MCQ: Area and Perimeter- 1 - SSC CGL MCQ

Required area = πr² = π x 25 x 25
= 625π sq m.

According to the formula,
∵ Percentage increase in sides = 10%
∴ Percentage increase diagonals = 10%

Required area = Length x Breadth
= 100 x 40 = 4000 sq m
= 4 x 10³ sq m

Area of parallelogram = Base x Height
= 8.06 x 2.08 = 16.76 cm²

Given that, a = 6 cm, b = 4 cm and c = 5 cm
Required perimeter = a + b + c
= 6 + 4 + 5 cm
= 15 cm

Req. Area = √3/4 x a² = √3/4 x 8² cm²
= 16√3 cm²

Ratio of area = a²/ √(3/4) a²
= 4/√3 = 4:√3

Let the diagonal of one square be (2d) cm
Then, diagonal of another square = d cm
∴ Area of first square = [ 1/2 x (2d)²] cm²
Area of second square = (1/2 x d²) cm²
∴ Ratio of area = (2d)²/ d²
= 4/1 = 4: 1

Let breadth = b, length = 2b
∴ Area of rectangle = 2b x b
= 2b²

As per question.
∵ (2b - 5 ) (b + 5 ) = 2b² + 75
⇒ 5b = 75 + 25
⇒ 5b = 100
∴ b = 100 / 5 = 20

Hence, length of the rectangle =2b
= 2 x 20
= 40 cm.

Let each side = x cm
Then, (x + 4 )² - x² = 60
⇒ x ² + 8x + 16 - x² = 60
∴ x = 5.5 cm

Let breadth = y meters,
Then, length = 2y meters
∴ Diagonal = √y² + (2y)²
= √5y² meters
So, √5y² = 9 √5
∴ y= 9
Thus, breadth = 9 m and length = 18 m
∴ Perimeter = 2 (18 + 9) m = 54m.

Perimeter = 2 x (36 + 21 ) m = 144 m
∴ Number of flagstaffs = 144 / 3 = 38

Radius = Diameter/2
∴ Diameter = 2 x Radius
= 2 x 3
= 6 cm

According to the formula,
Percentage increase in diagonals = 5%

Required area = Length x Breadth
= 15 x 8 = 120 sq m