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Jharkhand Police Constable (Paper-II) Mock Test - 6 - Jharkhand Police Constable MCQ


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30 Questions MCQ Test - Jharkhand Police Constable (Paper-II) Mock Test - 6

Jharkhand Police Constable (Paper-II) Mock Test - 6 for Jharkhand Police Constable 2024 is part of Jharkhand Police Constable preparation. The Jharkhand Police Constable (Paper-II) Mock Test - 6 questions and answers have been prepared according to the Jharkhand Police Constable exam syllabus.The Jharkhand Police Constable (Paper-II) Mock Test - 6 MCQs are made for Jharkhand Police Constable 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Jharkhand Police Constable (Paper-II) Mock Test - 6 below.
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Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 1

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question. 120, 99, 80, 63, 48, ?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 1

1st term = 120
2nd term = 120-21 = 99
3rd term = 99-19 = 80
4th term = 80 - 17 = 63
5th term = 63 - 15 = 48

⇒ For every next term , preious term is substracteed in the order: -21, -19, -17, -15, -13,.....

So, missing term = 48 - 13 = 35

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 2

X Can finish a piece of work in 12 days while Y can do it in 15 days. If both work at it together. How much time will they take to do the work?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 2

Efficiency of A = 100 / 12 = 8.33%
Efficiency of B = 100 / 15 = 6.66%
Combined efficiency of A and B = 8.33 + 6.66 = 15%
Number of days taken by A and B, when working together = 100 / 15 = 
Note : Efficiency x Time period = Fixed amount of work
Also, in terms of percentage total work to be done is considered as 100% (in fraction it is 1), unless otherwise stated.
Alternatively : It can be done through unitary method, also.

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Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 3

Three partners shared the profit in a business in the ratio 5 : 7 : 8. They had partnered for 14 months, 8 months and 7 months respectively. What was the ratio of their investments?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 3

Let their investments be Rs. x for 14 months, Rs. y for 8 months and Rs. z for 7 months respectively.
Then, 14x : 8y : 7z = 5 : 7 : 8.
Now,

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 4

A car started from Indore to Bhopal at a certain speed. The Car missed an accident at 40Kms away from Indore, then the driver decided to reduce Car speed to 4/5 of the original speed. Due to this, he reached Bhopal by a late of 1hr 15min.Suppose if he missed an accident at 80Km away from Indore and from then he maintained 4/5 of original speed then he would reach Bhopal by a late of 1hour. Then what is the original speed of the Car?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 4

(x+40/s) + 5/4 = 40/s + 5x/4s — — — 1
(x+40/s) + 1 = 80/s + 5(x-40)/4s — — — 2
s = 40

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 5

In what time will Rs. 8000 amount to 40,000 at 4% per annum? (simple interest being reckoned)

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 5

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 6

The sum of 3 consecutive even number is 40 more than the average of these numbers. Which of the following is the 2 largest number ?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 6

X+x+2+x+4 = 40+(x+x+2+x+4)/3
3x+6 = 40+ (3x+6)/3
(9x+18 – 3x-6)/3= 40
6x + 12 = 120
X = 108/6 = 18
18+2 = 20

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 7

(17)3.5 x (17)? = 178

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 7

Let (17)3.5 x (17)x = 178.

Then, (17)3.5 + x = 178.

∴ 3.5 + x = 8

⇒ x = (8 – 3.5)

⇒ x = 4.5

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 8

The average of the first ten prime numbers, which are odd, is

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 8

Required average = (3 + 5 + 7 + 11 + 13 + 17 + 19
+ 23 + 29 + 31)/10 = 158/10 = 15.8.

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 9

What fraction is equal to 57.12% (approximately)?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 9

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 10

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 13, 32, 24, 43, 35, ?, 46, 65, 57, 76

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 10

The given sequence is a combination of two series:

  • 13, 24, 35, 46, 57
  • 32, 43, ?, 65, 76

In both series are in A.P. with common difference of 11.

So, missing term = 43 + 11 = 54.

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 11

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 6, 13, 25, 51, 101, ?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 11

1st term = 6
2nd term = (6 * 2) + 1 = 13
3rd term = (13 * 2) -1 = 25
4th term = (25 * 2) +1 = 51
5th term = (51 * 2) - 1 = 101
6th term = ?

⇒ For every even position term, the previous term is multiplied by 2 and then  1 is added and for the odd positioned term, the previous term is multiplied by 2 and 1 is substracted

So, missing term = (101 * 2) + 1 = 203.

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 12

Efficiency of Asha is 25% more than Usha and Usha takes 25 days to complete a piece of work, Asha started a work alone and then Usha joined her 5 days before actual completion of the work. For how many days Asha worked alone?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 12


∴ Number of days required by Asha to finish the work alone = 20
  ► ∴ (4 x = 4 x 5)
(Alternatively, from percentage change graphic, number of days taken by Asha will be 20% less than Usha, if efficiency of Asha is 25% more than Usha)
Now, since Asha and Usha did work together for last 5 days = 5 x 9 = 45%
(Since efficiency of Asha = 5% and Usha's efficiency = 4%)
It means Asha completed 55% work alone
∴ Number of days taken by Asha to complete 55% work = 55 / 5 = 11

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 13

A and B started a business in partnership investing Rs. 20,000 and Rs. 15,000 respectively. After six months, C joined them with Rs. 20,000. What will be B's share in total profit of Rs. 25,000 earned at the end of 2 years from the starting of the business?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 13

A : B : C
= (20,000 × 24) : (15,000 × 24) : (20,000 × 18)
= 4 : 3 : 3.
So B's Share
total share 4+3+3 = 10
B share would be 3/10

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 14

Two Cars started at same time, same place and towards same direction. First Car goes at a speed of 5km/hr in first and 7 Km/hr in second hour and repeats the cycle over the entire journey. Similarly second Car goes at 4km/hr in first hour and 9km/hr in second hour and repeats the cycle over the entire journey.Then these two Cars for the first time for after how many hours of journey?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 14

First car : 5,12,17
Second Car: 4,3,17

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 15

A sum of money invested at simple interest triples itself in 8 years at simple interest. Find in how many years will it become 8 times itself at the same rate?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 15

In 8 years, the interest earned = 200% Thus, per year interest rate = 200/8 = 25% To become 8 times we need a 700% increase 700/25 = 28 years.

