JEE Exam  >  JEE Tests  >  KEAM Paper 2 Mock Test - 5 - JEE MCQ

KEAM Paper 2 Mock Test - 5 - JEE MCQ


Test Description

13 Questions MCQ Test - KEAM Paper 2 Mock Test - 5

KEAM Paper 2 Mock Test - 5 for JEE 2024 is part of JEE preparation. The KEAM Paper 2 Mock Test - 5 questions and answers have been prepared according to the JEE exam syllabus.The KEAM Paper 2 Mock Test - 5 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for KEAM Paper 2 Mock Test - 5 below.
Solutions of KEAM Paper 2 Mock Test - 5 questions in English are available as part of our course for JEE & KEAM Paper 2 Mock Test - 5 solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt KEAM Paper 2 Mock Test - 5 | 13 questions in 180 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
KEAM Paper 2 Mock Test - 5 - Question 1

If one root of the equation ax2 + bx + c = 0 be n times the other root, then

Detailed Solution for KEAM Paper 2 Mock Test - 5 - Question 1

KEAM Paper 2 Mock Test - 5 - Question 2

Let n(U) = 700, n(A) = 200, n(B) = 300 and n(A ∩ B) = 100,
Then n(Ac∩Bc) =

Detailed Solution for KEAM Paper 2 Mock Test - 5 - Question 2

n(Ac ∩ Bc) = n(U) - n(A ∪ B)
= n(U) - [n(A) + n(B) - n(A ∩ B)]
= 700 - [200 + 300 - 100] = 300.

1 Crore+ students have signed up on EduRev. Have you? Download the App
KEAM Paper 2 Mock Test - 5 - Question 3

Detailed Solution for KEAM Paper 2 Mock Test - 5 - Question 3

KEAM Paper 2 Mock Test - 5 - Question 4

Detailed Solution for KEAM Paper 2 Mock Test - 5 - Question 4

KEAM Paper 2 Mock Test - 5 - Question 5

In a ΔABC, a = 13 cm, b = 12 cm and c = 5 cm. The distance of A from BC is

Detailed Solution for KEAM Paper 2 Mock Test - 5 - Question 5

KEAM Paper 2 Mock Test - 5 - Question 6

The lengths of sides of a triangle are in the ratio 5 : 12 : 13 and its area is 270 cm2. The respective lengths of sides of the triangle (in cm) are

Detailed Solution for KEAM Paper 2 Mock Test - 5 - Question 6

Let the lengths of sides of the triangle be 5x, 12x, 13x;  Obviously, the triangle is right-angled.
Hence, area of the Δ = ½ (12x) (5x) ⇒ 30x2 = 270 ⇒ x = 3 
Hence, the lengths of sides (in cm) are 15, 36 and 39.

KEAM Paper 2 Mock Test - 5 - Question 7

If the mean of a binomial distribution is 25, then its standard deviation lies in the interval

Detailed Solution for KEAM Paper 2 Mock Test - 5 - Question 7

KEAM Paper 2 Mock Test - 5 - Question 8

The solution of the equation x2 dy/dx = x2 + xy + y2  is

Detailed Solution for KEAM Paper 2 Mock Test - 5 - Question 8

KEAM Paper 2 Mock Test - 5 - Question 9

Assuming that f is continuous everywhere, (1/c)  is equal to

Detailed Solution for KEAM Paper 2 Mock Test - 5 - Question 9

KEAM Paper 2 Mock Test - 5 - Question 10

If (√8+i)50 = 349 (a + ib), then a2 + b2 is

Detailed Solution for KEAM Paper 2 Mock Test - 5 - Question 10

KEAM Paper 2 Mock Test - 5 - Question 11

The equation of the normal to the ellipse x2/a2 + y2/b2 = 1 at the positive end of the latus rectum is

Detailed Solution for KEAM Paper 2 Mock Test - 5 - Question 11

The equation of the normal at (x1, y1) to the given ellipse is

Here x1 = ae and y1 = b2/a 
So the equation of the normal at positive end of the latus rectum is 

KEAM Paper 2 Mock Test - 5 - Question 12

 is equal to

Detailed Solution for KEAM Paper 2 Mock Test - 5 - Question 12

KEAM Paper 2 Mock Test - 5 - Question 13

If  then f(2x) − f(x) is not divisible by

Detailed Solution for KEAM Paper 2 Mock Test - 5 - Question 13

Information about KEAM Paper 2 Mock Test - 5 Page
In this test you can find the Exam questions for KEAM Paper 2 Mock Test - 5 solved & explained in the simplest way possible. Besides giving Questions and answers for KEAM Paper 2 Mock Test - 5, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE