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MCQ: Area and Perimeter- 2 - SSC CGL MCQ


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15 Questions MCQ Test - MCQ: Area and Perimeter- 2

MCQ: Area and Perimeter- 2 for SSC CGL 2024 is part of SSC CGL preparation. The MCQ: Area and Perimeter- 2 questions and answers have been prepared according to the SSC CGL exam syllabus.The MCQ: Area and Perimeter- 2 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MCQ: Area and Perimeter- 2 below.
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MCQ: Area and Perimeter- 2 - Question 1

One side of a rectangular field is 4 meter and its diagonal is 5 meter. The area of the field is ?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 1

Other side = √5 2 - 42
= √ 9
=3 m

So The area of the rectangular field = 4 x 3
= 12 m2

MCQ: Area and Perimeter- 2 - Question 2

The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is ?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 2

Let breadth = b meters.
Then, length = 4b/3 meters.
∵ b x 4b/3 = 300

⇒ b2 = 300 x 3/4
⇒ b2 = 225
∴ b = 15

Hence, required difference = [(Length) - (Breadth) ]
= 4b/3 - b
= b/3
= 15/3 m
= 5 m

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MCQ: Area and Perimeter- 2 - Question 3

A rectangular plot is half as long again as it broad. The area of the lawn is 2/3 hectares. The length of the plot is?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 3

Let breadth = b meters.
then, length = 3b/2 meters
∴ b x 3b/2 = 2/3 X 10000
⇒ b2 = (4 x 10000)/9
⇒ b = ( 2 X 100)/3 m
∴ Length = (3/2) x (2/3) x 100 m
= 100 m

MCQ: Area and Perimeter- 2 - Question 4

The area of a rectangle, 144 m long is the same as that of a square having a side 84 m long. The width of the rectangle is ?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 4

Area of the square = (84 + 84) m2
Area of the rectangle = (144 x width) m2

From question both area would be same,
∴ Width = (84 x 84) / 144 m = 49 m

MCQ: Area and Perimeter- 2 - Question 5

The cost of papering the four walls of a room is Rs. 48. Each one of length, breadth and height of another room is double that of this room.The cost of papering the walls of the new room is ?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 5

Let the length, breadth and height of the room be l, b and h respectively

As per question
Cost of 2(l + b) x h = Rs. 48
∴ Required cost = cost of 2 (2l + 2b) x 2h
= cost of 4 [2(l + b) x h ]
= 4 x Rs. 48
= Rs. 192

MCQ: Area and Perimeter- 2 - Question 6

Area of a four wall of a room is 77 square meters . the length and breadth of room are 7.5 meters and 3.5 meters respectively . the height of the room is ?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 6

Area of four walls = 2 x (l + b ) x h
⇒ 2 x (7.5 + 3.5 ) x h = 77 m2
⇒ h = 77 / (2 x 11) = 7/2
∴ h = 3.5 meters

MCQ: Area and Perimeter- 2 - Question 7

The length of a rectangle room is 4 meters . if it can be partitioned into two equal square rooms . what is the length of each partition in meters ?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 7

Let the width of the room be x members
Then, its area = (4x) m2
Area of each new square room = (2x)m2
Let the side of each new room = y meters
Then, y2 = 2x
Clearly, 2x is a complete square when x=2
∴ y2 = 4
⇒ y = 2 m . 

MCQ: Area and Perimeter- 2 - Question 8

A hall 20 m long and 15 m broad is surrounded by a verandah of uniform width of 2.5 m. the cost of flooring the verandah at the rate of 3.50 per sq. meter is ?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 8

Area of verandah = [(25 x 20) -(20 x 15)] m2
= 200 m2
∴ Cost of flooring = Rs. (200 x 3.50)
= Rs. 700 

MCQ: Area and Perimeter- 2 - Question 9

If the ratio of the area of two square is 9 : 1 the ratio of their perimeters is ?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 9

Let the area of square be (9x)2 m2 and (x2) m2
Then, their sides are (3x) m and x metres respectively
∴ Ratio of their perimeters = 12x / 4x
=3:1 

MCQ: Area and Perimeter- 2 - Question 10

The area of a rectangle is thrice that of square. Length of the rectangle is 40 cm and the breadth of the rectangle is ( 3 / 2 ) times that of the side of the square. The side of the square in cm is ?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 10

Let the side of the square = y cm
Then, breadth of the rectangle = 3y/2 cm
∴ Area of rectangle = (40 x 3y/2) cm2
= 60y cm2
∴ 60y = 3y2
∴ y = 20
Hence, the side of the square = 20 cm

MCQ: Area and Perimeter- 2 - Question 11

The radius of a circle has been reduced from 9 cm to 7 cm . the appropriate percentage decrease in area is ?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 11

Original area = (22/7) x 9 x 9 cm2
New area = (22/7) x 7 x 7 cm2
∴ Decrease = 22/7 x [(9)2 -(7)2] cm2
=(22/7) x 16 x 2 cm2
Decrease percent = [(22/7 x 16 x 2) /( 7/22 x 9 x 9)] x 100 %
= 39.5 % 

MCQ: Area and Perimeter- 2 - Question 12

The area of a circular field is 13.86 hectares . The cost of fencing it at the rate of 20 paisa per meter is ?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 12

∵ 22/7 x r2 = 13.86 x 10000
⇒ r2 = (13.86 x 10000 x 7) / 22
∴ r = 210 m
⇒ Circumference = [2 x (22/7) x 210 ] m
= 1320 m
Cost of fencing = Rs. (1320 x 20)/100
= Rs . 264 

MCQ: Area and Perimeter- 2 - Question 13

If the circumference of a circle is the 352 meters, then its area in m square is ?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 13

circumference = 2πr = 2 x (22 / 7) x r = 352
⇒ r = (352 x 7) / (22 x 2) =56 cm
Now area = πr2 = (22 / 7) x 56 x 56 m2
= 9856 m2 

MCQ: Area and Perimeter- 2 - Question 14

If the circumference of a circle is the 352 meters, then its area in m square is ?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 14

circumference = 2πr = 2 x (22 / 7) x r = 352
⇒ r = (352 x 7) / (22 x 2) =56 cm
Now area = πr2 = (22 / 7) x 56 x 56 m2
= 9856 m2 

MCQ: Area and Perimeter- 2 - Question 15

In a triangle ABC, BC = 5 cm AC = 12 cm and AB = 13 cm. The length of a altitude drawn from B on AC is ?

Detailed Solution for MCQ: Area and Perimeter- 2 - Question 15

∵ s= (13 + 5 + 12) / 2 cm
= 15cm
s-a = 2 cm,
s-b = 10 cm and
s-c = 3 cm
⇒ Area = √ (15 x 2 x 10 x 3 ) cm2
= 30 cm2
⇒ (12 x h) / 2 = 30
∴ h = 5 cm

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