DSSSB PGT Physics Mock Test - 6 - DSSSB TGT/PGT/PRT MCQ

M-travels in car X
T-+Q as given in Y
J-no female, and travels in Z
R-car X(sequential)
D-car Y
W-female with Z
Q-X
hence correct option is C.

 If x >0 then x will be positive and y less than 0 means it gets negative value
that means it lies in 4th quadrant. 

Numbers obtained in three throws are 5,3 and 6
Let the number obtained in fourth throw be x
Now, Sum > 20
5 + 3 + 6 + x > 20
14 + x > 20
x > 6(never wins)

x > 1 means x is greater than 1 in this equation the values of x can be 2,3,4,5.............∞
x < -1 means is less than -1 therefore values of x can be -2, -3, -4, -5............ -∞
So no common point for x
Hence there will be no solution

3(2 - x) ≥ 2(1 - x)
6 - 3x ≥ 2 - 2x
4 ≥ x

x > 1 and x > -1
Take two points 1,-1 on number line
Therefore x > 1

In this type of problem, the formula is"

Here, H is replaced by the first interval of given time and t is spaces apart.
Given that H is 5.

 mins or 24 mins
Therefore, the hands will by 3 minutes apart at 336/11 minutes or 24 minutes past 5.

Hour hand rotates 360° in 12 hrs, so it rotates 30° in 1 hour.
So, in 1 min, it rotates 0.5°.
Minute hand rotates 6° in 1 min.
So, angle at 8:45 = 0.25 × 30° = 7.5°
At 4:15, angle will be 0.25 × 30° + 30° = 7.5° + 30° = 37.5°
So, 37.5° + 0.5t + 7.5° = 6t
45 = 5.5t

Hence clock makes same angle at 23minutes past 4 o'clock

Time from 3 pm on a day to 6 am after 4 days is 87 hours. Now, 23 hr 51 min on this clock are the same as 24 hr on the correct clock.
That is, on this clock = 24 hr on the correct clock
∴ 87 hr on this clock = hr on the correct clock
= 87 hr and 33 minutes approx. on the correct clock
So, the correct time will be 6:33 am.

Number of days from March 15th, 2013 to July 10th, 2013 = 16 + 30 + 31 + 30 + 10 = 117
On dividing 117 by 7, remainder is 5.
Now, counting 5 days after Friday, we get Wednesday.

Using formula: 

Significant Digits

Significant digits are the digits in a number that carry meaning contributing to its precision. They are used to indicate the reliability of a measurement.

Rules for determining significant digits:

1. Non-zero digits are always significant.
2. Zeros between non-zero digits are always significant.
3. Leading zeros (zeros to the left of the first non-zero digit) are never significant.
4. Trailing zeros in a number with a decimal point are significant.

Applying the rules to 0.000532:

• The first non-zero digit is 5.
• The digits following 5, which are 3 and 2, are non-zero and therefore significant.

So, the significant digits in 0.000532 are 5, 3, and 2.

The zeros before the 5 are leading zeros and do not contribute to the precision of the number, hence they are not significant.

for an approximate result, divide the length value by 1.609

► One kilometer is equals to 0.62 miles.

157900  implies that the population is believed to be within the range of about 157850 to about 157950.

In other words, the population is 157900 ± 50. The “plus-or-minus 50” appended to this number means that we consider the absolute uncertainty of the population measurement to be 50 – (–50) = 100.

We can also say that the relative uncertainty is 100/157900, which we can also express as 1 part in 1579, or 1/1579 = 0.000633, or about 0.06 percent.

Derived units are units which may be expressed in terms of base units by means of mathematical symbols of multiplication and division.
Example: the SI derived unit of area is the square metre (m^{​​​​​​2}), and the SI derived unit of density is the kilogram per cubic metre (kg/m³ or kg m^{​​​​​​-3}).

The names of SI units are written in lowercase.

It would be more exact to say that "Quantities with the same units can be added and subtracted with no problem."

Quantities with the same dimensions can often be added and subtracted as long as the units are correctly converted.

Intensity of magnetisation : It represents the extent to which a specimen is magnetised when placed in a magnetising field. Or in other words the intensity of magnetisation of a magnetic material is defined as the magnetic moment per unit volume of the material. 

It indicates how the sample affected by magnetic field when placed in it.

M = Magnetic moment/volume = μM / V

unit SI : M= Amp.metre^-1

We know that coefficient of viscosity (η)= Fr/Av where F = tangential force, r = distance between the layers , v = velocity and A is the area of the surface.
 Thus we get [η] = MLT^-2.L / L². (L/T)
= M / LT
Thus its unit is kg / m sec

As 'at' and 3 are added in the equation, we get at and 3 have same dimensions i.e.1
Thus a has dimensions same as 1/t.

• We know, v = u + gt
  As the ball is dropped, v = gt.
  When coming down, v increases then makes collision, the value of v becomes +ve, then value of v decreases, becomes zero and then increases.
• The change from +v to –v is almost instantaneous. Using -ve signs when coming down, so option c is correct.
  Further h = (1/2) gt²  is a parabola. Therefore (c) is correct.

From the equation of motion, we knows,
v = u + at  ...(1)
► u = (2i + 3j)
► a = (0.3i + 0.2j)
► t = 10 s
On putting these values in first equation we get:
v = (2i + 3j) + (0.3i + 0.2j) * 10
v = 5i + 5j
|v| = 5√2

As, v = k(yi + xi)
v_x = Ky → dx/dt = Ky
v_y = Kx → dy/dt = Kx
Dividing both equations,
► dy/dx = dy/dt divided by dx/dt = Kx / Ky = x/y
► ydy = xdx
Integrating the equation,
► y²/ 2 = x²/2 + c
► y² = x² + constant

Because velocity is the slope of the x-t graph.(dx/dt=V) and by looking at the graph it can be seen that upto time T₀ slope is constant so velocity will be constant and after time T0 slope is zero ( line is parallel to X axis) so the velocity will be zero.