ECGC PO Mock Test - 3 - Bank Exams MCQ

Persons: A, B, C, D, E, F, G and H.
Floors: 1 to 8.
House numbers: 11 to 18.
1) D lives on the 5th floor and his house number is 16.
2) C and A live on 2nd and 7th floors respectively.
3) H lives on the 6th floor and his house number is 18.

4) F’s house number is 15 and doesn’t live on 4th or 8th floor.
5) G doesn’t live on the top floor and his house number is 14.
6) A person whose house number is 11 lives on the 3rd floor.

7) B’s floor is immediately above the person whose house number is 13.
8) A person whose house number is 12 lives immediately below the person whose house number is 17.

So, 'F lives on the 4th floor' is an incorrect statement as F lives on the 1st floor.

Persons: A, B, C, D, E, F, G and H.
Floors: 1 to 8.
House numbers: 11 to 18.
1) D lives on the 5th floor and his house number is 16.
2) C and A live on 2nd and 7th floors respectively.
3) H lives on the 6th floor and his house number is 18.

4) F’s house number is 15 and doesn’t live on 4th or 8th floor.
5) G doesn’t live on the top floor and his house number is 14.
6) A person whose house number is 11 lives on the 3rd floor.

7) B’s floor is immediately above the person whose house number is 13.
8) A person whose house number is 12 lives immediately below the person whose house number is 17.

So, '5th floor – D' is the correct pair.

Persons: A, B, C, D, E, F, G and H.
Floors: 1 to 8.
House numbers: 11 to 18.
1) D lives on the 5th floor and his house number is 16.
2) C and A live on 2nd and 7th floors respectively.
3) H lives on the 6th floor and his house number is 18.

4) F’s house number is 15 and doesn’t live on 4th or 8th floor.
5) G doesn’t live on the top floor and his house number is 14.
6) A person whose house number is 11 lives on the 3rd floor.

7) B’s floor is immediately above the person whose house number is 13.
8) A person whose house number is 12 lives immediately below the person whose house number is 17.

So, 'E' lives on the top floor.

Persons: A, D, H, I, J, R, S, and V
1) J is sitting third to the right of S.

2) J and V are immediate neighbors.
Case 1:

Case 2:

3) There are 2 persons sitting between R and V.
4) H and R are not immediate neighbors of S.
Case 1 cannot satisfy the above conditions. So, gets eliminated.

5) A is facing in the opposite direction of R.

6) There are 2 persons sitting between H and D.
7) H and R are immediate neighbors.

So, I will sit between R and D.

So, V sits opposite to person I.

Persons: A, D, H, I, J, R, S, and V
1) J is sitting third to the right of S.

2) J and V are immediate neighbors.
Case 1:

Case 2:

3) There are 2 persons sitting between R and V.
4) H and R are not immediate neighbors of S.
Case 1 cannot satisfy the above conditions. So, gets eliminated.

5) A is facing in the opposite direction of R.

6) There are 2 persons sitting between H and D.
7) H and R are immediate neighbors.

So, I will sit between R and D.

One persons are sitting between A and J (when counted from right of A).

Clearly, for better economic gain, losses should be reduced and income increased. So, only course I follows.

8 boxes: B, F, J, O, S, U, W and Z.
8 shelves: 1 to 8 (from bottom to top).
We can solve this question step by step,
1) There are at least 5 shelves above the box Z.
2) There are three boxes between box J and Z.
Case – 1

Case – 2

Case – 3

3) Box B is placed two places above the box J.
This condition doesn’t satisfy in case 1. Thus, case 1 gets eliminated.
4) There are four boxes between the box B and F.
Case – 2

Case – 3

5) There are three shelves between the box O and W.
6) Box W is neither placed at the bottom nor on the top.
Case – 2

Case – 3

7) Box S is placed on one of the shelves which is below the box U but not at even This number.
This condition doesn’t satisfy in case 2.
Thus, case 2 gets eliminated and we have the final arrangement as follows:
Case – 3

So, Box Z is placed at shelf 1.

8 boxes: B, F, J, O, S, U, W and Z.
8 shelves: 1 to 8 (from bottom to top).
We can solve this question step by step,
1) There are at least 5 shelves above the box Z.
2) There are three boxes between box J and Z.
Case – 1

Case – 2

Case – 3

3) Box B is placed two places above the box J.
This condition doesn’t satisfy in case 1. Thus, case 1 gets eliminated.
4) There are four boxes between the box B and F.
Case – 2

Case – 3

5) There are three shelves between the box O and W.
6) Box W is neither placed at the bottom nor on the top.
Case – 2

Case – 3

7) Box S is placed on one of the shelves which is below the box U but not at even This number.
This condition doesn’t satisfy in case 2.
Thus, case 2 gets eliminated and we have the final arrangement as follows:
Case – 3

So, the combinations ‘Box S, Shelf 6’ and ‘Box O, Shelf 7’ are not correct.

