Indian Coast Guard Navik GD Mock Test - 1 - Indian Coast Guard Navik GD/DB MCQ

Hence, Option D is correct.

a + b + c = 6 and ab + bc + ca = 11
∴  bc (b + c) + ca (c + a) + ab (a + b) + 3abc
= bc (b + c) + abc + ca (c + a) + abc + ab (a + b) + abc
= bc (a + b + c) + ca (a + b + c) + ab (a + b + c)
= (a + b + c) (bc + ca + ab)
= 6 × 11 = 66

Cost of 5 pens + 8 pencils = ₹31
On multiplying by 3
15 pens + 24 pencils = 3 x 31 =
₹15 pens + 24 pencils = 93

I. 144x² = 16 + 20

II. 20y = √169 – √9
20y = 13 – 3
20y = 10

Answer: x ≤ y
Hence, Option B is correct.

= log₁₀10 + log₁₀100 + log₁₀1000 + log₁₀10000 + log₁₀100000
= 1 + 2 + 3 + 4 + 5
= 15 

AP: 10, 6, 2, …
a = 10, d = - 4
Sum of first n terms = S(n) = (n/2) x [2a + (n – 1) x d]
S5 = (5/2) x [2 x (10) + (5 – 1) x (-4)]
= (5/2) x [20 + 4 x (-4)]
= (5/2) x (20 – 16)
= (5/2) x (4)
= 5 x 2
= 10

Required time 

Hence, Option A is correct.

Net part filled in 1 hr = (1/8 ? 1/16) = 1/16
Total time taken to fill the tank = 16 hrs.

Time taken by A to run 1 km = 290 sec.
Time taken by B to run 1 km = 300 sec.
A can give B a start of (300-290) = 10sec.
In 300 sec, B runs (1000/300*10) m = 100/3 m
∴ A can give B start of 100/3 m.

Simran invested Rs 50000 for 36 months and Nanda invest Rs 80000 for 30 months
Jitesh’s one month equivalent investment = 50000*36
Rahul’s one month equivalent investment = 80000*30
Thus, ratio of their investments =  = 50000*36 : 80000*30 = 3 : 4
Therefore Jitesh’s share in the profit = 24500 x 3/7 = Rs 10,500 (option ‘D’)

Let CP = 100
MP = 160
SP = 125

Hence, Option D is correct.

There should be 56 in place of 57.
Hence, Option C is correct. 

One of AB, AD and CD must have given.

So, the data is inadequate.

Total milk bought =8.5l+7.25l+9.4l=25.15l

∴ Milk left in booth = 30l−25.15l = 4.850 liters

In a bag, there are 12 black and 6 white balls.
Two balls are chosen at random, and the first one is found to be black.
There are a total of 18 balls in the bag.
Step 1:
The probability of the first ball being black is given by:
P(First ball is black) = ¹²⁄₁₈

Step 2:
After removing one black ball, there are 17 balls left in the bag, of which 11 are black and 6 are white.

Step 3:
The probability that the second ball is white is:
P(Second ball is white) = ⁶⁄₁₇
Therefore, the probability that the second ball chosen is white is: ⁶⁄₁₇

∵ 8 m shadow means original height = 12 m
∴ 1 m shadow means original height = 12/8 m
∴ 100 m shadow means original height = (12/8) x 100 m
= (6/4) x 100 = 6 x 25 = 150 m

On the basis of question we draw a figure of a circle with centre O ,

Let OE = y cm
then OF = (y +1) cm
OA = OC = r cm
AE = 4 cm; CF = 3 cm
From ∆ OAE,
OA² = AE² + OE²
⇒ r² = 16 + y²
⇒ y² = r² – 16 ......(i)
From ∆OCF,
(y + 1)² = r² – 9 ..... (ii)
By equation (ii) – (i),
(y + 1)² – y² = r² – 9 – r² + 16
⇒ 2y + 1 = 7
⇒ y = 3 cm
∴ From equation (i),
9 = r² – 16
⇒ r² = 25
⇒ r = 5 cm

Let total work be LCM of (90, 60) = 180 unit
Ratio of number of days by Sarthak and Deepak = 90 : 60 = 3 : 2
Ratio of efficiency of Sarthak and Deepak = 2 : 3
Total unit in one day = 2 + 3 = 5 unit
Number of days taken = 180/5 = 36 days 
Hence, Option B is correct.

