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Test: CSIR-NET Chemical Sciences Mock Test - 3 - UGC NET MCQ


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30 Questions MCQ Test - Test: CSIR-NET Chemical Sciences Mock Test - 3

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Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 1

In an examination 10,000 students appeared. The result revealed the number of students who have:

  • Passed in all five subjects = 5583
  • Passed in three subjects only = 1400
  • Passed in two subjects only = 1200
  • Passed in one subject only = 735
  • Failed in English only = 75
  • Failed in Physics only = 145
  • Failed in Chemistry only = 140
  • Failed in Mathematics only = 200
  • Failed in Bio-science only = 157

The number of students passed in at least four subjects is:

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 1

Total no of student = 10000
Total number of students passed in all five subjects = 5583
Total number of students passed in four subjects = total number of students failed in one subject only = 75+145+140+200+157 = 717
Therefore, number of students passed in at least four subjects is 5583 + 717 = 6300.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 2

Which of the following is not a method of a survey?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 2

Surveys can be done in various ways. Some of the methods of conducting surveys are personal interviews, telephonic interviews, mailing questionnaires, through schedules, etc. Whereas archive is a historical record of an event which can be utilised for data collection but it is not appropriate for a survey.

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Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 3

Brinjal plant belongs to the family ________.

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 3

Brinjal is one of the most common vegetables grown throughout the country for it and green or white pendulous fruit.
It is a member of the Solanaceae family and is closely related to tomato and potato.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 4

The mean of the ages of father and his son is 27 years. After 18 years, father will be twice as old as his son. Their present ages are

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 4

Present age of father= x years
Present age of son= y years
(x+y)/2 = 27
x + y = 54 ------- 1
After 18 years,
father’s age = (x + 18) years
Son’s age = (y + 18) years
So,
x + 18 = 2(y+18)
x + 18 = 2y + 36
x - 2y = 18    ---- 2
Put value of 1 in 2,
54-y-2y = 18
3y = 36
y = 12, x = 42
present age of father = 42 years
present age of son = 12 years

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 5

The stone formed in human kidney consist mostly of  _______ .

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 5

Calcium oxalate (in archaic terminology, oxalate of lime) is a calcium salt of oxalic acid with the chemical formula CaC2O4.
It is a chemical compound that forms envelope-shaped crystals, known in plants as raphides.
A major constituent of human kidney stones, calcium oxalate is also found in beerstone, a scale that forms on containers used in breweries.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 6

The measures of the three angles of a triangle are in the ratio 3:4:5. What is the measure of the biggest angle?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 6

Given: Ratio between the angles of the triangle = 3 : 4 : 5
Let the angles of the triangle are 3x, 4x and 5x, then
3x + 4x + 5x = 180
⇒ x = 15°
Thus, biggest angle = 5 × 15
= 75°

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 7

Given are the differences between a thesis and a research article. Choose the correct option.
(a) Thesis covers all the aspects of a research study and research article covers one idea or gist of entire research in brief.
(b) A thesis will have an extensive presentation of methods but research article will have a controlled presentation of specific methodology.
(c) Thesis is a general requirement for an academic degree while research article may or may not be required for getting a degree.
(d) Thesis has an exhaustive list of references whereas research article will have a selective list only.
(e) Thesis takes a longer time to complete but article needs less time.

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 7

A thesis is different from a research article in many aspects. Firstly, thesis is more scientific and formal; hence, it will cover all the important aspects of a research study. However, this is not true about a research article as it presents some particular idea or ideas about a research study. Writing a thesis is also a relatively longer process than writing a research article. So, all of them are true.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 8

A tropical location B is 20 km N15° E of A. Another location C is N45°W of A and S75° W of B. How far (in km) is C from A?
(N15° E denotes a direction 15° east of north.)

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 8

As per the instruction given in the question, the diagram is drawn below and all the angles are marked.

Now, ∠ A = ∠B = ∠C = 60º

  • The tiangle is an equilateral triangle as all three angles of the traingle is 60º. 
  • As AB = 20 km, CA and BA will also be 20 km.

