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KEAM Paper 2 Mock Test - 9 - JEE MCQ


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13 Questions MCQ Test - KEAM Paper 2 Mock Test - 9

KEAM Paper 2 Mock Test - 9 for JEE 2024 is part of JEE preparation. The KEAM Paper 2 Mock Test - 9 questions and answers have been prepared according to the JEE exam syllabus.The KEAM Paper 2 Mock Test - 9 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for KEAM Paper 2 Mock Test - 9 below.
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KEAM Paper 2 Mock Test - 9 - Question 1

The area bounded by the curve y = x | x |, x-axis and the ordinates x = 1, x = -1 is given by

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KEAM Paper 2 Mock Test - 9 - Question 2

The area of the figure bounded by y = sin x, y = cos x in the first quadrant is

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KEAM Paper 2 Mock Test - 9 - Question 3

Period of cot 3 x - cos (4x + 3) is

Detailed Solution for KEAM Paper 2 Mock Test - 9 - Question 3

Period of cot 3x is π/3 and period of cos (4x + 3) is π/2 
⇒ L.C.M. is π, hence the answer.

KEAM Paper 2 Mock Test - 9 - Question 4

The value of sin 10° + sin 20° + sin 30° + ........+ sin 360° is

Detailed Solution for KEAM Paper 2 Mock Test - 9 - Question 4

Since, sin 190° = - sin 10°, sin 200° = - sin 20°, 
sin 210° = - sin 30°, sin 360° = sin 180° = 0 etc.
Hence all the terms in the expression cancels out, therefore answer is 0.

KEAM Paper 2 Mock Test - 9 - Question 5

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KEAM Paper 2 Mock Test - 9 - Question 6

India plays two matches each with West Indies and Australia. In any match, the probabilities of India getting points 0, 1 and 2 are 0.45, 0.05 and 0.50 respectively. Assuming that the outcomes are independent, the probability of India getting atleast 7 points is

Detailed Solution for KEAM Paper 2 Mock Test - 9 - Question 6

Probability of getting atleast seven points 
= Probability of getting 7 points or 8 points 
= Prob. of getting 7 points + Prob. of getting 8 points. 
Seven points in four matches can be obtained in the following four different ways :
2, 2, 2, 1; 
2, 2, 1, 2; 
2, 1, 2, 2; 
1, 2, 2, 2
The probability of each of these ways = (0.50)3 x (0.05) (by multiplication theorem for independent events) 
= 0.00625
Hence, probability of getting 7 points = 4 x (0.00625) (by add. Theorem) 
= 0.0250.
Eight points in four matches can be obtained only in one way i.e. 2, 2, 2, 2.
Hence, Prob. of getting 8 points = (0.50)4 = 0.0625
Thus, the required prob. = 0.250 + 0.0625 = 0.0875.

KEAM Paper 2 Mock Test - 9 - Question 7

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KEAM Paper 2 Mock Test - 9 - Question 8

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KEAM Paper 2 Mock Test - 9 - Question 9

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KEAM Paper 2 Mock Test - 9 - Question 10

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KEAM Paper 2 Mock Test - 9 - Question 11

The number of values of x where the  function f(x) = 2 (cos 3x + cos √3x attains its maximum, is

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KEAM Paper 2 Mock Test - 9 - Question 12

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KEAM Paper 2 Mock Test - 9 - Question 13

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