Bank Exams Exam  >  Bank Exams Test  >  MCQ: Coding- Decoding - 2(Medium) - Bank Exams MCQ

Coding- Decoding - 2(Medium) Free MCQ Practice Test with solutions, Bank


MCQ Practice Test & Solutions: MCQ: Coding- Decoding - 2(Medium) (15 Questions)

You can prepare effectively for Bank Exams with this dedicated MCQ Practice Test (available with solutions) on the important topic of "MCQ: Coding- Decoding - 2(Medium)". These 15 questions have been designed by the experts with the latest curriculum of Bank Exams 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 15 minutes
  • - Number of Questions: 15

Sign up on EduRev for free to attempt this test and track your preparation progress.

MCQ: Coding- Decoding - 2(Medium) - Question 1

In a certain code language 'LIEUTENANT' is written as 1232212021411420,then how 'MANGO' can be written in that code language?

Detailed Solution: Question 1

Code for Consonant is it's place value, and code for vowels are given below
A ⇒ 1,
E ⇒ 2,
I ⇒ 3,
O ⇒ 4,
U ⇒ 5

Therefor
M ⇒ 13,
A ⇒ 1,
N ⇒ 14,
G ⇒ 7,
O ⇒ 4

So the code for MANGO is 1311474

MCQ: Coding- Decoding - 2(Medium) - Question 2

In a certain code, 'CALANDER' is written as 'CLANAEDR'. How is 'CIRCULAR' written in that code?

Detailed Solution: Question 2

For question it is clear that, the second and third letters, fourth and fifth letters, sixth and seventh letters of the word mutually interchange positions to form the code.
So
C ⇒ C
I ⇘ R
R ⇗ I
C ⇘ U
U ⇗ C
L ⇘ A
A ⇗ L
R ⇒ R
so the code for CIRCULAR is CRIUCALR

MCQ: Coding- Decoding - 2(Medium) - Question 3

In a certain code language, GRAPE is written as 27354 and FOUR is written as 1687 . How is GROUP written is that code ?

Detailed Solution: Question 3

GRAPE = 2 7 3 5 4
FOUR = 1 6 8 7
So, G = 2, R = 7, A = 3, P = 5, E = 4,
F = 1, O = 6, U = 8,
R = 7
GROUP = 2 7 6 8 5

MCQ: Coding- Decoding - 2(Medium) - Question 4

If 1 + 4 = 9, 2 + 8 = 18, 3 + 6 = 15 then 7 + 8 = ?

Detailed Solution: Question 4

The given logic is as follows,
Sum of the digits + second digit = Answer.
i.e., 1 +4 = 5 + 4 = 9
2 + 8 = 10 + 8 = 18
Similarly, 7 + 8 = 15 + 8 = 23.

MCQ: Coding- Decoding - 2(Medium) - Question 5

If A = 1, ACT = 24, then FAT = ?

Detailed Solution: Question 5

Each letter represents its position in the alphabet (A=1, B=2, ..., Z=26). Here’s how the calculations for the words are done:

  • ACT:
    • A = 1
    • C = 3
    • T = 20

    Therefore, ACT = A + C + T = 1 + 3 + 20 = 24.

  • FAT:
    • F = 6
    • A = 1
    • T = 20

    Thus, FAT = F + A + T = 6 + 1 + 20 = 27.

MCQ: Coding- Decoding - 2(Medium) - Question 6

Using the following code and key decode the given coded word :

Code : L X P Z J Y Q M N B
key : b a e s p r h i g t
Coded word : ZBYXMNQB

Detailed Solution: Question 6

To decode the word, each letter in the code is replaced by the corresponding letter from the key based on their positions.

  • Z (position 4) → s
  • B (position 10) → t
  • Y (position 6) → r
  • X (position 2) → a
  • M (position 8) → i
  • N (position 9) → g
  • Q (position 7) → h
  • B (position 10) → t

Combining these letters gives the word 'straight'.

The correct answer is option C: straight.

MCQ: Coding- Decoding - 2(Medium) - Question 7

In a certain code PATHOLOGIST is written as PIUBQKSRHFN. How is CONTROVERSY written in that code?

Detailed Solution: Question 7

Five letters of the word PATHOLOGIST are reversed first and then coded as one place forward. Similarly, the last five letters of the word are reversed then coded as one place backward. Middle letter is coded as one place backward.
Hence, CONTROVERSY will be written as SUOPDNXRQDU.

MCQ: Coding- Decoding - 2(Medium) - Question 8

The following small letters are coded by capital letters in a certain way :
s u m l a d
R A P M S O

Now, which small letters can be decoded from the letters given below :
M A P S R O

Detailed Solution: Question 8

According to given question,
R = s
A = u
P = m
M = l
S = a
O = d
Replace the each capital from given relationship for M A P S R O, We will get
M → l
A → u
P → m
S → a
R → s
O → d

MCQ: Coding- Decoding - 2(Medium) - Question 9

Unscramble the following letters to frame a meaningful word and find out the correct numerical sequence of the letters.
E → 1
S → 2
R → 3
T → 4
A → 5
R → 6
U → 7
N → 8
A → 9
T → 10

Detailed Solution: Question 9

The below pattern is given in the question,
E → 1
S → 2
R → 3
T → 4
A → 5
R → 6
U → 7
N → 8
A → 9
T → 10
Try all option one by one and formed a word by arranging them.
After arranging the option (b), we get the meaningful word -
R → 3
E → 1
S → 2
T → 4
A → 5
U → 7
R → 6
A → 9
N → 8
T → 10
Hence , the required answer will be Restaurant.

