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CA Foundation Exam  >  CA Foundation Tests  >  Test: Ratio And Proportion, Indices, Logarithms - 2 - CA Foundation MCQ

Test: Ratio And Proportion, Indices, Logarithms - 2 - CA Foundation MCQ


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30 Questions MCQ Test - Test: Ratio And Proportion, Indices, Logarithms - 2

Test: Ratio And Proportion, Indices, Logarithms - 2 for CA Foundation 2024 is part of CA Foundation preparation. The Test: Ratio And Proportion, Indices, Logarithms - 2 questions and answers have been prepared according to the CA Foundation exam syllabus.The Test: Ratio And Proportion, Indices, Logarithms - 2 MCQs are made for CA Foundation 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Ratio And Proportion, Indices, Logarithms - 2 below.
Solutions of Test: Ratio And Proportion, Indices, Logarithms - 2 questions in English are available as part of our course for CA Foundation & Test: Ratio And Proportion, Indices, Logarithms - 2 solutions in Hindi for CA Foundation course. Download more important topics, notes, lectures and mock test series for CA Foundation Exam by signing up for free. Attempt Test: Ratio And Proportion, Indices, Logarithms - 2 | 40 questions in 40 minutes | Mock test for CA Foundation preparation | Free important questions MCQ to study for CA Foundation Exam | Download free PDF with solutions
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 1
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Division of Rs. 750 into 3 parts in the ratio 4 : 5 : 6 is

Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 2
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The sum of the ages of 3 persons is 150 years. 10 years ago their ages were in the ratio 7 : 8 : 9. Their present ages are

Detailed Solution for Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 2

their 10years ago age be 7x,8x,9x
so their current age be 7x+10,8x+10,9x+10
7x+10+8x+10+9x+10=120
24x+30=150
24x=120
x=5
present age= 7x+10,8x+10,9x+10
                   =7(5)+10,8(5)+10,9(5)+10
                   =45,50,55

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Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 3
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The numbers 14, 16, 35, 42 are not in proportion. The fourth term for which they will be in proportion is

Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 4
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If x/y = z/w, implies y/x = w/z, then the process is called
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 5
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If p/q = r/s = p–r/q–s, the process is called
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 6
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If a/b = c/d, implies (a+b)/(a–b) = (c+d)/(c–d), the process is called
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 7
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If u/v = w/p, then (u–v)/(u+v) = (w–p)/(w+p). The process is called
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 8
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12, 16, x, 20 are in proportion. Then find x
Detailed Solution for Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 8

Concept used:

If given a : b : : x : c

then x is called the third proportion.

It can be calculated as,

a/b = x/c

⇒ x = ac/b

Calculations:

12 : 16 : : x : 20

then,

x = (12 × 20)/16

⇒ x = 15

∴ third proportion = 30

 

Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 9
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4, *, 9, 13½ are in proportion. Then * is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 10
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The mean proportional between 1.4 gms and 5.6 gms is
Detailed Solution for Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 10

Let 1.4 gms, x gms and 5.6 gms be in continuous proportion.

(Mean proportional terms)^2 = Product of extremes.

Therefore x^2 = 1.4 x 5.6

therefore x^2 = 7.84

therefore x= 2.8 gms.

Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 11
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Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 12
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Two numbers are in the ratio 3 : 4; if 6 be added to each terms of the ratio, then the new ratio will be 4 : 5, then the numbers are
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 13
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Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 14
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Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
Detailed Solution for Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 14

Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 15
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if  then  (b-c)x + (c-a)y+(a-b)z is 
Detailed Solution for Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 15

Let X=(b+c-a);y=(c+a-b);z=(a+b-c)

=(b-c)(b+c-a)+(c-a)(c+a-b)+(a-b)(a+b-c)

=b^2-c^2-ab+ac+c^2-a^2-bc+ab+a^2-b^2-ac+bc

=0

Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 16
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4x–1/4 is expressed as
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 17
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The value of 81/3 is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 18
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The value of 2 × (32) 1/5 is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 19
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The value of 4/(32)1/5 is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 20
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The value of (8/27)1/3 is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 21
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2½ .4¾ is equal to
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 22
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 has simplified value equal to 
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 23
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xa–b × xb–c × xc–a is equal to
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 24
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The value of  is equal to 
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 25
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{(33)2 × (42)3 × (53)2} / {(32)3 × (43)2 × (52)3} is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 26
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Which is True ?
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 27
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If x1/p = y1/q = z1/r and xyz = 1, then the value of p+q+r is
Detailed Solution for Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 27

x1/p=y1/q=z1/r=k (say)

⇒ x = kp,y = kq,z = kr

xyz=1 (given)

kp.kq.kr=1

k(p+q+r)=1.

k(p+q+r)=k0

p+q+r = 0

Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 28
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The value of ya–b × yb–c × yc–a × y–a–b is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 29
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The True option is
Test: Ratio And Proportion, Indices, Logarithms - 2 - Question 30
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The simplified value of 16x–3y2 × 8–1x3y–2 is
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