So,the distance between point C and A is 20 km.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 9

A substance decays at a rate proportional to the amount of the substance itself. If half of the substance decays in one year, then what is the proportionality constant?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 9

It is given that the decay rate is proportional to the amount of substance. If the amount of the substance is N then, 

Here, λ is the decay constant.
The half life of any radioactive substance is given as: 
Given: The half life of the substance is : t1/2 = 1years.
Substituting in the half life formula : 

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 10

If 25 is written as
11001 (1 × 24 +1 × 23 + 0 × 22 + 0 × 21 +1 × 20),
then how will 101 be written?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 10

Considering the Binary Number System:

101 = (1×26)+(1×24)+(0×24)+(0×23)+(1×22)+(0×21)+(1×20)

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 11

Suppose A=1, B=2, C=3, D=4,...,X=24, Y=25, Z=26.
What is the value of 

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 11

The total number of alphabets is 26. Now, as per the series given in the question, the complete series is given below:

Substituting the values in the equation:

x = −1

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 12

Suppose the ratings of five players A, V, T, K and S are all distinct. The average of S and A’s ratings is equal to the minimum of the ratings of V and K. T has a higher rating than A, and A’s rating is equal to the average of V and K’s ratings. Who has the third highest rating among the five players?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 12
  • A's rating is the average of V and K. It means that  A has a place between V and K. 
  • Now, let us suppose that the ratings are:  V = 4, A = 3, and K =2.
  • Now, it is given that T is above A. Supposing that rating of T = 5.
  • The average of S and A is equal to a minimum of V and K. So, that suggests that the rating of S should be significantly less. Let us suppose it is S = 1.

Summarising the ratings from higher to lower order.

Note: The rating of V and K might be different but in the question, only the third position is to be obtained. So, the position of the rest players doesn't matter.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 13

In a hall, the fraction of people seated is 9/13 and the fraction of chairs occupied is 7/9. If the number of empty chairs is 36, how many more chairs are needed to seat everyone in the hall?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 13
  • Let the total number of people be: A
  • Let the total number of chairs be: B
  • The total number of occupied chairs is: 7B/9
  • The total number of people seated: 9A/13

Now total number of unoccupied chairs is: B−(7B/9) = 36
2B = 324
B = 162
Hence, the total number of chairs is: 162
Now, the total number of chairs and the people occupying it will be the same.

∴ A = 182
Now, the number of chairs needed to occupy the rest members: 182−162 = 20

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 14

A, B, C and D are consecutive integers such that B2 - A2 = 103 Then D2 - C2 =

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 14

It is given that  B2−A= 103 which implies (B−A)(B+A)=103. Now, it is given that A and B are consecutive numbers, so their difference will be 1.
(B−A)=1 and  (B+A)=103
Adding both the equations, B is obtained as: 52. Hence, A will be 51. C and D will be 53 and 54 respectively.
So, 
D2−C2 = (54)2−(53)2
D2−C2 = 2916−2809
D2−C2 = 107

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 15

The qualifying marks for an exam attempted by a large number of students are set at half of the median of the marks scored in that exam. Under this condition, 10% of the candidates fail. If the qualifying marks are set at the median of the scores, and if no two students have the same marks, the percentage of candidates failing will be closest to

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 15

Case 1: Consider 100 students attempting the exam and the exam is of 100 marks.

  • Now it is given that no two students have the same marks. Each student will have a different score.
  • So, if the median of the marks achieved is considered, it will be : X = (49+50)/2 = 49.5
  • Now, in this case, the cut-off is half of the median: X/2 = 25.25
  • Here, 90 students pass and 10 fail.

Case 2: Now, here the median is double of case 1: X = 49.5.

