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DSSSB PGT Physics Mock Test - 3 - DSSSB TGT/PGT/PRT MCQ


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30 Questions MCQ Test - DSSSB PGT Physics Mock Test - 3

DSSSB PGT Physics Mock Test - 3 for DSSSB TGT/PGT/PRT 2024 is part of DSSSB TGT/PGT/PRT preparation. The DSSSB PGT Physics Mock Test - 3 questions and answers have been prepared according to the DSSSB TGT/PGT/PRT exam syllabus.The DSSSB PGT Physics Mock Test - 3 MCQs are made for DSSSB TGT/PGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for DSSSB PGT Physics Mock Test - 3 below.
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DSSSB PGT Physics Mock Test - 3 - Question 1

Two vectors are equal if

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 1

Explanation:Equal vectors are vectors that have the same magnitude and the same direction. Equal vectors may start at different positions.

DSSSB PGT Physics Mock Test - 3 - Question 2

A smooth block is released at rest on a 45° incline and then slides a distances d. The time taken to slide is n time as much to slide on rough incline than on a smooth incline. The coefficient of friction is

[AIEEE 2005]

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 2

When friction is absent

a1 = gsinθ

When friction is present

a2 = gsin θ - μk gcos θ

From Eqs. (i) and (ii)

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DSSSB PGT Physics Mock Test - 3 - Question 3

Consider a car moving on a straight road with a speed of 100 ms-1. The distance at which car can be stopped, is 

[AIEEE 2005] 

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 3

DSSSB PGT Physics Mock Test - 3 - Question 4

A block is kept on a frictionless inclined surface with angle of inclination a. The incline is given an acceleration a to keep the block stationary. Then a is equal to    

[AIEEE 2005]

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 4

In the frame of wedge, the force diagram of block is shown in figure. From free body diagram of wedge.

For block to remain stationary

ma cos α = mg sin α

or         a = g tan α

DSSSB PGT Physics Mock Test - 3 - Question 5

It is advised to drive along the slippery road slowly, because:

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 5

It is advised to drive along the slippery road slowly, because friction is reduced and if the driver is driving at a larger speed there is a risk of skidding.

DSSSB PGT Physics Mock Test - 3 - Question 6

The angular acceleration is known as the rate of change of _________.

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 6

CONCEPT:

  • Angular displacement (θ): The angular displacement of a body is the angle in degrees or radians or revolutions through which a point revolves around a point or axis.
  • Angular velocity (ω): How fast the angular position or orientation of an object changes with time or How fast an object rotates or revolves relative to another point is known as angular velocity.
    • It is the rate of change of angular displacement.​
  • Angular acceleration (α): The rate of change of angular velocity is known as angular acceleration.
  • Angular momentum (L): The moment of momentum is known as angular momentum.

CALCULATION:

  • The rate of change of angular velocity is known as angular acceleration. 

Mathematically,

α = dω/dt

  • So the correct answer is option 3.
DSSSB PGT Physics Mock Test - 3 - Question 7

A body dropped from height H reaches the ground with a speed of showimage (1)

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 7

The forces acting on the body are the force of gravity and the air friction. By work energy theorem, the total work done on the body is
W=1/2m(1.2√gH)2−0=0.72mgH
The work done by the force of gravity is mgH.
. Hence, the work done by the air friction is,
=0.72mgH-mgH
=00.28mgH.
 

DSSSB PGT Physics Mock Test - 3 - Question 8

A ball of mass 10 g hits a hard surface vertically with a speed of 5 m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01 s. The average force exerted by the surface on the ball is  

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 8

Average force = change in momentum/time
Change in momentum = m(v1 - v2)
=0.01[ 5 - (-5)]
=0.1
Average force = 0.1/0.01
= 10 N

DSSSB PGT Physics Mock Test - 3 - Question 9

An earth satellite is moving around the earth in a circular orbit. In such case, what is conserved?

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 9

An earth satellite is moving in a circular motion due to change in the direction of velocity. Its angular momentum about centre is conserved as there is no external force acting on the system.

DSSSB PGT Physics Mock Test - 3 - Question 10

To complete one revolution around Earth, communication satellites take

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 10

A communications satellite is in a GEO (geostationary equatorial orbit) with a period of 24 hours. The spin rate ωs about its axis of symmetry is 1 revolution per minute, and the moment of inertia about the spin axis is 550 kg · m2.

DSSSB PGT Physics Mock Test - 3 - Question 11

When a solid is deformed,

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 11

Explanation:External force permanently distubed the equilibrium position of the interatomic ( or intermolecular ) forces between the particles of solid bodies.

DSSSB PGT Physics Mock Test - 3 - Question 12

A circular steel wire 2.00 m long must stretch no more than 0.25 cm when a tensile force of 400 N is applied to each end of the wire. What minimum diameter is required for the wire?

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 12

DSSSB PGT Physics Mock Test - 3 - Question 13

A mild steel wire of length 1.0 m and cross-sectional area 0.50 × 10−2 cm2 is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid-point of the wire. Calculate the depression at the midpoint.

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 13

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DSSSB PGT Physics Mock Test - 3 - Question 14

The property by virtue of which the free surface of a liquid at rest behaves like an elastic stretched membrane tending to contract so as to occupy minimum surface area is known as

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 14

The property by virtue of which the free surface of a liquid at rest behaves like an elastic stretched membrane tending to contract so as to occupy minimum surface area is known as surface tension. By the definition of surface tension.

