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Jharkhand Police Constable (Paper-II) Mock Test - 10 - Jharkhand Police Constable MCQ


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30 Questions MCQ Test - Jharkhand Police Constable (Paper-II) Mock Test - 10

Jharkhand Police Constable (Paper-II) Mock Test - 10 for Jharkhand Police Constable 2024 is part of Jharkhand Police Constable preparation. The Jharkhand Police Constable (Paper-II) Mock Test - 10 questions and answers have been prepared according to the Jharkhand Police Constable exam syllabus.The Jharkhand Police Constable (Paper-II) Mock Test - 10 MCQs are made for Jharkhand Police Constable 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Jharkhand Police Constable (Paper-II) Mock Test - 10 below.
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Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 1

The number of prime factors of 510510

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 1

2*3*5*7*11*13*17 = 510510

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 2

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 2

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Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 3

Ganguly has a certain average for 4 innings. In the 5th inning, he scores 40 runs thereby increasing his average by 4 runs. His new average is

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 3

4x + 40 = 5(x + 4) → x = 20 (average after 4 innings).

Hence, new average = 20 + 4 = 24.

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 4

In a mixture of 100 litres of milk and water, 25% of the mixture is milk. How much water should be added to the mixture, so that milk becomes 20% of the mixture?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 4

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 5

There was a leakage in the container of the refined oil. If 11 kg oil leaks out per day then it would have lasted for 50 days, if the leakage was 15 kg per day, then it would have lasted for only 45 days. For how many days would the oil have lasted, if there was no leakage and it was completely used for eating purpose?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 5

Let x kg of oil is used for eating purpose, daily, then
   ► (x + 11) x 50 = + 15 x 45
   ► x = 25
∴ Total quantity of oil = (25 + 11) x 50 = 1800
∴ Required number of days = 1800 / 25 = 72
 

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 6

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 1, 2, 3, 6, 9, 18, ?, 54

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 6

1st term = 1
2nd term = 1 * 2 = 2
3rd term = 2 * 3/2 = 3
4th term = 3 * 2 = 6
5th term = 6 * 3/2 = 9
6th term = 9 * 2 =18
7th term = ?
8th term = 54

⇒ For every even position term, the previous term is multiplied by 2 and for the odd positioned term, the previous term is multiplied by 3/2

So, missing term = 18 x 3/2 = 27.

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 7

A and B can complete a task in 30 days when working together. After A and B have been working together for 11 days, B is called away and A, all by himself completes the task in the next 28 days. Had A been working alone from begining, the number of days taken by him to complete the task would have been:

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 7

Work done in 11 days = 11 / 30
Rest work = 19 / 30
1 day's work of A = 
Total number of days required to complete the whole work alone.

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 8

In a business, A and C invested amounts in the ratio 2 : 1 , whereas the ratio between amounts invested by A and B was 3 : 2 . If Rs 157300 was their profit, how much amount did B receive?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 8

Assume that investment of C = x
Then, investment of A = 2x

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 9

Two places A and B are at a distance of 480Km. Sita started from A towards B at the speed of 40Kmph. After 2 hours Gita started from B towards A at speed of 60 Kmph. They meet at a Place C then what is the difference between the time taken by them to reach their destinations from Place C?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 9

t*40+ (t-2)*60 = 480
t=6
From Place C to A = C to B = 240
Then time taken by Sita = 6hours and GIta = 4 hours
Difference = 6-4 = 2 hours

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 10

A sum of Rs. 600 amounts to Rs. 720 in 4 years at Simple Interest. What will it amount to if the rate of interest is increased by 2%?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 10

600 becomes 720 in 4 years SI —> SI per year = Rs. 30 and hence the SI rate is 5%.
At 7% rate of interest the value of 600 would become 768 in 4 years. (600 + 28% of 600)

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 11

When a positive number n is divided by 7 leaves the remainder 2, when 3n is divided by the same number, then the remainder is

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 11

N = 7+2 =9
3n = 27
27/7 = 6

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 12

The value of [(10)150 ÷ (10)146]

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 12

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 13

The mean temperature of Monday to Wednesday was 35 °C and of Tuesday to Thursday was 30 °C. If the temperature on Thursday was ½ that of Monday, the temperature on Thursday was

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 13

Monday + Tuesday + Wednesday = 3 x 35 = 105;
Tuesday + Wednesday + Thursday = 3 x 30 = 90.
Thus, Monday – Thursday = 15 and
Thursday = Monday/2 → Monday = 30 and Thursday = 15

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 14

After spending 20% on clothes, 10% on books, 9% on purchasing gift for girl friend and 7% on others, Chandra has a balance of Rs 2,700. How much money was there with him initially?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 14

Let initial Amount = Rs. 100

Money left = 100 – (20 + 10 + 9 + 7)

= Rs. (100 – 46)

= Rs. 54

This 54r = 2700

r = 50

100r = 5000

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 15

A man, a woman and a girl worked for a contractor for the same period. A man is twice efficient as a woman and a woman is thrice efficient as a girl. ₹ 10000 were given to all of them. What is the sum of money received by a woman and a girl together?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 15

Efficiency of a man : woman : girl = 6 : 3 : 1
∴ Share of a woman and girl = 

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 16

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 5,6,9, 15, ?, 40

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 16

1st term = 5
2nd term = 5 + 1 = 6
3rd term = 6 + 3 = 6 + (1 + 2) = 9
4th term = 9 + 6 = 9 + (1 + 2 + 3) = 15
5th term = x
6th term = 40

⇒ For every term previous term is added with sumation of it previous position i.e. next term = previous term + ∑ (position -1)

