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Square Roots and Cube - 2 - Free MCQ Practice Test with solutions, SSC


MCQ Practice Test & Solutions: MCQ: Square Roots and Cube Roots - 2 (15 Questions)

You can prepare effectively for SSC CGL with this dedicated MCQ Practice Test (available with solutions) on the important topic of "MCQ: Square Roots and Cube Roots - 2". These 15 questions have been designed by the experts with the latest curriculum of SSC CGL 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 15 minutes
  • - Number of Questions: 15

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MCQ: Square Roots and Cube Roots - 2 - Question 1

√3100 × √567 ÷ √250 = ? ÷ 8

Detailed Solution: Question 1

√3100 × √567 ÷ √250 = ? ÷ 8

∴ required answer = 670

MCQ: Square Roots and Cube Roots - 2 - Question 2

Which of the following numbers are divisible by 3 but not by 9?

Detailed Solution: Question 2

For this, calculate the sum of digits:
936: Sum of digits = 18 i.e. divisible by 3 and 9.
39987: Sum of digits = 36 i.e. divisible by 3 and 9.
2343: Sum of digits = 12 i.e. divisible by 3, but not by 9.
36: Sum of digits = 9 i.e. divisible by 3 and 9.

MCQ: Square Roots and Cube Roots - 2 - Question 3

The least number to be subtracted from 24136 to make it a perfect square

Detailed Solution: Question 3

Let us extract the square root from 24136.

∴ 24136, is 111 more than (155)2.
So if we subtract 111 from 24136, we will get a perfect sq. number.

MCQ: Square Roots and Cube Roots - 2 - Question 4

The difference of the squares of two consecutive even integers is divisible by which of the following integers?

Detailed Solution: Question 4

Let the consecutive integers(even) be 2p and (2p + 2):
= (2p + 2)2 - 2p2 = (2p + 2 + 2p)(2p + 2 -2p)
= 2(4p + 2)
= 4 (2p + 1)
Therefore, divisible by 4.

MCQ: Square Roots and Cube Roots - 2 - Question 5

What is the least number to be added to 2000 to make it a perfect square?

Detailed Solution: Question 5


Clearly, the required least number is 25.

MCQ: Square Roots and Cube Roots - 2 - Question 6

If the number 517 * 324 is completely divisible by 3, then the smallest whole number in place of * will be?

Detailed Solution: Question 6

For this:
= (5 + 1 + 7 + x + 3 + 2 +4)
= 22 + x
Now, 22 + x must be divisible by 3. So, for this x should be 2.
22 + 2 = 24 i.e. divisible by 3

MCQ: Square Roots and Cube Roots - 2 - Question 7

7365 + (5.4)2 + √? = 7437.16

Detailed Solution: Question 7

7365 + 29.16 + √? = 7437.16

√? = 473.16 – 7394.16

√? = 43 = 1849

MCQ: Square Roots and Cube Roots - 2 - Question 8

(74 × √676) − (42 × √?) = 496

Detailed Solution: Question 8

(74 × √676) − (42 × √?) = 496

MCQ: Square Roots and Cube Roots - 2 - Question 9

The three numbers are in the ratio 2 : 3 : 4. The sum of their cubes is 33957. The numbers are,

Detailed Solution: Question 9

Let the ratio of numbers be x.

∴ numbers are 2x, 3x & 4x.

∴ (2x)3 + (3x)3 + (4x)3 = 33957

⇒ 8x3 + 27x3 + 64x3 = 33957

⇒ x3 = 343 ⇒ x = 7

∴ Numbers are 2×7,3×7,4×7

i.e. 14, 21, 28

MCQ: Square Roots and Cube Roots - 2 - Question 10

The area of a circular play ground is   The diameter of the ground is

Detailed Solution: Question 10

r = √144 = 12m

Diameter = 24 m

MCQ: Square Roots and Cube Roots - 2 - Question 11

The square of a natural number when subtracted from its cube results in 48. The number is

Detailed Solution: Question 11

Let the natural number be 'x'.

∴ x3 − x2 = 48

⇒ x2(x - 1) = 48

⇒ 42(4 - 1) = 48

∴ x = 4

MCQ: Square Roots and Cube Roots - 2 - Question 12

255 ÷ 17 ÷ 5 = (?)2

Detailed Solution: Question 12


∴? = √3

MCQ: Square Roots and Cube Roots - 2 - Question 13

(656 ÷ 164)2 = √?

Detailed Solution: Question 13

√? = 42 = 16

∴? = 256

MCQ: Square Roots and Cube Roots - 2 - Question 14

(13)2 − (4)3 - √676 + 2 = (?)2

Detailed Solution: Question 14

169 – 64 – √676 + 2 = (?)2

= 169 – 64 – 26 + 2 = (?)2 = 171 – 90 = 81

∴ ? = 9

MCQ: Square Roots and Cube Roots - 2 - Question 15

1190 ÷ √7225 × ? = 3094 =

Detailed Solution: Question 15

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