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AP Police Exam  >  AP Police Test  >   Constable Mock Test Series 2027  >  AP Police Constable Mock Test - 4 - AP Police MCQ

AP Police Constable Mock Test - 4 Free Online Test 2026


Full Mock Test & Solutions: AP Police Constable Mock Test - 4 (200 Questions)

You can boost your AP Police 2026 exam preparation with this AP Police Constable Mock Test - 4 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of AP Police 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 180 minutes
  • - Total Questions: 200
  • - Analysis: Detailed Solutions & Performance Insights

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AP Police Constable Mock Test - 4 - Question 1
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The average of 13 numbers is 60. The average of the first 7 numbers is 57 and that of the last 7 numbers is 65. What is the 7th number?

Detailed Solution: Question 1

7 × 57 + 7 × 65 = 854
Since the 7th number came twice, it is added two times.
So the answer = 854 – 13 × 60 = 74
Hence, Option D is correct.

AP Police Constable Mock Test - 4 - Question 2
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What is the area of a right-angled triangle with 12 meter base and 13 meter hypotenuse?

Detailed Solution: Question 2

Height of the triangle = √(132 – 122) = 5 meters


Hence, Option A is correct.

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AP Police Constable Mock Test - 4 - Question 3
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The HCF of two numbers is 15 and their LCM is 225. If one of the number is 75, then the other number is :

Detailed Solution: Question 3

Using Rule 1 :
1st number × 2nd number = L.C. M. × H.C.F,
First number × Second number = HCF × LCM
⇒ 75 × Second number = 15 × 225

AP Police Constable Mock Test - 4 - Question 4
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Shree bought 200 articles at the same price. He sold some of them at a 20% loss and the rest at a 40% loss. If he incurred a loss of 25%, how many articles did he sell at a 40% loss?

Detailed Solution: Question 4


At 20% loss : At 40% loss = 15% : 5% = 3 : 1

Hence, Option B is correct.

AP Police Constable Mock Test - 4 - Question 5
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If  the value of a3 + b3 is equal to

Detailed Solution: Question 5


⇒ a2 + b2 = ab
⇒ a2 – ab + b2
= 0
∴  a3 + b3 = (a + b) (a2 – ab + b2) = 0 

AP Police Constable Mock Test - 4 - Question 6
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The difference between the squares of two numbers is 256000 and the sum of the numbers is 1000. The numbers are

Detailed Solution: Question 6

Let us assume the numbers are a and b.
According to question,
a2 - b2 = 256000 .......................(1)
and a + b = 1000 .........................(2)
On dividing the Equation (1) with Equation (2),
(a2 - b2)/(a + b) = 256000/1000
(a2 - b2)/(a + b) = 256
(a + b)(a - b)/(a + b) = 256
a - b = 256...............................(3)
Add the equation (2) and (3), we will get
a + b + a - b = 1000 + 256
2a = 1256
a = 628
Put the value of a in equation (2), we will get
658 + b = 1000
b = 1000 - 628
b = 372
So answer is 628 , 372. 

AP Police Constable Mock Test - 4 - Question 7
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Directions: In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer.
I. x2 + 11x + 28 = 0 
II. 2y2 + 30y + 112 = 0

Detailed Solution: Question 7

I. x2 + 11x + 28 = 0
x2 + 4x + 7x + 28 = 0
x = – 4 and – 7

II. 2y2 + 30y + 112= 0
2y2 + 14y + 16y + 112 = 0

Answer: x ≥ y
Hence, Option C is correct.

AP Police Constable Mock Test - 4 - Question 8
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In an A.P. twenty fifth term is 70 more than to fifteenth term. Find the common differences.

Detailed Solution: Question 8

Concept:
The nth number in A.P. series = Tn = a + (n - 1)d
Where 'a' is the first number of the series and 'd' is the common difference

Calculation:
Let the first element of A.P. is 'a' and common difference is 'd'

Given:
T25 = T15 + 70
According to the question,
T25 = T15 + 70
⇒ a + (25 – 1)d = a + ( 15 – 1)d + 70
⇒ 24d – 14d = 70
⇒ 10d = 70
⇒ d = 7
∴ The common difference is 7.

AP Police Constable Mock Test - 4 - Question 9
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On which number of term does 78 falls in the A.P. 3, 8, 13, 18, … is 78?

Detailed Solution: Question 9

Given, 3, 8, 13, 18, … is the AP.
a = 3
d = a(2) – a(1) = 8 − 3 = 5
Let a(n) term be 78.
a(n) = a + (n − 1) x d
78 = 3 + (n − 1) x 5
75 = (n − 1) x 5
(n − 1) = 15
n = 16

AP Police Constable Mock Test - 4 - Question 10
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What is the sum of first five prime numbers?