DSSSB PGT Physics Mock Test - 3 - Question 15

In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 15

Correct Answer : C

Explanation : The adiabatic condition is given by the relation between pressure volume and temperature volume as:

(PV)γ = constant 

where, γ = Cp/Cv is ratio of the specific heats

These relations suggest that an decrease in volume is associated with increase in temperature

 

ATQ 

P1(V1)γ = (P2V2

=> P1(1)2 = P2(4)2

P1/P2 = 16

DSSSB PGT Physics Mock Test - 3 - Question 16

A 7 kg disc is free to rotate about a horizontal axis passing through its centre O (see figure).  The radius of the disc is 10 cm and spring constant of both the spring is 600 Nm-1 There is  no slipping between the disc and the string. The time period of small oscillations of the disc is

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 16

When the angular displacement of the disc is θ the deformation (elongation and compression) in each  spring is x = Rθ .

DSSSB PGT Physics Mock Test - 3 - Question 17

Electric flux will be maximum if the angle between the field lines and area vector is ______

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 17

We know that the electric field and area both are vector quantity and the electric flux is expressed as E.s (taking dot product). But if the angle between the two vectors is θ then the formula becomes E-.s-.cosθ. Cosθ will be maximum if theta is zero, in all other cases, the value of Cosθ is less than 1. Therefore flux will be the maximum if the angle is 0 degrees.

 

DSSSB PGT Physics Mock Test - 3 - Question 18

What is the angle between the electric dipole moment and the electric field on the equatorial line of the dipole?

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 18

On equatorial line, the direction of electric field is reversed to that of angle of axial line. Therefore, the angle between dipole moment and electric field is 180°.

DSSSB PGT Physics Mock Test - 3 - Question 19

On moving a charge of 20 coulombs by 2 cm, 2 J of work is done, then the potential difference between the points is

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 19

Potential difference between two points is given by

Va - Vb = W/q0

Work, W = 2 J

Charge, q0 = 20 C

Potential difference = 2/20 = 0.1 V

The correct option is C.

DSSSB PGT Physics Mock Test - 3 - Question 20

Optical analogue of an equipotential surface is

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 20

Definition based

DSSSB PGT Physics Mock Test - 3 - Question 21

What will be the effect on capacitance, if the distance between the parallel plates reduced to one-third of its original value?​

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 21

C=(Kε0A/d)∝K/d
Hence,C1/C2=d2/d1=(d/3)d=3
C2=3C1

DSSSB PGT Physics Mock Test - 3 - Question 22

What should be the radius of an isolated spherical conductor so that it has a capacity of 2μF?​

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 22

Capacitance of an isolated spherical conductor =4π€R , where €=permittivity of vacuum
C=2×10-6F
C=4π€R
4×3.14×8.85×10-12×R=2×10-6
R=2×10-6/4×3.14×8.85×10-12
=1.8×104 m

DSSSB PGT Physics Mock Test - 3 - Question 23

Shown in figure is a Post Office box. In order to calculate the value of external resistance, it should be connected between

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 23

Total external resistance will be the total resistance of whole length of box. It should be connected between A and D.

DSSSB PGT Physics Mock Test - 3 - Question 24

Kamla peddles a stationary bicycle the pedals of the bicycle are attached to a 100 turn coil of area 0.10m2. The coil rotates at half a revolution per second and it is placed in a uniform magnetic field of 0.02 T perpendicular to the axis of rotation of the coil. What is the maximum voltage generated in the coil?

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 24

Maximum voltage

DSSSB PGT Physics Mock Test - 3 - Question 25

A pair of adjacent coils has a mutual inductance of 1.5 H. If the current in one coil changes from 0 to 20 A in 0.5 s, change of flux linkage with the other coil is

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 25

DSSSB PGT Physics Mock Test - 3 - Question 26

The magnetic field between the Horizontal poles of an electromagnet in is uniform at any time, but its magnitude is increasing at the rate of 0.020 T/s.The area of a loop made of perfect insulating material is 120cm2.This loop is kept horizontally in the magnetic field. Induced emf and the induced current in the circuit are

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 26

e = Rate of change of magnetic field x area

 

=0.02×120×10−4=0.24mV

DSSSB PGT Physics Mock Test - 3 - Question 27

A radio can tune over the frequency range of a portion of MW broadcast band: (800 kHz to 1200 kHz). If its LC circuit has an effective inductance of 200 μH, what must be the range of its variable capacitor?

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 27

 So the range is 88 - 198 pF

DSSSB PGT Physics Mock Test - 3 - Question 28

A light bulb is rated at 50W for a 220 V supply. The resistance of the bulb, the peak voltage of the source and the rms current through the bulb are

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 28

Given    P=50W, Vrms​=220V,
by     P=Vrms2​​/R
or      R=Vrms2/P​​= 2202/50=968Ω
The peak voltage of the source is,
Erms=E0/√2
=>E0=Erms x √2=220√2=311.13V
Now, 
Irms​=Vrms​​/R
=220/968​
=0.227A
Hence option B is correct.

DSSSB PGT Physics Mock Test - 3 - Question 29

A convex lens forms a real image of an object on a screen; the magnification of the image being 3/2. The object and the screen are kept fixed and the lens is moved through a distance of 16 cm when a sharp image is again formed on the screen; the magnification now being 2/3. What is the focal length of the lens?

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 29

3/2=v/u…...1
2/3=(v-16)/(u+16)......2
from these equation
we get v=48, u=32
so now f=(vxu)/(v+u)=96/5=19.2
The correct answer is option B.

DSSSB PGT Physics Mock Test - 3 - Question 30

For a rectangular slab, refraction takes place at

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 30

The refraction takes place at both the air-glass interface and glass-air interface of a rectangular glass slab. When the light ray incident on the air-glass interface (DC) obliquely, it bends towards the normal.

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