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NEET Exam  >  NEET Tests  >  P. Bahadur Test: States of Matter (Old NCERT) - NEET MCQ

P. Bahadur Test: States of Matter (Old NCERT) - NEET MCQ


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25 Questions MCQ Test - P. Bahadur Test: States of Matter (Old NCERT)

P. Bahadur Test: States of Matter (Old NCERT) for NEET 2024 is part of NEET preparation. The P. Bahadur Test: States of Matter (Old NCERT) questions and answers have been prepared according to the NEET exam syllabus.The P. Bahadur Test: States of Matter (Old NCERT) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for P. Bahadur Test: States of Matter (Old NCERT) below.
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P. Bahadur Test: States of Matter (Old NCERT) - Question 1
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The average Kinetic energy and Thermal energy are proportional to the:

Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 1
  • The average KE and Thermal energy are proportional to absolute temperature.
  • When a substance is heated, some of the absorbed energy is stored within the particles, while some of the energy increases the motion of the particles. This is registered as an increase in the temperature of the substance.
P. Bahadur Test: States of Matter (Old NCERT) - Question 2
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Above the Critical temperature (TC) of carbon dioxide:

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Tc is the highest Temp where a gas can exist in liquid state. Above this no liquid state exist

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P. Bahadur Test: States of Matter (Old NCERT) - Question 3
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A student forgot to add the reaction mixture to the round bottomed flask at 27 °C but instead he/she placed the flask on the flame. After a lapse of time, he realized his mistake, and using a pyrometer he found the temperature of the flask was 477 °C. What fraction of air would have been expelled out?

Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 3

Let the volume of  air in the  flask at 27° C be V1 & that of the same amount of the gas at 477° C be V2.
According to charle’s law
V2/T2  =  V1/ T1   …………………(1)
Volume of gas expelled out = V2 – V1,
Then fraction of the gas expelled out = (V2 – V1 ) / V2 = 1- (V1/ V2)     …………….(2)
Also from equation (1)  V1/ V2 = T1/ T2   …………..(3)
Substituting the values of (3) in (2), we get
Fraction of the air expelled  = 1- T1/ T2 = (T2 – T1)/ T2
= 750- 300 /750 = 0.6
Hence, fraction of air expelled out is 0.6 or 3/5

P. Bahadur Test: States of Matter (Old NCERT) - Question 4
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The pressure of a 1:4 mixture of dihydrogen and dioxygen enclosed in a vessel is one atmosphere. What would be the partial pressure of dioxygen?
Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 4

PH2+PO2 , PH2=1 atm and PH2 V=(1/2)RT While PO2V=(4/32)RT

P. Bahadur Test: States of Matter (Old NCERT) - Question 5
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The ease with which the electron cloud of a particle can be distorted is called its
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The polarizability in isotropic media is defined as the ratio of the induced dipole moment of an atom to the electric field that produces this dipole moment.

P. Bahadur Test: States of Matter (Old NCERT) - Question 6
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Gases have much lower density than the solids and liquids because
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In gases thermal energy overcomes the the attractive intermolecular forces.

P. Bahadur Test: States of Matter (Old NCERT) - Question 7
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The three states of matter of H2O are in equilibrium at
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Triple point is the point where all the three states coexist in equilibrium.

P. Bahadur Test: States of Matter (Old NCERT) - Question 8
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Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar. (R = 0.083 bar dm3K−1mol−1)
Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 8

PV=nRT

P. Bahadur Test: States of Matter (Old NCERT) - Question 9
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As the temperature increases, average kinetic energy of molecules increases. What would be the effect of increase of temperature on pressure provided the volume is constant?
Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 9

P α T at constant volume.

P. Bahadur Test: States of Matter (Old NCERT) - Question 10
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Molecules in the interior of liquid experience intermolecular
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Net force on the molecules present inside in bulk is zero.