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 16

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: In series 2, 6, 18, 54, ...... what will be the 8th term ?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 16

1st term = 2 x 3 = 6
2nd term = 6 x 3 = 18
3rd term = 18 x 3 = 54,.....
⇒ Series is a G.P. in which a = 2, r = 3.

∴ 8th term = ar8-1 = ar7 = 2 x 37 = (2 x 2187) = 4374.

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 17

Ajit is 3 times as efficient as Bablu, then the ratio of number of days required by each to work alone, completely?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 17

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 18

P and Q invested in a business. The profit earned was divided in the ratio 2 : 3. If P invested Rs 40000, the amount invested by Q is

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 18

Let the amount invested by Q = q.

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 19

Two Cars started at same time, same place and towards same direction. First Car goes at uniform speed of 12Km/hr. Second Car goes at speed of 4 Km/hr in first hour and increases it speed by 1 Km/hr for every hour. Then what is the distance traveled by car B when the both the Cars meet for the first time?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 19

12*x = x/2(2*4+(x-1)*1)
X= 17
D = 17*12 =204

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 20

Divide Rs. 3903 between Amar and Akbar such that Amar’s share at the end of 7 years is equal to Akbar’s share at the end of 9 years at 4% p.a. rate of compound interest.

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 20

Akbars’ share should be such that at 4% p.a. compound interest it should become equal to Amar’s share in 2 years. Checking thorugh the options it is clear that option (a) fits perfectly as 1875 would become 2028 in 2 years @4% p.a. compound interest.

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 21

If a = -2 and b = -5 then find the value of a3 + b3– a2 + b2 + 2a – 3b

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 21

a3 + b3– a2 + b2 + 2a – 3b
(-2)3 + (-5)3 – (-2)2 + (-5)2 + 2(-2) – 3(-5) = -8 -125-4+25-4+15 = -101

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 22

If 5a = 3125, then the value of 5(a – 3) is:

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 22

5a = 3125    ⇔    5a = 55

⇒ a = 5.

∴ 5(a – 3) = 5(5 – 3) = 52 = 25.

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 23

The average of the first ten odd numbers is

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 23

The sum of the first n odd numbers = n2. In this case n = 10 → Sum = 102 = 100.
Required average = 100/10 = 10.

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 24

The length of rectangle is increased by 30% and the breadth is decreased by 25%. What is the percentage change in the area of the rectangle due to this?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 24

Let Length = 100, Breadth =100 Hence, Area = 10000

Now, Length =130, Breadth = 75 Hence, Area = 130 x 75 = 9750 

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 25

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question -
90, 180, 12, 50, 100, 200, ?, 3, 50, 4, 25, 2, 6, 30, 3

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 25

Clearly the pattern is:

► 90 = 30 x 3,
► 180 = 6 x 30,
► 12 = 2 x 6,
► 50 = 25 x 2,
► 100 = 4 x 25,
► 200 = 50 x 4.

So, missing term = 3 x 50 = 150.

Alternatively,

The pattern is the combination of 2 series:

  • 90, 180, 12, 50, 100, 200, ?
  • 3, 50, 4, 25, 2, 6, 30, 3

after reversing 2nd series, i.e. 3, 30, 6, 2, 25, 4, 50, 3
on dividing term of the same position would give next term of reversed series.
i.e.

► 90/3 = 30
► 180/30 = 6
► 12/6 = 2
► 50/2 = 25
► 100/25 = 4
► 200/ 4 =50
► ?/50 = 3

So, missing term = 3 x 50 = 150.

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 26
Which article of the Indian Constitution grants all minorities, whether based on religion or language, the fundamental right to establish and administer educational institutions of their choice?
Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 26
Article 30 (1) of the Indian Constitution grants all minorities, whether based on religion or language, the fundamental right to establish and administer educational institutions of their choice. This provision ensures that minority communities can maintain their cultural and educational institutions independently.
Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 27
What is the role of the Comptroller and Auditor General of India (CAG) in relation to the audit of public corporations?
Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 27
The role of the Comptroller and Auditor General of India (CAG) in relation to the audit of public corporations includes conducting supplementary audits or test audits when necessary. Some public corporations are audited by private auditors appointed by the government.
Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 28

Which economic theory advocates a completely "hands-off" approach to trade?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 28

Laissez-faire is an economic theory that advocates minimal government intervention in economic affairs, including trade. It suggests that free markets should operate without restrictions, and the government should not interfere with the pricing, production, or distribution of goods and services.

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 29

The New Economic Policy (NEP) focused on:

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 29

The New Economic Policy emphasized privatization, reducing government intervention, and promoting market-oriented reforms.

Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 30

Which industry is responsible for the manufacturing of goods on a large scale with the help of machines?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 6 - Question 30

The manufacturing industry involves the production of goods on a large scale using machines, tools, and skilled labor. It is an essential part of economic development and provides finished products for consumption.

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