Integration, Differentiation, Errors And Significant Figures MCQ Level -1 - Class 11 MCQ

If L= 2.331 cm, B - 2.1 cm, then L + B is equal to

A plate has a length (5 ± 0.1) cm and breadth(2 ± 0.01) cm. Then the area of the plate is

The number of significant figures in all the givennumbers 25.12, 2009, 4.156 and 1.217 x 10^-4 is

An object, moving with a speed of 6.25 m/s, isdecelerated at a rate given by

where v isthe instantaneous speed. The time taken by the object,to come to rest, would be

The position of a particle x (in metre) at a time t secondis given by the relation r = (3tiˆ - t2 ˆj + 4kˆ) . Calculatethe magnitude of velocity of the particle after 5s.

A particle moves along with x-axis. The position x ofparticle with respect to time t from origin given by x =b₀ + b₁t + b₂ t². The acceleration of particle is

The acceleration a of a particle starting from rest varieswith time according to relation a = αt + β . The velocityof the particle after a time t will be

A particle moves along a straight line such that itsposition x at any time t is x = 6t² -t³. Where x in metreand t is in second, then

Displacement (x) of a particle is related to time (t) as x = at + bt2 - ct3 where a,b and c are constants of the motion. Thevelocity of the particle when its acceleration is zero isgiven by

Acceleration of a body when displacement equation is3s = 9t + 5t² is

The velocity of particle is v = v₀ + gt + ft². If its positionis x = 0 at t = 0, then its displacement after unit time(t = 1) is

The coordinates of a moving particle at any time t are given by x = αt3 and y = βt3 . The speed of particle attime t is given by

A particle located at x = 0 at time t = 0, starts movingalong the position x-direction with a velocity v that varies as .The displacement of the particle varies withtime as

The displacement of particle is given by

What is its acceleration?

The relation between time t and distance x ist = ax² + bx, where a and b are constants. Theacceleration is

A particle moves along x - axis asx = 4 (t - 2) + a (t - 2)² Which of the following is true?

If the velocity of a particle is given by v = (180 -16x)^1/2ms^-1, then its acceleration will be

A particle moves along x-axis in such a way that itscoordinate (x) varies with time t according to theexpression x = 2 -5t + 6t² m, the initial velocity of theparticle is

A particle moves along a straight line such that itsdisplacement at any time t is given by s = t³ - 6t² +3t + 4. The velocity when its acceleration is zero is

The displacement s of a particle is proportional to thefirst power of time t, i.e.,sa t; then the acceleration ofthe particle is

The displacement x of particle moving in one dimensionunder the action of a constant force is related to time tby the equation , where x is in metres and tis in seconds, Find the displacement of the particlewhen its velocity is zero

For motion of an object along the x-axis, the velocity vdepends on the displacement x as v = 3x² - 2x, thenwhat is the acceleration at x = 2m.