MCQ: Coding- Decoding - 2(Medium) - Question 10

In a certin code the following numbers are coded in a certain way by assigning signs:
1 → %
2 → x
3 → -
4 → +
5 → >
6 → <
7 → ∧
8 → ∨
9 → $
Which number can be decoded from the following?
> $ x ∨ %

Detailed Solution: Question 10

According to given question,
1 → % , 2 → x , 3 → - , 4 → + , 5 → > , 6 → < , 7 → ∧ , 8 → ∨ , 9 → $ ,
Replace the each capital from given relationship for > $ x ∨ % , We will get
5 → >
9 → $
2 → x
8 → ∨
1 → %
Hence , the required answer will be 59281.

MCQ: Coding- Decoding - 2(Medium) - Question 11

In a code language, the following alphabets are coded in a particular way:
A → @
C → #
D → $
E → %
M → ^
S → &
N → *
R → α
Q → β
V → γ
L → δ
Which word can be decoded from the following?
^ @ α γ % δ

Detailed Solution: Question 11

According to given question,
A → @ , C → # , D → $ , E → % , M → ^ , S → & , N → * , R → α , Q → β , V → γ , L → δ
Replace the each capital from given relationship for ^ @ α γ % δ, We will get
^ → M
@ → A
α → R
β → V
% → E
δ → L
Hence , the required answer will be MARVEL.

MCQ: Coding- Decoding - 2(Medium) - Question 12

Direction: Given below are letters A to Z. Under each capital letter a small letter is written which is to used as a code for the capital letters.

Select the equivalent capital letters for the following:
hjwlcm

Detailed Solution: Question 12

As per the given table in the question, After replacing the each capital from given relationship for hjwlcm, We will get
h → W
j → S
w → Q
l → D
c → V
m → H
Hence , the required answer will be WSQDVH.

MCQ: Coding- Decoding - 2(Medium) - Question 13

Direction: Below are given letter A to Z. Under each capital letter a small letter is written which is to be used as a code for the capital letter:
In each of the following questions, a group of six capital letters is given and its code equivalent is given in one of the columns (1), (2), (3) and (4). Study the group of letters given in each question and with the help of code given above, choose the code equivalent from among (1), (2), (3) and (4) as your answer.
(A) julsqr, mkzbxn , hijmub, vishwa, ocdkzq, zocbak
(B) lzcndo, mzkbxn, ucjlbo, mkzbxn, amwrnd, hmfxco
(C) cxtndo, cvafog, amwnrd, hilmbu, vithwa, ocqzkd
(D) vithaw, mzkbnx, odcazq, napkin, amwrny, hijump

ELBJSR

Detailed Solution: Question 13

As per the above given table, We can replace the each capital from given relationship for ELBJSR , We will get
E → a
L → m
B → w
J → r
S → n
R → d
Hence , the required answer will be amwrnd.

MCQ: Coding- Decoding - 2(Medium) - Question 14

Direction: Below are given letter A to Z. Under each capital letter a small letter is written which is to be used as a code for the capital letter:
In each of the following questions, a group of six capital letters is given and its code equivalent is given in one of the columns (1), (2), (3) and (4). Study the group of letters given in each question and with the help of code given above, choose the code equivalent from among (1), (2), (3) and (4) as your answer.
(A) julsqr, mkzbxn , hijmub, vishwa, ocdkzq, zocbak
(B) lzcndo, mzkbxn, ucjlbo, mkzbxn, amwrnd, hmfxco
(C) cxtndo, cvafog, amwnrd, hilmbu, vithwa, ocqzkd
(D) vithaw, mzkbnx, odcazq, napkin, amwrny, hijump

XACGLY

Detailed Solution: Question 14

As per the above given table, We can replace the each capital from given relationship for XACGLY , We will get
X → h
A → i
G → j
C → u
L → m
Y → p
Hence , the required answer will be hijump.

MCQ: Coding- Decoding - 2(Medium) - Question 15

Direction: Below are given letter A to Z. Under each capital letter a small letter is written which is to be used as a code for the capital letter:
In each of the following questions, a group of six capital letters is given and its code equivalent is given in one of the columns (1), (2), (3) and (4). Study the group of letters given in each question and with the help of code given above, choose the code equivalent from among (1), (2), (3) and (4) as your answer.
(A) julsqr, mkzbxn , hijmub, vishwa, ocdkzq, zocbak
(B) lzcndo, mzkbxn, ucjlbo, mkzbxn, amwrnd, hmfxco
(C) cxtndo, cvafog, amwnrd, hilmbu, vithwa, ocqzkd
(D) vithaw, mzkbnx, odcazq, napkin, amwrny, hijump

LKFZOS

Detailed Solution: Question 15

As per the above given table, We can replace the each capital from given relationship for LKFZOS , We will get
L → m
K → z
F → k
Z → b
O → x
S → n
Hence , the required answer will be mzkbxn.

Information about MCQ: Coding- Decoding - 2(Medium) Page
In this test you can find the Exam questions for MCQ: Coding- Decoding - 2(Medium) solved & explained in the simplest way possible. Besides giving Questions and answers for MCQ: Coding- Decoding - 2(Medium), EduRev gives you an ample number of Online tests for practice
Download as PDF