So, missing term = 15 + (1 + 2 + 3 + 4) = 25

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 17

Chandni and Divakar can do a piece of work in 9 days and 12 days respectively. If they work for a day alternatively, Chandni beginning, in how many days, the work will be completed?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 17

Efficiency of Chandni = 11.11%
Efficiency of Divakar = 8.33%
They do 19.44% work in 2 days.
∴ They need 10 days to do 97.22% work,
Now the rest work (2.78) was done by Chandni in 2.78 / 11.11 = 1 / 4 days
Therefore total number of days required = 
Alternatively :
Chandni's one day's work = 1 / 9
Divakar's one day's work = 1 / 12
Chandni's and Divakar's (1 + 1) = 2 day's work = 1 / 9 + 1 / 12 = 7 / 36
So, in 10 days they do = 
So, the remaining work will be done by Chandni = 
Thus total number of required days = 
Hint

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 18

P, Q, R enter into a partnership. P initially invests 25 lakh & adds another 10 lakhs after one year. Q initially invests 35 lakh & withdrawal 10 lakh after 2 years and R invests Rs 30 Lakhs . In what ratio should the profit be divided at the end of 3 years?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 18

P : Q : R
= (25 × 1 + 35 × 2) : (35 × 2 : 25 × 1) : (30 × 3)
= 95 : 95 : 90
= 19 : 19: 18

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 19

A police saw a Thief at a distance of 2km. When Police started chasing him Thief also started running. If the ratio of Speeds of Police to Thief is 5:4. Then thief was caught at a certain distance then how many Kms did police run to catch the Thief?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 19

2+x/5 = x/4
X = 8
Police = 8+2 = 10

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 20

If Rs. 1100 is obtained after lending out Rs. x at 5% per annum for 2 years and Rs. 1800 is obtained after lending out Rs. y at 10% per annum for 2 years, find x + y.

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 20

x = Rs. 1000 (As 1000 @ 5% for 2 years = 1100).
Similarly y = Rs. 1500. x +y = 2500.

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 21

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 9, 27, 31, 155, 161, 1127, ?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 21

⇒ For every term at even position, previous term is multiplied with the position+1
⇒ For every term at odd position, previous term is added with the position+1

So, missing term = 1127 + 8 = 1135.

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 22

Directions for question : A can do a work in 15 days and B can do it in 18 days. with the help of C work is completed in 6 days.

Q. How long will it take for C to finish the work alone?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 22

Efficiency of A = 6.66% , Efficiency of B = 5.55% , Efficiency of A + B + C = 16.66%
∴ Efficiency of C = 4.44%
Now, number of days required by C = 

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 23

A and B started a partnership business investing some amount in the ratio of 3 : 5. C joined then after six months with an amount equal to that of B. In what proportion should the profit at the end of one year be distributed among A, B and C?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 23

Let initial investment of A is 3x and B is 5x, then C investment is also 5x, but most important to note in this question is the time duration of investment
Like, A invested for 12 months, B invested for 12 months and C invested for 6 months.
A : B : C = (3x x 12) : (5x x 12) : (5x x 6)
= 36 : 60 : 30
= 6 : 10 : 5.

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 24

Two rabbits start running towards each other, one from A to B and another from B to A. They cross each other after one hour and the first rabbit reaches B, 5/6 hour before the second rabbit reaches A. If the distance between A and B is 50 km. what is the speed of the slower rabbit?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 24

Let second rabbit takes x hr with speed s2
First rabbit takes x-5/6 hr with speed s1
Total distance = 50km
S1 = 50/(x-(5/6))
S2 = 50/x
As they cross each other in 1hr…
Total speed = s1 + s2
Now, T = D / S
50/(s1+s2) = 1
x = 5/2, 1/3
Put x = 5/2 in s2 –> 20km/hr

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 25

Hans Kumar borrows Rs. 7000 at simple interest from the village moneylender. At the end of 3 years, he again borrows Rs. 3000 and closes his account after paying Rs. 4615 as interest after 8 years from the time he made the first borrowing. Find the rate of interest.

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 25

The interest would be paid on 7000 for 3 years + 10000 for 5 years. @ 6.5% the total interest for 8 years = 1365 + 3250 
= Rs. 4615

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 26
In the Indian Constitution, which article guarantees religious freedom to every individual?
Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 26
Article 25 of the Indian Constitution guarantees religious freedom to every individual. It ensures that every person in India has the right to freely profess, practice, and propagate their religion. This fundamental right is essential to protect the religious minorities and ensure that no one is discriminated against on the basis of their religion.
Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 27
Who is the head of the Indian Audit and Accounts Department?
Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 27
The head of the Indian Audit and Accounts Department is the Comptroller and Auditor General of India (CAG). The CAG plays a crucial role in overseeing and auditing the financial administration of both the central government and state governments.
Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 28

The "Most Favored Nation" clause in international trade refers to:

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 28

The "Most Favored Nation" (MFN) clause is a principle in international trade where a country extends its best trade terms and conditions, including tariffs and market access, to all other trading partners. It ensures that no country receives better treatment than others in terms of trade.

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 29

Which committee recommended the establishment of SEZs (Special Economic Zones) in India?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 29

The Rangarajan Committee recommended the establishment of Special Economic Zones to promote exports and attract foreign investments.

Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 30

Which industry is responsible for the provision of intangible products or services to customers?

Detailed Solution for Jharkhand Police Constable (Paper-II) Mock Test - 10 - Question 30

The tertiary industry, also known as the service industry, is involved in the provision of intangible products or services to customers. Examples include banking, healthcare, education, and hospitality.

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