Detailed Solution: Question 10

First five prime numbers are 2, 3, 5, 7, 11. Sum - 28

AP Police Constable Mock Test - 4 - Question 11
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 then the value of x is:

Detailed Solution: Question 11

AP Police Constable Mock Test - 4 - Question 12
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If all the digits of a three-digit number are even and different, how many such numbers are possible?

Detailed Solution: Question 12

Total digits = 5 → 0, 2, 4, 6, 8
Possible numbers for hundreds place = 4 = 2, 4, 6 and 8
Possible numbers for tens place = 4
Possible numbers for ones place = 3
So the answer = 4 × 4 × 3 = 48

AP Police Constable Mock Test - 4 - Question 13
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If 18 binders bind 900 books in 10 days, How many binders will be required to bind 660 books in 12 days?

Detailed Solution: Question 13

According to given question,
Since 900 books are bonded in 10 days by 18 binders.
∴ 1 books are bonded in 10 days by 18 / 900 binders.
∴ 1 books are bonded in 1 days by 18 x 10 / 900 binders.
∴ 660 books are bonded in 1 days by 18 x 10 x 660 / 900 binders.
∴ 660 books are bonded in 12 days by 18 x 10 x 660 / 12 x 900 binders.
∴ 660 books are bonded in 12 days by 18 x 10 x 55 / 900 binders.
∴ 660 books are bonded in 12 days by 18 x 55 / 90 binders.
∴ 660 books are bonded in 12 days by 55 / 5 binders.
∴ 660 books are bonded in 12 days by 11 binders.

AP Police Constable Mock Test - 4 - Question 14
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A, B, C are the three angles of a Δ. If A − B = 15° and B − C = 30°. Then ∠A is equal to :

Detailed Solution: Question 14

Since A, B and C are the angles of a Δ,
∴ A + B + C = 180° .................... (1)
According to question,
A – B = 15° ;
⇒ A = B + 15°...................(2)
B – C = 30°;
⇒ B = C + 30°;....................(3)
Put the value of B from equation (2) in Equation (1), we will get
∴ A = B + 15°
A = C + 30° + 15°
A = C + 45° ......................(4)
From a equation,
∴ A + B + C = 180°
⇒ (C + 45°) + (C + 30°) + C = 180°
⇒ 3C + 45° + 30° = 180°
⇒ 3C = 180° – 75° = 105°
⇒ C = 35° ...........................(5)
From equation (4)
A = C + 45°
Put the value of C from equation (5) , we will get
∴ ∠A = 35° + 45° = 80°.

AP Police Constable Mock Test - 4 - Question 15
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If a 640 meters long train crosses a 160 meters long platform in 25 seconds, what is the speed of the train?

Detailed Solution: Question 15


Hence, Option D is correct.

AP Police Constable Mock Test - 4 - Question 16
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If two pipes function simultaneously, a tank is filled in 12 hours. One pipe fills the tank 10 hours faster than the other. How many hours does the faster pipe alone take to fill the tank?

Detailed Solution: Question 16

Using Rule 1,

If the slower pipe fills the tank in x hours, then

Required time = 30 - 10 = 20 hours

AP Police Constable Mock Test - 4 - Question 17
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A can run 1 km in 4 min.54 sec. and B in 5 min. How many meters start can A give B in a km race so that the race may end in a dead heat?

Detailed Solution: Question 17

Distance covered by B in 6 sec. =(1000/300*6)m = 20m
∴  A beats B by 20 m.
For a dead heat race, A must give B a start of 20m.

AP Police Constable Mock Test - 4 - Question 18
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Sumit, Ravi and Puneet invest ₹ 45000, ₹ 81000 and ₹ 90000 respectively to start a business. At the end of the year the total profit is ₹ 4800. 30% of the total profit gives in charity and rest is divided among them. What will be the share of Sumit?

Detailed Solution: Question 18

Investment of Sumit = Rs.45000
Duration of Sumit = 1 year
Investment of Ravi = Rs.81000
Duration of Sumit = 1 year
Investment of Puneet = Rs.90000
Duration of Puneet = 1 year
Ratio of profits = Ratio of investments...


Given, Total profit = Rs.4800 30% of total profit donated to charity
Amount donated to charity = 30% of Rs.4800 = Rs.1440...
Remaining amount = Rs.4800-1440 = Rs.3360
Let the profits of Sumit, Ravi and Puneet be Rs.5x, Rs.9x and Rs.10x respectively....
Total profit = Rs.5x+9x+10x = Rs.24x...
Given, 24x = 3360 => x = 140 Therefore, Profit of Sumit = 5x = 5*140 = Rs.700.

