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Properties of Acids & Bases - Free MCQ Practice Test with solutions, UPSC


MCQ Practice Test & Solutions: 12-Minute Test: Properties of Acids & Bases (15 Questions)

You can prepare effectively for UPSC Science & Technology for UPSC CSE with this dedicated MCQ Practice Test (available with solutions) on the important topic of "12-Minute Test: Properties of Acids & Bases". These 15 questions have been designed by the experts with the latest curriculum of UPSC 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 12 minutes
  • - Number of Questions: 15

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12-Minute Test: Properties of Acids & Bases - Question 1

Turmeric, a natural indicator, turns what color in the presence of bases?

Detailed Solution: Question 1

Turmeric solution or paper turns reddish brown when exposed to a base. Unlike acids, turmeric does not change color with acidic substances.

12-Minute Test: Properties of Acids & Bases - Question 2

Acids turn blue litmus :

Detailed Solution: Question 2

Blue litmus paper turns red under acidic conditions and red litmus paper turns blue under basic or alkaline conditions

12-Minute Test: Properties of Acids & Bases - Question 3

Which of the following does not conduct electricity?

Detailed Solution: Question 3

Distilled water do not conduct electricity. The reason is that a liquid conducts electricity is by the positively or negatively charged ions that are actually moving from one of the electrodes to the other, carrying charge (electricity) with them.

12-Minute Test: Properties of Acids & Bases - Question 4

Aqueous solution of sodium hydroxide turns blue litmus:

Detailed Solution: Question 4

Since Sodium hydroxide is a base and thus it has no effect on a blue litmus paper but it changes red litmus to blue.

12-Minute Test: Properties of Acids & Bases - Question 5

Which of the following compound can turn blue litmus solution red?​

Detailed Solution: Question 5

- Acids and Bases: Blue litmus turns red in the presence of an acid.
- Identifying the Acid:
- Mg(OH)2: Magnesium hydroxide is a base.
- NaOH: Sodium hydroxide is a strong base.
- NH4OH: Ammonium hydroxide is a weak base.
- CH3COOH: Acetic acid is a weak acid.
- Correct Answer: Acetic acid (CH3COOH) can turn blue litmus red because it is an acid.

12-Minute Test: Properties of Acids & Bases - Question 6

The colour of phenolphthalein in acids is:

Detailed Solution: Question 6

Phenolphthalein is often used as an indicator in acid–base titrations. For this application, it turns colourless in acidic solutions and magenta in basic solutions.

12-Minute Test: Properties of Acids & Bases - Question 7

An element common to all acids is

Detailed Solution: Question 7

All acids contain hydrogen, but not all hydrogen-containing compounds are acids. Most acids also contain oxygen.

12-Minute Test: Properties of Acids & Bases - Question 8

Acids change the colour of methyl orange to:

Detailed Solution: Question 8

Methyl orange is a pH indicator frequently used in titration because of its clear and distinct colour variance at different pH values. Methyl orange shows red colour in acidic medium and yellow colour in basic medium. Because it changes colour at the pH of a mid strength acid, it is usually used in titration for acids. Unlike a universal indicator, methyl orange does not have a full spectrum of colour change, but it has a sharp end point.

12-Minute Test: Properties of Acids & Bases - Question 9

Which of the following is an olfactory indicator?

Detailed Solution: Question 9

An olfactory indicator is a material whose smell varies reliant on whether it is mixed with an acidic or basic solution. Olfactory indicators mainly used in laboratory to test whether a solution is a base or an acid. Onion is an example of olfactory indicators. 

12-Minute Test: Properties of Acids & Bases - Question 10

Which gas is released when acids react with metal carbonates?​

Detailed Solution: Question 10

As metal carbonates react with acid, a neutralisation reaction happens. Salt, water, and carbon dioxide are produced. This can be expressed in the following general equation:

metal carbonate + acid → salt + water + carbon dioxide

12-Minute Test: Properties of Acids & Bases - Question 11

Identify the type of reaction: HCl + NaOH → NaCl + H2O

Detailed Solution: Question 11

Reaction of a strong acid with strong base is called neutralization reaction which produces salt and water,

HCl + NaOH → NaCl + H2O

This equation is already balanced.

12-Minute Test: Properties of Acids & Bases - Question 12

Carbon dioxide is an example of:

Detailed Solution: Question 12

The property of carbon dioxide to behave like an acid and react with an alkali makes it an acidic oxide. Acidic oxides are a type of oxides that react with alkalis to form salt and water.

12-Minute Test: Properties of Acids & Bases - Question 13

Marble chips reacts with a solution to produce a gas which turns lime water milky. So the solution contains:​

Detailed Solution: Question 13

Marble chips are made of calcium carbonate (CaCO3). When calcium carbonate reacts with an acid, carbon dioxide gas is released, which turns lime water milky due to the formation of calcium carbonate.

If dilute hydrochloric acid (HCl) is used, the reaction proceeds smoothly and continuously because the product formed, calcium chloride (CaCl2), is soluble in water and does not form any coating on the marble chips.

Reaction:
CaCO3 + 2HCl → CaCl2 + CO2 + H2O

The carbon dioxide gas evolved turns lime water milky:
CO2 + Ca(OH)2 → CaCO3 + H2O

12-Minute Test: Properties of Acids & Bases - Question 14

Identify ‘X’ in the reaction: 2HCl + CuO → X + H2O​

Detailed Solution: Question 14

When copper oxide and dilute hydrochloric acid are mixed the blue green solution is formed. 
The reaction is :- 
CuO + 2HCl → CuCl2 + H2O

12-Minute Test: Properties of Acids & Bases - Question 15

Which of the following base is used in the manufacture of bleaching powder?

Detailed Solution: Question 15

Bleaching powder is prepared by passing chlorine gas over dry slaked lime (calcium hydroxide).

Chemical Equation:

Cl2 + Ca(OH)2 → CaOCl2 + H2O

Here,

  • Ca(OH)2 = Calcium hydroxide (slaked lime)
  • Cl2 = Chlorine
  • CaOCl2 = Bleaching powder
  • H2O = Water

 So, the base used is Calcium hydroxide.

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