Jharkhand Police Constable (Paper-II) Mock Test - 7 - Jharkhand Police Constable MCQ

Total Valid votes are = 80% of 7500= 6000
If one has 55% vote then the other has left with 45% votes
Hence, 45% of 6000= 2700

Given:

A and B together can do a piece of work in 50 days.

A is 40% less efficient than B

Concept used:

Total work = Efficiency of the workers × time taken by them

Calculation:

Let the efficiency of B be 5a

So, efficiency of A = 5a × 60%

⇒ 3a

So, total efficiency of them = 8a

Total work = 8a × 50

⇒ 400a

Now,

60% of the work = 400a × 60%

⇒ 240a

Now,

Required time = 240a/3a

⇒ 80 days

∴ A can complete 60% of the work working alone in 80 days.

Solve this question through options.
⇒  For instance, if he travelled at 25 km/h, his original speed would have been 24 km/h.
⇒ The time difference can be seen to be 6 minutes in this case = 60 / 24 – 60 / 25 = 0.1 hrs = 6 mins

Thus, 25 km/h is the correct answer. 

So Option A is correct

Relative speed = Speed of A + Speed of B = 2 + 3 = 5 rounds per hour
(∴ they walk in opposite directions)

⇒ They cross each other 5 times in 1 hour and 2 times in 1/2 hour

∵ Time duration from 8 a.m. to 9.30 a.m. = 1.5 hour

∴ They cross each other 7 times before 9.30 a.m

In this type of question, we need to get the relative speed between them.

The relative speed of the boys = 5.5 – 5 = 0.5 km/h

The distance between them is 8.5 km.
Time = Distance/Speed
Time = 8.5/0.5 = 17 hrs

Assume that investment of C = x
Then, investment of A = 2x

A : B : C
= (20,000 × 24) : (15,000 × 24) : (20,000 × 18)
= 4 : 3 : 3.
So B's Share
total share 4+3+3 = 10
B share would be 3/10

► Let x and (12-x) litres of milk be mixed from the first and second container respectively

► Amount of milk in x litres of the the first container = .75x

► Amount of water in x litres of the the first container = .25x

► Amount of milk in (12-x) litres of the the second container = .5(12-x)

► Amount of water in (12-x) litres of the the second container = .5(12-x)

► Ratio of water to milk = [.25x + .5(12-x)] : [.75x + .5(12-x)] = 3 : 5

⇒ (.25x+6-5x)/(.75x+6-.5x) =3/5

⇒(6−.25x)/(.25x+6) =3/5

⇒30−1.25x=.75x+18

⇒2x=12

⇒x=6

► Since x = 6, 12-x = 12-6 = 6

Hence 6 and 6 litres of milk should mixed from the first and second container respectively

► Spirit in 1 litre mix of A = 5/7 litre.
► Spirit in 1 litre mix of B = 7/13 litre.
► Spirit in 1 litre mix of C = 8/13 litre. 
By rule of alligation we have required ratio X:Y

Therefore required ratio = 1/13 : 9/91
= 7:9

Part filled by first tap in 1 hour = 1/3
Part emptied by second tap 1 hour = 1/8
Net part filled by both these taps in 
1 hour
= 1/3 − 1/8 = 5/24
i.e, the cistern gets filled in 24/5 hours 
= 4.8 hours.

Part filled by pipe A in 1 hour = 1/5
Part filled by pipe B in 1 hour = 1/20
Part filled by pipe A and B in 1 hour = 
i.e., A and b together can fill the tank in 4 hours
Given that due to the leakage, it took 40 minutes more to fill the tank.
i.e., due to the leakage, the tank got filled in 
⇒ Net part filled by pipe A and B and the leak in 1 hour = 3/14
⇒ Part emptied by the leak in 1 hour = 
i.e., the leak can empty the tank in 28 hours.

A loss of 25% means a cost price of 100 corresponding to a selling price of 75. CP as a percentage of the SP would then be 133.33%

CP = 6612.5/1.15 = 5750. Selling this at 5380 would mean a loss of ₹370 on a CP of ₹ 5750.

S.I. for 1 year = Rs. (854 - 815) = Rs. 39.

S.I. for 3 years = Rs.(39 * 3) = Rs. 117.

 Principal = Rs. (815 - 117) = Rs. 698.

Given, SI = Rs 929.20
P = ?
T = 5 years
R = 8%
P = (100 x SI) / RT
⇒ (100 x 929.20) / (8 x 5)
⇒ Rs. 2323

Radius of the sphere = 6/2 = 3 cm
Radius of the cylinder = 12/2 = 6cm
Volume of the sphere 

New volume of the cylindrical vessel - Initial volume of the cylindrical vessel = Volume of the sphere
Initial height = h cm
Final height = H cm
πr²H - πr²h = 36π

Since three metal cubes of volumes 125 cm³, 64 cm³ and 27 cm³ are melted to form a new cube,
Therefore, volume of the new cube = 125 + 64 + 27 = 216 cm³
Total volume = 216 cm³
a³ = 216 cm³
a³ = 6³
On comparing, we get
a = 6
Edge = 6 cm

Ratio of the bill = 21 : 20

When there are 20 women,
Number of men = 32 and number of children = 4
Then, wages of each category would be in the following ratio 160 : 40 : 12.
Wages of men = 
Wages of women = 
Wages of children = 

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