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Test: Hydrogen Bonding (June 2) - NEET MCQ


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10 Questions MCQ Test - Test: Hydrogen Bonding (June 2)

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Test: Hydrogen Bonding (June 2) - Question 1

Direction (Q. Nos. 1-12) This section contains 12 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. Which of the following compounds are soluble in H2O ? 

Detailed Solution for Test: Hydrogen Bonding (June 2) - Question 1




All these are soluble in water due to intermolecular H-bonding.

Test: Hydrogen Bonding (June 2) - Question 2

In which of the following boiling point of Column I is not higher than that of Column II?

Detailed Solution for Test: Hydrogen Bonding (June 2) - Question 2

(a) Intermolecular H-bonding, boiling point increases with molecular weight for compounds within the same family.
(b) H-bonding is absent is CH3CH2CH3.
(c) Methanol is the larger molecule but H2O has more H-bonding because of two O—H bonds.
Thus, boiling point of H2O(ll) > CH3OH(l).
(d) Molecular weight of butanol is much higher and overcomes attractive forces of butanol.

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Test: Hydrogen Bonding (June 2) - Question 3

In dimer formation of which O-atom(s) is/are involved through H-bonding?

Detailed Solution for Test: Hydrogen Bonding (June 2) - Question 3

Test: Hydrogen Bonding (June 2) - Question 4

In the following alcohol, which — OH group is involved to the maximum extent in H-bonding?

Detailed Solution for Test: Hydrogen Bonding (June 2) - Question 4

O — H group is attached to (ene) is m ost a cidic and thus, has maximum intermolecular H-bonding.

Test: Hydrogen Bonding (June 2) - Question 5

What is the dominant intermolecular force or bond that must be overcome in converting liquid CH3CH2OH to vapours?

Detailed Solution for Test: Hydrogen Bonding (June 2) - Question 5

CH3CH2OH is in liquid state due to association as a result of intermolecular H-bonding.

Test: Hydrogen Bonding (June 2) - Question 6

Number of water molecules directly attached to one water molecule is

Detailed Solution for Test: Hydrogen Bonding (June 2) - Question 6


One water molecule is directly attached to four water molecules. Thus, coordination number of water is 4.

*Multiple options can be correct
Test: Hydrogen Bonding (June 2) - Question 7

Direction (Q. Nos. 13-16) This section contains 4 multiple choice questions. Each question has four choices (a), (b), (c) and (d) 
(Multiple Answer Correct)

Q. In which of the following I is more volatile than II? 

Detailed Solution for Test: Hydrogen Bonding (June 2) - Question 7


I. Intermolecular H-bonding makes boiling point higher than that of I. Thus, I is more volatile 

II. Ortho nitrophenol is more volatile than para nitrophenol because O-Nitrophenol has intramolecular hydrogen bonding whereas para nitrophenol has inter molecular H bonding and so boils relatively at higher temperature
(c) BP of H2O > > H2S
(d) BP of CH3CH2OH (due to H-bonding) > > CH3— O — CH3 

*Multiple options can be correct
Test: Hydrogen Bonding (June 2) - Question 8

Hydrogen bonding plays a central role in the following phenomenon
(Multiple Answer Correct)

[JEE Advanced 2014]

Detailed Solution for Test: Hydrogen Bonding (June 2) - Question 8

(a) When liquid water changes to ice, there is an air gap inside the cage formed due to intermolecular H-bonding. Thus, volume of ice > volume of water.


Hence, density (ice) < density (water).
Thus, ice floats on water - hydrogen bonding plays its role.
(b) In gaseous phase, basicity of 1° < 2° < 3° amines due to increase of electron density at N-atom

But in aqueous (H2O) solvent, RNH2 is stabilised by solvation. Thus 1° amine is more

basic than 3° amine (3° < 1° < 2°) amines.
(c) l+ (positive inductive effect) explains this

Dimer due to intermolecular H- bonding.

*Multiple options can be correct
Test: Hydrogen Bonding (June 2) - Question 9

Out of

Q. unstable compound is/are 

Detailed Solution for Test: Hydrogen Bonding (June 2) - Question 9

I. CCI3CH (OH)2 with two — OH groups on same carbon atom is stable due to intramolecular H-bonding.



Test: Hydrogen Bonding (June 2) - Question 10

Direction (Q. Nos. 17) Choice the correct combination of elements and column I and coloumn II  are given as option (a), (b), (c) and (d), out of which ONE option is correct.

Q. Match the species in Column I with rank order of their boiling point in Column II. (Species with lowest boiling points is at SN1).

Detailed Solution for Test: Hydrogen Bonding (June 2) - Question 10

n-butane lacks H-bonding. Hence, its boiling point is least. 

due to difference in polar H+ for H-bonding.
Boiling point of CH3CH2CH2CH2OH > H2O due to much larger size of alcohol.

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