  • As it is given that no students can have the same score. So, the students scoring from 50 to 100 have passed the exam.
  • So, in total 51 students passed the exam.
  • Out of 100,51 students clear the exam which states that approx 50% of students failed the exam.
Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 16

How much nitrogen must be added to a 20% nitrogen solution to obtain 100 Kg of 40% nitrogen solution?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 16

Let the amount of nitrogen added be x, and amount of 20% nitrogen solution be P. Nitrogen balance: x + 0.2(P) = 0.4(100), Water balance: 0.8(P) = 0.6(100), ⇒ P = 75 Kg, ⇒ x = 0.4(100) – 0.2(75), ⇒ x = 25 Kg.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 17

A process is carried out for the feed mixture of 95% air and 5% ammonia vapor, the compressor recovered 40% of ammonia, what is the exit pressure of the compressor, if the partial pressure of ammonia vapor is 10 mm Hg?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 17

Exit components, ammonia: 0.05*0.6 = 0.03, air: 0.95, ⇒ yammonia = 0.03/0.98 = 0.0306, ⇒ Total exit pressure = 10/0.0306 = 326.8 mm Hg.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 18

A reactor is supplied with a feed of composition 46% C3H7O4, 44% O2 and 10% N2, if 50% of the limiting reagent is converted into product, what is the percentage of O2 in the product?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 18

The reaction is 4C3H7O4 + 11O2 → 12CO2 + 14H2O, ⇒ Limiting reagent is O2. Let 100 moles of feed was supplied, ⇒ after the reaction, moles of CO2 = 24, moles of H2O = 28, moles of O2 = 22, moles of C3H7O4 = 38, moles of N2 = 10, ⇒ percentage of O2 = 18%

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 19

The specific volume of SO2 is 10 m3/Kg, at 5 Pa, H = 100 J/Kg and at 10 Pa, H = 250 J/Kg, what is the heat transferred to the system?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 19

Q = ∆H – V∆P = (250 – 100) – 10(10 – 5) = 100 J/Kg.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 20

An unsteady-state system, with 10 liters as initial amount of water in the vessel, water flow in rate is 8 liters/ s and flow out rate is 5 liters/s, what will be the amount of water in the vessel after 10 seconds?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 20

Amount of water added to the vessel in 10 seconds = (8 – 5)*10 = 30 liters, => Final amount of water = 10 + 30 = 40 liters.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 21

What is the final amount of fluid in the vessel if the system is in steady state?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 21

Since in steady-state the rate of flow in is equal to the rate of flow out, so final amount of fluid in the vessel is same as the initial amount.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 22

A reaction has produced 5 moles of water vapor and 10 liter bone dry air at 27ºC and 15 atm, what is the humidity?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 22

Moles of bone dry air = 6, ⇒ humidity = 5/6*100 = 83%.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 23

 

What is the specific gravity of a substance with density 100 kg/m3 with respect to reference substance of density 100 lb/m3?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 23

Density of the substance = 100*2.2 = 220 lb/m3, Specific gravity = (100*2.2)/100 = 2.2.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 24

Condensation starts at which point?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 24

A dew point is a temperature at which condensation starts.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 25

How long would it take for an irreversible process to complete?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 25

It takes a finite time for an irreversible process to complete.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 26

A closed U-tube manometer has a gas on one end with pressure 5 Pa and other end has vacuum, what is the approximate height difference of the liquid if the density of liquid is 10 Kg/m3?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 26

Pressure of gas = Pressure due to height difference of liquid = d*g*h, ⇒ 5 = 10*10*h ⇒ h = 0.05 m = 50 mm.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 27

A container has gas mixture of 20% H2 and 80% N2 with total pressure P, now same amount of Ois added to the mixture, what is the new partial pressure of N2?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 27

New partial pressure of N2 = Old partial pressure of N2 = 0.8P.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 28

Which of the following is used to measure a pressure of only gas?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 28

U-tube manometer is used to measure the pressure of gas only.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 29

In air conditioning process, what has to be done first to the moist air?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 29

In air conditioning process, moist air is heated and then cooled.

Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 30

An unsteady state system, the flow in rate of A is 5 mole/s, what is the flow out rate of B if the accumulation was 10 mole in 5 seconds?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 3 - Question 30

Flow rate of B = 5 – 10/5 = 3 mole/s.

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