MCQ: Mathematical Operations- 1 - SSC CGL MCQ

? = 10 x 5 ÷ 3 - 2 + 3
= 10 ÷ 5 + 3 x 2 - 3
Apply the rule BODMAS
Do things in Brackets First
(Powers, Roots) before Multiply, Divide, Add or Subtract.
Multiply or Divide before you Add or Subtract
= 10 ÷ 5 + 3 x 2 - 3
= 2 + 3 x 2 - 3
Addition
= 2 + 6 - 3
Subtraction
= 8 - 3 = 5

Given expression, (50 x 2) W (28 T 4)
After interchanging the letters with symbols, we get
(50 ÷ 2) + (28 x 4) = 25 + 112 = 137

Given, 40* 2* 4 * 3 * 8
Let us check all the options one by one.
From option (a), putting the signs in given equation, we get
40 + 2 - 4 ÷ 3
= 8 ⇒ 42 - 4/3 = 8
⇒ 126 - 4 = 24 ⇒ 122 = 24
∴ L H S ≠ R H S
So, option (a) is incorrect.
From option (b), putting the signs in given equation, we get
40 ÷ 2 + 4 = 3 x 8
⇒ 20 + 4 = 24 ⇒ 24 = 24
LHS = RHS
Hence, option (b) is correct and there is no need to check remaining options.

As, 4 - 4 ⇒ 4 x 4 + 1 = 17
6 - 6 ⇒ 6 x 6 + 1 = 37
2 - 2 ⇒ 2 x 2 + 1 = 5
Similarly, 5 - 5 ⇒ 5 x 5 + 1 = 26
∴ ? = 26

After replacing the sign according to question
1   P   45   R   2   Q   2   S   4
Apply the BODMAS Rule
= 1 + 45 ÷ 2 x 2 - 4
= 1 + 22.5 x 2 - 4
= 1 + 45 - 4 = 42

∵ 6%12C3@8   $   3 = ?
After replacing the sign according to the question
⇒ 6 + 12 ÷ 3 x 8 - 3 = ?
Apply the BODMAS Rule
⇒ 6 + 4 x 8 - 3 = ?
⇒ 6 + 32 - 3 = ?
⇒ 38 - 3 = ?
∴ ? = 35

Let us check all the options one by one.
From option (a),
6 - 5 + 4 = 34 (using VBODMAS rule)
⇒ 10 - 5 = 34 ⇒ 5 = 34
∴ LHS ≠ RHS
So, option (a) is incorrect
From option (b),
6 x 5 + 4 = 34 (using VBODMAS rule)
⇒ 30 + 4 = 34 ⇒ 34 = 34
⇒ LHS = RHS
So, option (b) gives us the correct answer and hence, there is no need to check remaining options.

Let us check all the options one by one.
From option (a),
65 - 40 + 11 = 36 ⇒ 76 - 40 = 36
⇒ 36 = 36 ⇒ LHS = RHS
So, option (a) is correct and hence there is no need to check remaining options.

Given, 7 * 7 * 2 * 1 = 12
Let us check all the options one by one.
From option (a), putting the signs in given equation, we get
7 x 7 - 2 ÷ 1 = 12 ⇒ 7 x 7 - 2 = 12
⇒ 49 - 2 = 12 ⇒ 47 = 12
⇒ LHS ≠ RHS
So, option (a) is incorrect.
From option (b), putting the signs in given equation, we get
7 + 7 - 2 x 1 = 12 ⇒ 7 + 7 - 2 = 12
⇒ 14 - 2 = 12 ⇒ 12 = 12
Hence, option (b) is correct and there is no need to check remaining options .

As, 73 + 82 = 14
⇒ (7 - 3) + (8 + 2) = 14
⇒ 4 + 10 = 14
⇒ 14 = 14 and 91 + 21 = 11
⇒ (9 - 1) + (2 + 1) = 11
⇒ 8 + 3 = 11 ⇒ 11 = 11
Similarly, 86 + 24 = (8 - 6) + (2 + 4) = 2 + 6 = 8

From option (b),
24 = 4 x 5 + 4
⇒ 24 = 20 + 4 ⇒ 24 = 24

Apply all option one by one
∵ 16 x 6 ÷ 4 = 24
⇒ 96/4 = 24 ⇒ 24 = 24

∵ 9 ÷ 3 x 3 - 3 = 6
∵ 3 x 3 - 3 = 6
⇒ 9 - 3 = 6
⇒ 6 = 6

∵ 8 * 6 * 96 * 2 = 0
⇒ 8 x 6 - 96 ÷ 2 = 0
⇒ 48 - 48 = 0

∵ 8 x 20 ÷ 3 + 9 - 5 = 38
⇒ 8 x 20 ÷ 5 + 9 - 3 = 38
⇒ 8 x 4 = 9 - 3 = 38
⇒ 32 + 9 - 3 = 38