MCQ: Square Roots and Cube Roots - 2 - SSC CGL MCQ

√3100 × √567 ÷ √250 = ? ÷ 8

∴ required answer = 670

For this, calculate the sum of digits:
936: Sum of digits = 18 i.e. divisible by 3 and 9.
39987: Sum of digits = 36 i.e. divisible by 3 and 9.
2343: Sum of digits = 12 i.e. divisible by 3, but not by 9.
36: Sum of digits = 9 i.e. divisible by 3 and 9.

Let us extract the square root from 24136.

∴ 24136, is 111 more than (155)².
So if we subtract 111 from 24136, we will get a perfect sq. number.

Let the consecutive integers(even) be 2p and (2p + 2):
= (2p + 2)² - 2p² = (2p + 2 + 2p)(2p + 2 -2p)
= 2(4p + 2)
= 4 (2p + 1)
Therefore, divisible by 4.

Clearly, the required least number is 25.

For this:
= (5 + 1 + 7 + x + 3 + 2 +4)
= 22 + x
Now, 22 + x must be divisible by 3. So, for this x should be 2.
22 + 2 = 24 i.e. divisible by 3

7365 + 29.16 + √? = 7437.16

√? = 473.16 – 7394.16

√? = 43 = 1849

(74 × √676) − (42 × √?) = 496

Let the ratio of numbers be x.

∴ numbers are 2x, 3x & 4x.

∴ (2x)³ + (3x)³ + (4x)³ = 33957

⇒ 8x³ + 27x³ + 64x³ = 33957

⇒ x³ = 343 ⇒ x = 7

∴ Numbers are 2×7,3×7,4×7

i.e. 14, 21, 28

r = √144 = 12m

Diameter = 24 m

Let the natural number be 'x'.

∴ x³ − x² = 48

⇒ x²(x - 1) = 48

⇒ 4²(4 - 1) = 48

∴ x = 4

∴? = √3

√? = 4² = 16

∴? = 256

169 – 64 – √676 + 2 = (?)²

= 169 – 64 – 26 + 2 = (?)² = 171 – 90 = 81

∴ ? = 9