SSC Stenographer Practice Test - 1 - SSC Stenographer MCQ

(2)² + (4)² = 20

and (3)² + (9)² = 90

Therefore (1)² + (5)² = 26.

93 - (27 + 3) = 63

79 - (38 + 4) = 37

Therefore, 67 - (16 + X) = 42

X = 9

F – The statement provides a statistic which can be independently verified.
J – This is an opinion which people may or may not agree with.
J – This is only an opinion on the running abilities of Usain Bolt. It cannot be verified independently.
I – ‘Collapse of the bridge’ is the fact on the basis of which inference is drawn on ‘villagers facing the problem of travelling to the town’.

2004 is a leap year (Since the month of February in this year has 29 days).
Now, March 11, 2003 is a Tuesday. We have to find the day of the week on March 11, 2004.
The number of days between the two dates is 366 days.
The number of odd days is 2.
The day of the week on March 11, 2004 = Tuesday + 2 = Thursday

We know that the time difference between India and USA is 9 hours 30 minutes.
India is 9 hours 30 minutes  ahead of USA.
Time in India = 4 hours 15 minutes + 9 hours 30 minutes = 13 hours 45 minutes 
Required time after 18 hrs = 13 hours 45 minutes + 18 hrs = 7 hours 45 minutes 
Hence, it is 7 hours 45 minutes  the next morning. 

As 2012 was a leap year, so the number of days in each month from 23rd January, 2011 to 31st July, 2013 is given as follows.
Since 2011 is not a leap year = 365 - 22 = 343 days
Number of days in 2012 = 366 days (leap year)
Number of days in 2013:
January = 31 days
February = 28 days
March = 31 days
April = 30 days
May = 31 days
June = 30 days
July = 31 days
Total number of days in 2013 = 212
Therefore, total number of days from 23rd January, 2011 to 31st July, 2013 = 343 + 366 + 212 = 921

Every hour:

1. Table clock - Wall clock = +10 minutes ⇒ 1 hour in 6 hours
2. Alarm clock - Table clock = -5 minutes ⇒ 30 minutes in 6 hours
3. Wrist watch - Alarm clock = +5 minutes ⇒ 30 minutes in 6 hours

Also, every hour, wall clock loses 10 minutes.
If it is 6 hours since 12 noon, then time shown by the wall clock = 6:00 - 1 hour = 5:00 pm
⇒ Time shown by table clock with reference to wall clock = 5:00 + 50 min = 5:50 pm
⇒ Time shown by alarm clock with reference to table clock = 5:50 pm - 25 minutes - 25/6 minutes = 5:21 pm
⇒ Time shown by wrist watch = 5:21 + 25 minutes + 21/6 = 5.47 pm
Hence, 5.47 pm is the answer.

As Chairman is the highest authority in a conference similarly Editor is in Newspaper.

As the result of Race is Fatigue similarly the result of Fast is Hunger.

First and fouth letters are interchanged while second and third letters are interchanged.

Cup is used to drink something with the help of lips. Similarly birds collects grass with the help of beak to make her nest.

As position of M and N in Eq. alphabets are 13 and 14 respectively.Same position of F and R in Eq. alphabets are 6 and 18 respectively.

As 25 = (5)² → (5 + 1)² + 1 = 37.

As 49 = (7)² → (7 + 1)² + 1 = 65.

As Kick is in the game of Football, similarly Throw is used in the game of Ring.

Apple, Grape, Orange all are fruits. So they belong to the same group that is 'fruit'.

The other option is not related to the given items.

Hence, the correct answer is Fruits.

These are all defensive games.

As 'Knowledge' is achieved by 'Reading' in the same way 'Experience' is achieved by 'Work'.

As we move to right side on the number line the value increases. i.e. To the right of the point (-3,0)

Let x be the smaller of the two consecutive even positive integers, then the other even integer is x + 2. 
 Given x < 10  and x + (x + 2) > 11.  
⇒ x < 10, and 2x + 2 > 11.  
⇒ x < 10, 2x > 9 
⇒ x < 10, x > 9/2 
⇒  x > 9/2   and    x<10 
∴ the required parity even integers is (6, 8)

• IQ = (MA*100)/CA
• and 80 ≤ IQ ≤ 140
• 80 ≤ (MA*100)/CA ≤ 140
• 80 ≤ (MA*100)/12 ≤ 140
• 960 ≤ (MA*100) ≤ 1680
• 9.6 ≤ MA ≤ 16.8

The given statement is: C < A ≤ T = D ≥ O; G ≥ D < S; T ≥ A

Combine the statement: C < A ≤ T = D ≥ O; G ≥ D < S

Conclusions:

I: A ≤ O → False (as A ≤ T = D ≥ O gives; as A ≤ D and D ≥ O → clear relationship between A and O cannot be determined).

II: C < G → True (as C < A ≤ T = D ≥ O; G ≥ D < S gives; as by combinatin C < A ≤ T = D ≤ G so C < G True).

Hence, the correct answer is “Only II”.

According to given information:

Statements: M ≤ N = O ; M ≤ P ; O < Q

Combining the statement: P > M ≤ N = O < Q

Here, P is greater than or equal to M which is less than or equal to N equal to O which is less than Q.

Conclusions:

I.  Q > N → True (In the given statement, P > M ≤ N = O < Q ,It clearly mentioned Q is greater than O which is equal to N .So, Q is greater than N too. Thus, the conclusion I is true).

II. M ≥ O → False (In the given statement, M ≤ N = O, It is clearly mentioned that M is less than or equal to N which is equal to O. So, M can never be greater than O. Thus, conclusion II is a false).

Hence, "Option b" is the correct answer.

3m² - 21m + 30 < 0
m² - 7m + 10 < 0
⇒ (m - 5)(m - 2) < 0
⇒ 2 < m < 5

The options need to be converted to approximate values before you judge the answer. At x = 0, inequality is satisfied.
Thus, option (b) and (d) are rejected. Option (c) is correct. 

|x| ≤ 2 ⇒ minimum value of x = - 2.
|y + 3| ≤ 5 ⇒ minimum value of y = - 8.
So, x + y = - 2 - 8 = - 10.