So the answer = (100 – 50)% of 700 + (100 – 60)% of 500 = 550
Hence, Option D is correct.

All even numbers between 1 and 50 = 2 to 48

Hence, Option D is correct.

The correct answer is A) Sodium. Sodium reacts vigorously with both oxygen and water. When exposed to oxygen, sodium rapidly combines with it to form sodium oxide (Na₂O) or sodium peroxide (Na₂O₂), depending on the conditions. This reaction is exothermic and often accompanied by a bright yellow flame.

In the presence of water, sodium reacts vigorously to produce sodium hydroxide (NaOH) and hydrogen gas (H₂). The reaction is highly exothermic and can result in the release of heat, formation of hydrogen gas bubbles, and the production of sodium hydroxide solution.

Potassium (option B), calcium (option C), and magnesium (option D) also react with oxygen and water, but sodium is generally more reactive than these metals, exhibiting a more vigorous reaction.

Acetone is a common solvent used in nail polish removers due to its ability to dissolve nail polish quickly.

Prokaryotes: contain a single chromosome and cell division occurs through fission or budding. The usual method of prokaryote cell division is termed binary fission. The prokaryotic chromosome is a single DNA molecule that first replicates, then attaches each copy to a different part of the cell membrane. 
Bacteria: Bacteria are prokaryotic organisms that lack a membrane-bound nucleus and other membrane-bound organelles. They are considered primitive because they have an incipient nucleus and divide similarly to amitosis.
Primitive: Primitive means characteristic of an early state, especially in being crude or uncivilized. In science, primitive can also mean characteristic of an early stage of development or evolution.

In genetics, a backcross involves crossing an F1 hybrid individual with one of its parents or an organism genetically similar to one of its parents. The purpose of a backcross is to reintroduce traits from one parent into the hybrid offspring. It is often used to transfer desirable traits from the parent back to the hybrid or to recover a specific parental genotype.

X chromosomes are larger than Y chromosomes in humans. The Y chromosome is smaller and carries fewer genes compared to the X chromosome.

The bottleneck effect refers to a sudden reduction in the size of a population, leading to a loss of genetic variation. This reduction can occur due to a natural disaster, disease outbreak, or other events that drastically reduce the population's size.

The inflorescence of wheat is (d) Spike. Wheat plants produce a spike inflorescence, which is a dense, elongated structure consisting of multiple florets attached directly to the main stem without any individual stalks. The spike of wheat contains both male and female reproductive structures, with the florets arranged tightly along the central stem. Each floret has stamens (male parts) and a pistil (female part) enclosed within protective bracts. This spike inflorescence is characteristic of wheat and plays a crucial role in the reproduction and formation of grains.

The correct answer is C: Intercalary meristem.

Intercalary meristem is the meristem present at the base of leaves or internodes on twigs. It is a specialized type of meristem found in certain plants, particularly monocots. Intercalary meristem is responsible for the growth and elongation of internodes in the stem or the base of leaves.

Unlike apical meristem, which is located at the tips of shoots and roots and contributes to primary growth, and cambium, which is a lateral meristem involved in secondary growth, intercalary meristem is specific to certain regions of the plant. It allows for elongation and growth of the stem or leaf base, contributing to overall plant development.

Epidermis, on the other hand, is the outermost layer of cells in plants that covers the surfaces of leaves, stems, and roots. It functions as a protective barrier and helps regulate gas exchange and water loss. Epidermis is not directly associated with meristematic activity or growth at the base of leaves or internodes.

Chlorophyll is the pigment responsible for the absorption of light in plants. It is a group of green pigments found in the chloroplasts of plant cells. Chlorophyll absorbs light energy from the sun and plays a critical role in photosynthesis, where it captures light energy and converts it into chemical energy that can be used by the plant to produce glucose and oxygen.

The other options mentioned are not pigments but different plant structures or tissues. Stoma refers to the small openings on the surface of leaves that allow for gas exchange. Xylem and phloem are vascular tissues responsible for the transport of water, nutrients, and sugars throughout the plant.