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Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - JEE MCQ


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24 Questions MCQ Test - Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom)

Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) for JEE 2024 is part of JEE preparation. The Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) questions and answers have been prepared according to the JEE exam syllabus.The Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) below.
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Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 1
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Direction (Q. Nos. 1-24) This section contains 24 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. Wavelength associated with water molecule moving with a velocity of 500 ms-1 is

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Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 2
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Assume H-atom (rH = 0.0529nm) and proton (rp =1.5x 10-15m)to be spherical. Fraction of the space in an atom of hydrogen that is occupied by the nucleus is 

Detailed Solution for Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 2

Proton is a part of nucleus


Fraction of the volume of hydrogen occupied by nucleus

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Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 3
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What electronic transition in a hydrogen atom, starting from the orbit n = 7 will produce infrared light of wavelength 2170 nm?

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Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 4
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If for a given value of n, perimissible values of azimuthal quantum number l be 0,1,2...... n, then magnetic moment of chromium (24) would be 
Detailed Solution for Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 4

[Cr] = [Ar]3d54s1

Using this we get,

μ = √(n(n + 2)) = √(6(6 + 2)) = √48 BM

Hence D

Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 5
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Velocity of the electron in H-atom in second orbit is
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Angular momentum is quantised, thus


Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 6
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If uncertainties in the measurements of position and momentum are equal, then uncertainty in the measurement of velocity is
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 By H eisenberg’s uncertainty principle


Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 7
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For the two moving particles A and B, following values are given 

Q. Ratio of de-Broglie wavelength associated with the particles A and B is
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de-Broglie wavelength is given

Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 8
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The wave number of the spectral line in the emission spectrum of H-atom will be equal to 8/9 times the Rydberg’s constant if the electron jumps from
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Wave number of the spectral line in H-atom is given by 

Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 9
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Which one of the following constitutes a group of the isoelectronic species? 
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Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 10
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In an experiment reproducing the measurements of Rutherford and his co-workers, 22 x10-3 mg of He gas was collected in one year from a sample of radium. This sample was observed to emit 1. 06 x 1011 α - particlesper second. Thus, Avogadro’s number is
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22 x 10-3 mg per year = 22 x 10-6 g per year

Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 11
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Medical experts generally consider a lead level of 30 μg Pb per (dL) of blood to pose a significant health risk (Pb =208). Number of lead atoms per cm3 of blood is
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Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 12
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In Schrodinger wave equation given below
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Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 13
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Which hydrogen like species will have same radius as that of Bohr’s orbit of hydrogen atom?
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Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 14
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An atom for which the electron probability distribution is spherically symmetric about the nucleus is
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Spherically symmetric about the nucleus
(c) 3pas (a)

Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 15
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Which of the following statements in relation to the hydrogen atom is correct?
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Thus, w.r.t. (1s) orbital, 3s, 3p and 3d orbitals will have same energy.

Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 16
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Which of the following options does not represent ground state EC of an atom?
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Due to extra stability of com ple te ly filled sub orb it or half-filled suborbit
4s13d10 is more stable than 4s23d9. Thus, [Ar] 4s239 is not the ground state electronic configuration.

Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 17
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Statement I :The electronic configuration of N -atom is represented as :

Statement II : The electronic configuration of the ground state of an atom is the one which has the greatest multiplicity.
Detailed Solution for Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 17

 N (7) has electronic configuration as

Thus, Statement I is correct.
By Hund’s rule of maximum multiplicity, pairing of electrons takes place only after each orbital is half-filled, i.e. maximum multiplicity, and thus, has stable configuration.
Thus, Statement II is also correct and is the correct explanation of Statement I.

Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 18
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If n and l are respectively the principal and azimuthal quantum numbers, then the expression for calculating the total number of electrons in any energy level is
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For a given value of n
l = 0,1,2......(n - 1)
Total orbitals = (2l + 1)
Total electrons = 2(2l + 1)
Thus, total electrons are obtained by taking sum of all values of l from 0 to (n - 1)

Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 19
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 3d-suborbit first occurs in fourth orbit. It has
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For a given orbit, (3d, n = 3, l = 2)
Number of angular nodes = l = 2 for 3d number of radial nodes
= (n — l — 1) = (3 — 2 — 1) = 0
Total nodes = (n - I - 1 + l) = ( n - 1)= 2

Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 20
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How fast is an electron moving if it has a wavelength equal to the distance it travels in one second?
Detailed Solution for Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 20

Velocity = v cm -1 (say)
Distance travelled in 1s = v cm s-1 x 1 s = v cm


Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 21
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In the presence of magnetic field, d-suborbit is
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In the presence of magnetic field there is splitting of lines (Zeeman’s effect)
Total lines due to splitting = (2l + 1)
Total orbitals =(2l + 1)

Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 22
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Electrons are used to determine the structure of crystal surfaces. To have diffraction, the wavelength λ, of the electrons should be of the order of the lattice constant, which is typically 0.30 nm. What energy do such electrons have?
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Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 23
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The number of d-electrons in Fe2+ (24 electrons) is not equal to
Detailed Solution for Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 23

Fe = [Ar] 4s23d6
Fe2+ = [Ar]4s03d6
[Electrons of the outermost shell are taken out in the formation of Fe2+ (i.e. 4s)]
Electrons in 3d in Fe2+ = 6
Ne (10) = 1s2,2s2,2p6
p-electrons = 6: Correct
Mg (12)= 1s22s22p63s2
s-electrons = 6: Correct
Fe (26) = 1s22s22p63s23p64s23d6
d-electrons = 6: Correct
Cl (17) = 1s22s22p63s23p5
p-electrons 11 : Incorrect

Revisal Problems (Past 13 Years) JEE Main (Structure Of Atom) - Question 24
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Bohr's theory is applicable to the following set of species
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Bohr's theory is applicable to H-atom and FI-like species with one electron.
H (Z =1)1 electron
He+ (Z =2)1 electron
Li2+ (Z = 3) 1 electron
Be3+ (Z = 4)1 electron

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