P. Bahadur Test: States of Matter (Old NCERT) - Question 11
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Charles’ law states that pressure remaining constant, the volume of a fixed mass of a gas is
Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 11

P α T (at constant V).

P. Bahadur Test: States of Matter (Old NCERT) - Question 12
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Surface tension decreases as the temperature is raised because
Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 12

Surface tension decreases as the temperature is raised because Increase in temperature increases the kinetic energy of the molecules and effectiveness of intermolecular attraction decreases.

P. Bahadur Test: States of Matter (Old NCERT) - Question 13
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Calculate the total number of electrons present in 1.4 g of dinitrogen gas.
Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 13

moles of N2 =1.4/28. And 1 mole of N2= 6.022x1023 molecules of N2 And 1 molecule of N2 has 14 electrons

P. Bahadur Test: States of Matter (Old NCERT) - Question 14
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Gases possess characteristic critical temperature which depends upon the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases. From the data what would be the order of liquefaction of these gases? Start writing the order from the gas liquefying first 

Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 14

Tc=8a/27Rb. As Tc increases ‘a’ increases means force of attraction between molecules also increase hence liquification increases.

P. Bahadur Test: States of Matter (Old NCERT) - Question 15
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Surface tension results because
Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 15

Surface tension results because a liquid tends to minimize the number of molecules at the surface

P. Bahadur Test: States of Matter (Old NCERT) - Question 16
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Gay Lussac’s law states that at constant volume, pressure of a fixed amount of a gas
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P α T (at constant V).​

P. Bahadur Test: States of Matter (Old NCERT) - Question 17
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Viscous force is
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Viscous force is directly proportional to area and velocity gradient.

P. Bahadur Test: States of Matter (Old NCERT) - Question 18
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The van der Waals Equation adjusts the measured volume
Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 18

nb is subtracted

P. Bahadur Test: States of Matter (Old NCERT) - Question 19
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Domestic power supply in India is
Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 19

Domestic power supply in India is 220 V 50 Hz

P. Bahadur Test: States of Matter (Old NCERT) - Question 20
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Capillarity results from a competition between the
Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 20

It results because intermolecular forces within the liquid (cohesive forces) and those between the liquid and the tube walls (adhesive forces)

P. Bahadur Test: States of Matter (Old NCERT) - Question 21
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The statements for laws of chemical combinations are given below. Mark the statement which is not correct.
Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 21

Law of Conservation of Mass states that matter can neither be created nor destroyed. The total mass, that is, the sum of the mass of the reacting mixture and the products formed remains constant. 
Law of Definite Proportions states that the proportion of elements by weight in a given compound will always remain exactly the same. 
Gay Lussac’s Law of Gaseous Volume states that in a gaseous system, when the reactants combine together they always do so in volumes which bear a simple ratio to one another and to the volume of the products, under similar conditions of temperature and pressure.
Avogadro’s Law states that under the same conditions of temperature and pressure, the equal volume of all the gases contains an equal number of molecules.
Thus statement C is for Law of definite proportion
option C is correct

P. Bahadur Test: States of Matter (Old NCERT) - Question 22
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Water has high surface tension and high capillarity because of
Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 22

Water molecules form extensive Hydrogen Bonds.

P. Bahadur Test: States of Matter (Old NCERT) - Question 23
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The van der Waals Equation adjusts the measured pressure
Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 23

an2/V2 is added.

P. Bahadur Test: States of Matter (Old NCERT) - Question 24
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Atmospheric pressures recorded in different cities are as follows: Consider the above data and mark the place at which liquid will boil first. 

Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 24

Shimla has lowest atmospheric pressure, hence liquidwill boil first in this city. Boiling of a liquid takes place, when the vapour pressure becomes equal to the atmospheric pressure.s.

P. Bahadur Test: States of Matter (Old NCERT) - Question 25
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Which curve in Figure represents the curve of ideal gas? 

Detailed Solution for P. Bahadur Test: States of Matter (Old NCERT) - Question 25

for ideal gas PV=constant.

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