Integration, Differentiation, Errors & Significant Figures MCQ Level - 1 (Test - 2) - Class 11 MCQ

If L = 2.331 cm, B - 2.1 cm, then L + B is equal to

A plate has a length (5 ± 0.1) cm and breadth (2 ± 0.01) cm. Then the area of the plate is

The number of significant figures in all the given numbers 25.12, 2009, 4.156 and 1.217 x 10^-4 is

An obj ect, m oving with a speed of 6.25 m /s, is decelerated at a rate given by   where v is the instantaneous speed. The time taken by the object, to come to rest, would be 

The position of a particle x (in metre) at a time t second is given by the relation r  = (3tiˆ - t 2 ˆj + 4kˆ) . Calculate the magnitude of velocity of the particle after 5s. the magnitude of velocity of the particle after 5s.

A particle moves along with x-axis. The position x of particle with respect to time t from origin given by x = b₀ + b₁t + b₂ t². The acceleration of particle is

The acceleration a of a particle starting from rest varies with time according to relation α = αt + β . The velocity of the particle after a time t will be

A particle moves along a straight line such that its position x at any time t is x = 6t² -t³. Where x in metre and t is in second, then

Displacement (x) of a particle is related to time (t) as x = at + bt² - ct³ where a,b and c are constants of the motion. The velocity of the particle when its acceleration is zero is given by

Acceleration of a body when displacement equation is 3s = 9t + 5t² is

The velocity of particle is v = v₀ + gt + ft². If its position is x = 0 at t = 0, then its displacement after unit time (t = 1) is

The coordinates of a moving particle at any time t are given by x = αt³ and y = βt³. The speed of particle at time t is given by

A particle located at x = 0 at time t = 0, starts moving along the position x-direction with a velocity v that varies as .The displacement of the particle varies with time as

The displacement of particle is given by  What is its acceleration?

The relation between time t and distance x is t = ax² + bx, where a and b are constants. The acceleration is

A particle moves along x - axis as x = 4 (t - 2) + a (t - 2)² Which of the following is true?

If the velocity of a particle is given by v = (180 -16x)^1/2 ms^-1, then its acceleration will be

A particle moves along x-axis in such a way that its coordinate (x) varies with time t according to the expression x = 2 -5t + 6t² m, the initial velocity of the particle is

A particle moves along a straight line such that its displacement at any time t is given by s = t³ - 6t² +3t + 4. The velocity when its acceleration is zero is

The displacement s of a particle is proportional to the first power of time t, i.e.,s α t; then the acceleration of the particle is

The displacement x of particle moving in one dimension under the action of a constant force is related to time t by the equation , where x is in metres and t is in seconds, Find the displacement of the particle when its velocity is zero

For motion of an object along the x-axis, the velocity v depends on the displacement x as v = 3x² - 2x, then what is the acceleration at x = 2m.