MCQ: Problem Based on Ages - 3 - SSC CGL MCQ

Let the present age of A = 6x and B = 7x
8 years ago:
(Ratio of the age of P : Q = 6 : 7
Let the age of P = 6y and Q = 7y)
Present age of P = 6y + 8 and that of Q = 7y + 8
6 years later:
(6x + 6) : (6y + 8 + 6) = 6 : 5
and 7x – (7y + 8) = 13
Solving the above equations, we get:
x = 9 and y = 6
Present age of Q = 7y + 8 = 50 years
Hence, option A is correct.

After 15 years, ratio of the age of A : B = (30 + 15) : (40 + 15) = 9 : 11
After 15 years, ratio of the age of C : D = 9 : 11 and the difference between their age = 6
After 15 years, age of C = 27 and D = 33
Present age of D = 33 – 15 = 18 years
Hence, option D is correct.

After 5 years, ratio of the age of Mother : Daughter = 7 : 2
Let the present age of Mother = 7x – 5 and Daughter = 2x – 5
(7x – 5)² – (2x – 5)² = 875
49x² + 25 −70x – 4x² – 25 + 20x = 875
45x² – 50x – 875 = 0
9x² – 10x – 175 = 0
9x² – 45x + 35x – 175 = 0
x = 5
Present age of Mother = 7x – 5 = 30 years
Daughter = 2x – 5 = 5 years
Hence, option A is correct.

Present age of girl = 10 – (32 – 28) = 6 years
Girl was born 6 years ago, at that time:
Let the age of boy = x and age of the father = 4x
So, age of Wife = 4x − 2
The average age of the family 6 years ago = 28 – 6 = 22
x + 4x + 4x – 2 = 4 × 22
x = 10
Present age of the boy = x + 6 = 16 years
Hence, option D is correct.

Either Amit > Kiran > Rashi or Rashi > Kiran > Amit
Let the ages be (x – 4), x and (x + 4)
(x − 4) × (x + 4) = 240
x = 16
x – 4 = 12 and x + 4 = 20
Ratio of the age of Amit : Kiran = 12 : 16 = 3 : 4
or
20 : 16 = 5 : 4
Hence, option B is correct.

(A + B) : (C + D) = 11 : 7
(X + 12 + X + 16 + 20) : (X + 2 + X – 6 + 20) = 11 : 7
X = 20
10 years ago age of A = 32, B = 36, C = 22 and D = 14
Present age of A = 42, B = 46, C = 32 and D = 24
Present average age of A and D

Hence, option C is correct.

Total age 12 years ago = 6 × 50 = 300
Presently total age would have been = 300 + 6 × 12 = 372
Present total age = 382 years
The difference is because of the substitution of Daughter with Daughter in law
So, the age difference between them = 382 – 372 = 10 years
Hence, option C is correct.

Firdauz, Ali, Sarfaraz, Sameer and Faiz
Faiz : Firdauz = 9 : 5
Let Faiz = 9x, Sameer = 8x, Sarfaraz = 7x, Ali = 6x and Firdauz = 5x
After ‘k’ years ratio of the age of Firdauz : Faiz = 9 : 13
(5x + k) : (9x + k) = 9 : 13
k = 4x
Age of Ali after k years,
z = 6x + 4x = 10x

Hence, option D is correct.

At present let the age of
Jatin = x and Rohan = 8x
6 years later: Rohan = 8x + 6

Jatin = x + 6
Age difference between Jatin and Rekha = 8 – 2 = 6

16x + 12 = 7x + 84
9x = 72
x = 8


Hence, option C is correct.

When Age of A = 2 years
Age of B = 2 × 5 = 10 years
Presently the ratio of their age is 13 : 17
As the age difference between them is 8 years
The present age of A = 26 years and B = 34 years
(26 – x) : (34 – x) = 2 : 3
x = 10
Hence, option D is correct.

Let the age of the grandmother = 8x

Difference = 3x – 2x = (8 + 4)
x = 12
Age of Grandmother = 8 × 12 = 96 years
Age of Ravi = 2x + 8 = 32 years
Age of Chetan = 96 – 32 = 64 years
Reqd. ratio = (32 + 8) : (64 + 8) = 40 : 72 = 5 : 9
Hence, option C is correct.

Let the present age of Garima = G and Sneha = S
(G − 10) : (S − 10) = 2 : 3
(G + 14) : (S + 14) = 6 : 7
Solving we get:
G = 22 and S = 28
Both of them completed high school at the age of 16 years.
As Garima is 6 years younger to Sneha
When Sneha was 16 years old
Age of Garima = 16 – 6 = 10 years
Hence, option B is correct.

12 years ago Sehar was as old as Ada at present
So, Sehar is 12 years elder to Ada
Let the present age of Naira = N, Sehar = 6x and Ada = 6x – 12
When age of Ada becomes = N, Age of Naira = 11x
11x – N = N – (6x – 12)
N = 8.5x – 6
Sum of ages of all = 3 × 35
8.5x – 6 + 6x + 6x – 12 = 105
x = 6
Present age of Naira = 8.5x – 6 = 45
Ada = 24 and Sehar = 36
Age of the oldest one among them = 45 years
Hence, option C is correct.

A + B + C = 3 × 20 = 60

C : (A + B) = 1 : 5
So, C = 10 and A + B = 50
A + 15 = 3(B – 5)
3B = A + 30
and A + B = 50
Solving we get B = 20 and A = 30
When C was born age of A was = 30 – 10 = 20 years
Hence, option A is correct.

Couple got married at the age of 20, x years later a boy was born, y years later two girls were born and each girl is aged 10 years presently
Age of boy = y + 10
Age of the couple = 20 + x + y + 10 = 30 + x + y
(30 + x + y) : (y + 10) = 5 : 2
10 + 2x = 3y -------------- (1)
2(30 + x + y) + y + 10 + 2 × 10 = 116
2x + 3y = 26 --------------- (2)
Solving equations (1) and (2) we get:
x = 4 and y = 6
Present age of the boy = y + 10 = 16 years
Hence, option D is correct.