AP Police Constable Mock Test - 4 - Question 19
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A shopkeeper sold an article for Rs. 20,400 and incurred a loss of 15%. At what price should he sell it so that he suffers only 5% loss?

Detailed Solution: Question 19


Hence, Option C is correct.

AP Police Constable Mock Test - 4 - Question 20
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Directions: Find the wrong term in the given series.

12      24      48      120      360      1260

Detailed Solution: Question 20


There should be 16 in place of 12.
Hence, Option A is correct. 

AP Police Constable Mock Test - 4 - Question 21
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The angles of elevation of the tops of two vertical towers as seen from the middle point of the lines joining the foot of the towers are 45° & 60°.The ratio of the height of the towers is

Detailed Solution: Question 21


Tan(60) = h1/AB
=> h1 = √3AB
Tan(45) = h1/BC
=> h2 = BC
h1/ h2 = √3/1
=> h1 : h2 = √3 : 1

AP Police Constable Mock Test - 4 - Question 22
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Nitu did 1/2 of the work yesterday and one-third of the work today. How much work will she have to do tomorrow to complete the work?

Detailed Solution: Question 22

AP Police Constable Mock Test - 4 - Question 23
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A card is selected randomly from a deck of cards. What is the probability that the card is numbered?

Detailed Solution: Question 23

Total cards = 52
Numbered cards = 2 to 10
Total numbered cards = 4 × 9 = 36

AP Police Constable Mock Test - 4 - Question 24
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In a dairy farm, 40 cows eat 40 bags of husk in 40 days. In how many days one cow will eat one bag of husk?

Detailed Solution: Question 24

According to question,
40 cows eat 40 bags of husk in 40 days.
1 cows eat 40 bags of husk in 40 x 40 days.
1 cows eat 1 bags of husk in 40 x 40 / 40 days.
1 cows eat 1 bags of husk in 40 days.

AP Police Constable Mock Test - 4 - Question 25
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In the adjoining figure ∠A + ∠B + ∠C + ∠D + ∠E + ∠F = ?

Detailed Solution: Question 25

In ΔACE
∠A + ∠C + ∠E = 180°
Similarly in ΔDFB
∠D + ∠F + ∠B = 180°
∴ (∠A + ∠C + ∠E) + (∠D + ∠F + ∠B) = 360°
∠A + ∠B + ∠C + ∠D + ∠E + ∠F = 360°

AP Police Constable Mock Test - 4 - Question 26
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If the area of a square is the same as the area of a rectangle and the side of the square is twice the breadth of the rectangle, what is the ratio of the length to the breadth of the rectangle?

Detailed Solution: Question 26

Let the breadth of the rectangle = B
Length of the rectangle = L
L × B = 2 B × 2 B
L = 4B
L : B = 4 : 1
Hence, Option C is correct.

AP Police Constable Mock Test - 4 - Question 27
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Manish has a total of 160 coins of 10 rupees and 5 rupees. If he has a combined amount of Rs. 1280, how many 5 rupee coins does he have?

Detailed Solution: Question 27


10 rupee coins : 5 rupee coins = 480 : 230 = 3 : 2

Hence, Option C is correct.

AP Police Constable Mock Test - 4 - Question 28
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What is the midpoint coordinate of (1,2) and (5,2)?

Detailed Solution: Question 28

Midpoint formula:

AP Police Constable Mock Test - 4 - Question 29
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Directions: In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer.
I. x2 – 1200 = 169
II. y + 122 = 159

Detailed Solution: Question 29

I. x2 – 1200 = 169
x2 = 1200 + 169
x2 = 1369 = √(1369) = ± 37

II. y + 122 = 159
y = 159 – 122 = 37
Answer: x ≤ y
Hence, Option B is correct.

AP Police Constable Mock Test - 4 - Question 30
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log10x + log10y = z, then x is equal to ?

Detailed Solution: Question 30

log10xy = z
⇒ xy = 10z
⇒ x = 10z/y 

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About this AP Police Mock Test

This mock test contains 200 questions designed to replicate the pattern, difficulty level and time pressure of the actual AP Police exam. It is part of AP Police Constable Mock Test Series 2027 on EduRev, covering all the topics that are being asked as per the current AP Police syllabus. Attempting this test under timed conditions will help you assess your exam readiness, identify subject-wise weak areas, and improve your speed and accuracy before the actual exam.

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