18

For this system and inverse system all poles are inside |z| = 1. So both system are both causal and stable.

Test: ESE Electrical - 4 - Question 19

Determine the bilateral laplace transform and choose correct option

​ ​ ​

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Test: ESE Electrical - 4 - Question 20

Determine the bilateral laplace transform and choose correct option.

x(t) = u(-t + 3)

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Test: ESE Electrical - 4 - Question 21

Determine the Fourier series coefficient for given periodic signal x(t) is

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Test: ESE Electrical - 4 - Question 22

Consider the three continuous time signals with fundamental period of T = 1/2
x(t) = cos4πt
y(t) = sin 4πt
z(t) = x(t)·y(t)

The Fourier co-efficient of z(t) are given by

Detailed Solution for Test: ESE Electrical - 4 - Question 22


Test: ESE Electrical - 4 - Question 23

In the question, the FS coefficient of time-domain signal have been given. Determine the corresponding time domain signal and choose correct option.

Detailed Solution for Test: ESE Electrical - 4 - Question 23

 
= 2(cos 6πt - sin 2πt)

Test: ESE Electrical - 4 - Question 24

Consider the signal x(t) = cos(6πt) + sin(8πt), where t is in seconds. The Nyquist sampling rate (in samples/second) for the signal y(t) = x(2t + 5) is

Detailed Solution for Test: ESE Electrical - 4 - Question 24

Given,
x(t) = cos(6πt) + sin(8πt)
The bandwidth of the signal will be:

Now, y(t) = x(2t + 5) can be written as:

Taking the Fourier transform, we get:

Thus, the frequency spectrum of X(jω)  expands by 2.
This will make the highest frequency component of Y(jω) as:
2 × 4 = 8 Hz 
Hence, the Nyquist rate will be:
fs = 2 × 8 = 16 samples/sec

Test: ESE Electrical - 4 - Question 25

The Laplace transform of unity function is

Detailed Solution for Test: ESE Electrical - 4 - Question 25

The laplace transform of unity function i.e.

Test: ESE Electrical - 4 - Question 26

The poles of the transfer function C(s)/R(s) of the system represented by the block diagram shown below are located at 
 

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The given block diagram can be reduced as shown below.

Test: ESE Electrical - 4 - Question 27

Damping ratio is defined as the ratio of

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Test: ESE Electrical - 4 - Question 28

The characteristic equation of a servo system is given by 
a0s4 + a1s3 + a2s2 + a3s + a4 = 0
Now, consider the following conditions required to be satisfied by the coefficient of the above characteristic equation for the system to be stable:
1. a1 > 0 and a4 > 0
2. a1 < 0 and a4 > 0
3. a1a2< a0a3
4. a1a2 > a0a
5. 
6. 
Which of the above conditions holds true for the given system to be stable?

Detailed Solution for Test: ESE Electrical - 4 - Question 28

The Rouths array is formed as follows:

For the system to be stable, there should not be any sign change in the first column of Routh’s array.

Hence, above conditions must hold for the given system to be stable.

Test: ESE Electrical - 4 - Question 29

The open-loop transfer function of a closed loop control system is given as:

Which of the following statements is correct about the root locus of the above system?

Detailed Solution for Test: ESE Electrical - 4 - Question 29


Number of branches terminating at infinity = 3 = P - Z.
Number of branches terminating at zero = Z= 0.
Poles are at s = 0 and s = -3 ± j1.

Since, three number of poles have to terminate at infinity, therefore the two complex poles will terminate at infinity due to which there will be intersection of root locus branches with jω-axis. Now, characteristic equation is

Test: ESE Electrical - 4 - Question 30

For a control system having gain margin of -10 dB, the magnitude of GH(s) for 180° phase shift is

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