8 boxes: B, F, J, O, S, U, W and Z.
8 shelves: 1 to 8 (from bottom to top).
We can solve this question step by step,
1) There are at least 5 shelves above the box Z.
2) There are three boxes between box J and Z.
Case – 1

Case – 2

Case – 3

3) Box B is placed two places above the box J.
This condition doesn’t satisfy in case 1. Thus, case 1 gets eliminated.
4) There are four boxes between the box B and F.
Case – 2

Case – 3

5) There are three shelves between the box O and W.
6) Box W is neither placed at the bottom nor on the top.
Case – 2

Case – 3

7) Box S is placed on one of the shelves which is below the box U but not at even This number.
This condition doesn’t satisfy in case 2.
Thus, case 2 gets eliminated and we have the final arrangement as follows:
Case – 3

So, Box U is placed at shelf 6.

The statement is regarding the good part of drinking water as soon as one gets up, leading to benefits for health. Out of the inferences provided, only the first one is true and goes along with the statement. The second inference about water causing gas trouble hasn’t been talked about in the statement so inference II is not true.
Thus, only inference I is true.

So, the code for village is kn.

(1) There are five buildings between the third most expensive building and the building in which the number of residents is half of the third most expensive building.
(It is given in the question that N is the third most expensive building. Also, the number of residents in building N is 26, implies, the other building is B in which the number of residents is 13. Also, as there are five building between these two buildings, implies, one of them must be at an end.)
(2) The average number of residents in the two right-most building is 26.
(Implies, the total number of people the two right-most buildings is 52. On observing the number of residents closely, we can say that there is only one pair of buildings that satisfies this criteria i.e. buildings J and B (39 and 13). So, it means that building B is either at the right-most end or the second position from the right-most end.)
(3) The building with the second highest number of residents is to the immediate left of building N.
(Building T has the second highest number of residents in it, implies, building T is to the immediate left of building N. In this case, building N must be at the second position from the left and building B must be at the right-most end.)

(4) There are only three buildings between the second highest and second lowest expensive buildings.
(J is the second most expensive building and Y is the second lowest expensive building. As building J is second from the right end, implies, building Y must be the third building from the left end.)

(5) The least expensive building is not to the next of the building which has 22 residents.
(Implies, building K is not next to building Y as building Y has 22 residents.)
(6) The most expensive building is to the immediate left of the building which has half the number of residents as the most expensive building.
(P is the most expensive building and building O has half the number of residents as building P. Now, we cannot place building K to the immediate right of building Y. If we place building K second to the right of building Y then, in that case, we would not be able to place building P to the immediate left of building O.
Thus, building K is third to the right of building Y. Building P is to the immediate right of building Y and building O is to the immediate right of building P.)

Clearly, building J is to the immediate right of building K which has the highest number of residents.

(1) There are five buildings between the third most expensive building and the building in which the number of residents is half of the third most expensive building.
(It is given in the question that N is the third most expensive building. Also, the number of residents in building N is 26, implies, the other building is B in which the number of residents is 13. Also, as there are five building between these two buildings, implies, one of them must be at an end.)
(2) The average number of residents in the two right-most building is 26.
(Implies, the total number of people the two right-most buildings is 52. On observing the number of residents closely, we can say that there is only one pair of buildings that satisfies this criteria i.e. buildings J and B (39 and 13). So, it means that building B is either at the right-most end or the second position from the right-most end.)
(3) The building with the second highest number of residents is to the immediate left of building N.
(Building T has the second highest number of residents in it, implies, building T is to the immediate left of building N. In this case, building N must be at the second position from the left and building B must be at the right-most end.)

(4) There are only three buildings between the second highest and second lowest expensive buildings.
(J is the second most expensive building and Y is the second lowest expensive building. As building J is second from the right end, implies, building Y must be the third building from the left end.)

(5) The least expensive building is not to the next of the building which has 22 residents.
(Implies, building K is not next to building Y as building Y has 22 residents.)
(6) The most expensive building is to the immediate left of the building which has half the number of residents as the most expensive building.
(P is the most expensive building and building O has half the number of residents as building P. Now, we cannot place building K to the immediate right of building Y. If we place building K second to the right of building Y then, in that case, we would not be able to place building P to the immediate left of building O.
Thus, building K is third to the right of building Y. Building P is to the immediate right of building Y and building O is to the immediate right of building P.)

Clearly, there are three buildings to the right of building O which has the least number of residents.

(1) There are five buildings between the third most expensive building and the building in which the number of residents is half of the third most expensive building.
(It is given in the question that N is the third most expensive building. Also, the number of residents in building N is 26, implies, the other building is B in which the number of residents is 13. Also, as there are five building between these two buildings, implies, one of them must be at an end.)
(2) The average number of residents in the two right-most building is 26.
(Implies, the total number of people the two right-most buildings is 52. On observing the number of residents closely, we can say that there is only one pair of buildings that satisfies this criteria i.e. buildings J and B (39 and 13). So, it means that building B is either at the right-most end or the second position from the right-most end.)
(3) The building with the second highest number of residents is to the immediate left of building N.
(Building T has the second highest number of residents in it, implies, building T is to the immediate left of building N. In this case, building N must be at the second position from the left and building B must be at the right-most end.)

