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Test: Measures of Central Tendency - 2 - SSC CGL MCQ


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10 Questions MCQ Test - Test: Measures of Central Tendency - 2

Test: Measures of Central Tendency - 2 for SSC CGL 2024 is part of SSC CGL preparation. The Test: Measures of Central Tendency - 2 questions and answers have been prepared according to the SSC CGL exam syllabus.The Test: Measures of Central Tendency - 2 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Measures of Central Tendency - 2 below.
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Test: Measures of Central Tendency - 2 - Question 1

Find the mode of given samples.
47, 25, 15, 89, 47, 89, 89, 1, 47, 73, 29, 64, 95, 90, 47, 25.

Detailed Solution for Test: Measures of Central Tendency - 2 - Question 1

89 and 25 occurs twice, 64 occurs once, 47 occurs four times.
Since 47 has occurred four times in the above data set and other numbers less than that. The mode of the above data set is 47.

Test: Measures of Central Tendency - 2 - Question 2

Find the median of 4.1, 5.2, 6.3, 3.6, 2.4, 6.4, 4.6

Detailed Solution for Test: Measures of Central Tendency - 2 - Question 2

Concept:
Median: It is the middle value in the given set, while the set is either in increasing or decreasing order.

If the number of observations (n) is odd then the median is (n+1)/2nd term.

If the number of observations (n) is even then the median is the average of nth and (n+1)th term.

Calculation:

Given data are 4.1, 5.2, 6.3, 3.6, 2.4, 6.4, 4.6

Increasing order of given data: 2.4, 3.6, 4.1, 4.6, 5.2, 6.3, 6.4

The number of observations is odd (n = 7)

So, the median is the  (n+1)/2th term or 4th term

Median is 4th term i.e., 4.6

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Test: Measures of Central Tendency - 2 - Question 3

A data set of n observations has mean 2M, while another data set of 2n observations has mean M. What is the mean of the combined data sets?

Detailed Solution for Test: Measures of Central Tendency - 2 - Question 3

Concept:

Combined Mean:

Let x1 and x2 are the means of the first and second group of data containing n1 and n2 items respectively.

Then combined mean is:

 

Calculation:

Given: 

n1 = n and x1 = 2M

n2 = 2n and x2 = M

The combined mean will be:

Test: Measures of Central Tendency - 2 - Question 4

What is the mode of 19, 18, 9, 24, 1, 12, 23, 75?

Detailed Solution for Test: Measures of Central Tendency - 2 - Question 4

According to the definition of mode, a mode is a number that occurs most frequently. There is no such number which is repeated more than once . So, we can say there is No Mode.

Test: Measures of Central Tendency - 2 - Question 5

If mean and mode of some data are 4 & 10 respectively, its median will be:

Detailed Solution for Test: Measures of Central Tendency - 2 - Question 5

Given that,

mean of data = 4 and mode of  data = 10

We know that

Mode = 3(Median) - 2(Mean)

⇒ 10 = 3(median) - 2(4)

⇒ 3(median) = 18

⇒ median = 6

Hence, the median of data will be 6.

Test: Measures of Central Tendency - 2 - Question 6

Find the mean of given data:

Detailed Solution for Test: Measures of Central Tendency - 2 - Question 6

The mean of grouped data is given by,

Given:

 

Calculation:

Now, to calculate the mean of data will have to find ∑fiXi and ∑fi as below,

 

Then,

We know that, mean of grouped data is given by

Hence, the mean of the grouped data is 35.7

Test: Measures of Central Tendency - 2 - Question 7

Find the mode of the data: 13, 16, 12, 14, 19, 12, 14, 13, 14

Detailed Solution for Test: Measures of Central Tendency - 2 - Question 7

Given data = 13, 16, 12, 14, 19, 12, 14, 13, 14

Arranging the data in ascending order, we get

12, 12, 13, 13, 14, 14, 14, 16, 19.

Mode is the observation that occurs highest number of times.

14 occurs three times in the given data.

∴ Mode = 14 

Test: Measures of Central Tendency - 2 - Question 8

The Values of mean and median are given as 22.5 and 20 respectively. Find the approximate value of Mode.

Detailed Solution for Test: Measures of Central Tendency - 2 - Question 8

The empirical mean median mode relation is given as
Mean – Mode = 3(Mean – Median)
Given Mean = 22.5 and Median = 20
22.5 – Mode = 3(22.5 – 20)
Mode = 15

Test: Measures of Central Tendency - 2 - Question 9

Find the median of the given set of numbers 2, 6, 6, 8, 4, 2, 7, 9

Detailed Solution for Test: Measures of Central Tendency - 2 - Question 9

Concept:

Median: The median is the middle number in a sorted- ascending or descending list of numbers.

Case 1: If the number of observations (n) is even

Case 2: If the number of observations (n) is odd

Calculation:

Given values 2, 6, 6, 8, 4, 2, 7, 9

Arrange the observations in ascending order:

2, 2, 4, 6, 6, 7, 8, 9

Here, n = 8 = even

As we know, If n is even then,

 

Test: Measures of Central Tendency - 2 - Question 10

Find the mean of given data:

Detailed Solution for Test: Measures of Central Tendency - 2 - Question 10

Formula used:

The mean of grouped data is given by,

Given

 

Calculation:

Now, to calculate the mean of data will have to find ∑fiXi and ∑fi as below,

Then,

We know that, mean of grouped data is given by

Hence, the mean of the grouped data is 35.7

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