Gauss Law MCQ Level - 2 - Class 12 MCQ
25 Questions MCQ Test - Gauss Law MCQ Level - 2
In a region with a uniform electric field, the number of lines of force per unit area is E. If a spherical metallic condcutor is placed in the area, the field inside the conductor will be
If one penetrates a uniformly charged spherical cloud electric field strength
therefore field decreases directly as the distance form the centre. | 1 Crore+ students have signed up on EduRev. Have you? Download the App |
An unchanged metal sphere is placed between two equal and oppositely charged metal plates. The nature of lines of force will be
Consider two concertric spherical surfaces S1 with radius a and S2 with radius 2a, both centred on the origin. There is a charge +q at the origin and no other c harges, Compare the flux 
through S1 with the flux 
through S2 .
as charge is same in both total flux will be 
for both of them. 
Under what conditions can the electric flux 
be found through a closed surface?
Three charges of q1 = 1 × 10-6 C, q2 = 2 × 10-6 C and q3 = -3 ×10-6 C have been placed as shown, Then the net electric flux will be maximum for the surface
will be max if charge enclosed is max S1 has max charge so flux will be max from S1.In a region of space, the electric field is given by 
. The electric flux through a surface or area of 100 units in x - y plane is
A flat square surface with sides of length L is described by the equations
The electric flux through the square due to a positive point charge q located at the origin (x = 0, y = 0, z = 0 ) is
, but flux from one face will be 
.
Two conducting plates X and Y, each having large surface area A (on one side) are placed parallel to each other. The plate X is given a charge Q whereas the other is neutral. The electric field at a point in between the plates is given by :
A hemispherical surface of radius R is placed with its cross-section perpendicular to a uniform elcetric field E as shown in Fig. Flux linked with its curved surface is :
The Fig. shows two parallel equipotential surfaces A and B at same potential kept at a distance r apart from each other. A point cahrge -q is taken from surface A to B, the amount of net work done W will be :
An ellipsoidal cavity is curved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in Fig.
Two thin infinite sheets have uniform surface densities of charge +σ and - σ . Electric field in the space between the two sheets is :
Fig. shows a hemisphere of radius 'R'. A point charge q is kept at distance 'y' above the centre such that y → 0.
Electric flux through the curved surface is :
A and B are two concentric spheres, If A is given a charge Q while B is earthed as shown in fig, then
A solid metallic sphere has a charge +3Q concentric with this sphere is a conducting spherical shell having charge -Q. The radius of the sphere is a and that of the spherical shell is b(>a). What is the electric field at a distance r (a <r <b) from the centre?
There are two concentric metal shells of radii r1 and r2 (<r1). If the outer shell has a charge q and the inner shell is grounded, the charge on the inner shell is :
A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge -3Q, the new potential difference between the same two surface is :
A uniformly charged an infinitely long line having a iinear charge density 'λ' is placed at a normal distance y from a point O, Consider s sphere of radius R with O as centre and R > y. Electric flux through the surface of the sphere is :
An insulating solid sphere of radius 'R' is charged in a non-uniform manner such that volume charge density P(A/r), where A is a positive constant and r the distance from centre. Electric field strength at any inside point at distance r1 is :
Three infinitely long charge sheets are placed as shown in figure. The electric field at point P is :
A spherical portion has been removed from a solid sphere having a charge distributed uniformly in its volume as shown in the fig. The electric field inside the emptied space is :
Figure shows an imaginary cube of edge L/2. An uniformly charged rod of length L moves towards left at a small but constant speed v. At t = 0, the left end just touches the centre of the face of the cube opposite it. Which of the graphs shown in the figure represents the flux of the electric field through the cube as the rod goes through it
A conducting sphere S1 intersects a closed surfae S2 as shown in the figure. A positive charge q is placed at a point P. What is the value of electric flux through the surface S2?
Important Questions for Gauss Law MCQ Level - 2
Gauss Law MCQ Level - 2
Online Tests for Gauss Law MCQ Level - 2
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