(4) There are only three buildings between the second highest and second lowest expensive buildings.
(J is the second most expensive building and Y is the second lowest expensive building. As building J is second from the right end, implies, building Y must be the third building from the left end.)

(5) The least expensive building is not to the next of the building which has 22 residents.
(Implies, building K is not next to building Y as building Y has 22 residents.)
(6) The most expensive building is to the immediate left of the building which has half the number of residents as the most expensive building.
(P is the most expensive building and building O has half the number of residents as building P. Now, we cannot place building K to the immediate right of building Y. If we place building K second to the right of building Y then, in that case, we would not be able to place building P to the immediate left of building O.
Thus, building K is third to the right of building Y. Building P is to the immediate right of building Y and building O is to the immediate right of building P.)

Clearly, building N is to the immediate left of building Y and there are 26 residents in that building.

Given Statements: X > Y ≥ Z ≥ W, W > V ≥ U
On combining: X > Y ≥ Z ≥ W > V ≥ U
Conclusions:
I. W < U → False (as X > Y ≥ Z ≥ W > V ≥ U → W > U)
II. Y > W → False (as Y ≥ Z ≥ W → Y ≥ W, it is possible but not definite)
Thus, none is true.

As we can see in the first step of the given example that the word starting from the smallest letter is placed at the leftmost end and the smallest number is increased by one first and then placed at the rightmost end. Rest of the elements remain in the same order.
Similarly, in the step II, the word starting with second least letter is placed at the leftmost end and the second smallest number is increased by two and then placed at the rightmost end. Rest of the elements remain in the same order.
This process is repeated till an arrangement is achieved where the words are arranged in a decreasing order of the letter that they start with from left to right and the numbers are arranged in decreasing order from right to left.
Using the same pattern, we get the solution of the given input:
Input: your like 18 34 pray 51 to many 40 66 book 27
Step I: book your like 34 pray 51 to many 40 66 27 19
Step II: like book your 34 pray 51 to many 40 66 19 29
Step III: many like book your pray 51 to 40 66 19 29 37
Step IV: pray many like book your 51 to 66 19 29 37 44
Step V: to pray many like book your 66 19 29 37 44 56
Step VI: your to pray many like book 19 29 37 44 56 72
Logic:
In the given problem the following pattern is followed:
Step I: The smallest number is arranged in the first position the left most position in the sequence.
Step II: The highest number is pushed to the last position the right most position in the sequence.
Similarly, lowest numbers are arranged from the right side and the highest to the left side.
Final position is all the numbers are arranged in ascending order.
Now the given input is 116 85 66 50 73 39 146 25 112 79
Step 1: 25 116 85 66 50 73 39 146 112 79
Step 2: 25 116 85 66 50 73 39 112 79 146
Step 3: 25 39 116 85 66 50 73 112 79 146
Step 4: 25 39 85 66 50 73 112 79 116 146
Step 5: 25 39 50 85 66 73 112 79 116 146
Step 6: 25 39 50 85 66 73 79 112 116 146
Step 7: 25 39 50 66 85 73 79 112 116 146
Step 8: 25 39 50 66 73 79 85 112 116 146
So, eight steps are required for the final arrangement.

As we can see in the first step of the given example that the word starting from the smallest letter is placed at the leftmost end and the smallest number is increased by one first and then placed at the rightmost end. Rest of the elements remain in the same order.
Similarly, in the step II, the word starting with second least letter is placed at the leftmost end and the second smallest number is increased by two and then placed at the rightmost end. Rest of the elements remain in the same order.
This process is repeated till an arrangement is achieved where the words are arranged in a decreasing order of the letter that they start with from left to right and the numbers are arranged in decreasing order from right to left.
Using the same pattern, we get the solution of the given input:
Input: your like 18 34 pray 51 to many 40 66 book 27
Step I: book your like 34 pray 51 to many 40 66 27 19
Step II: like book your 34 pray 51 to many 40 66 19 29
Step III: many like book your pray 51 to 40 66 19 29 37
Step IV: pray many like book your 51 to 66 19 29 37 44
Step V: to pray many like book your 66 19 29 37 44 56
Step VI: your to pray many like book 19 29 37 44 56 72
Clearly, ‘44’ is the rightmost element in step IV.

The figure according to the information given in the question will be as follows:

We know that, XY = XO + OY where O is the starting point.
By Pythagoras’ theorem,
OY² = AO² + OY²
OY² = 5² + 5² = 50
Similarly, OX² = 50
⇒ OX = OY = 5√2
Therefore, XY = 2 × 5√2 = 10√2
So, the shortest distance between the final positions of X and Y is 10√2 km.

Clearly, shifting agriculture is a practice in which a certain crop is grown on a land and when it becomes infertile it is left bare and another piece of land is chosen. Clearly, it is a wasteful practice. So, only argument I holds.

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