A series RLC circuit resonates at 1 MHz. At frequency of 1.1 MHz, the circuit impedance will be:
A capacitor C at time t = 0+ with zero initial charge acts as a:
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The condition for the electrical symmetry of the circuit is that
At half power frequencies. the current in the RLC series circuit is:
The 3dB bandwidth of series RLC tuned circuit is 10 KHz and its frequency of resonance is 19000 KHZ. The Q of the circuit is:
The formula for determining the inductance of two coils connected in series aiding is
If f1 and f2 are the 3–dB frequencies and f0 is the frequency of resonance, the the selectivity Q of RLC circuit is given by
A source V has an internal impedance Zin = (R + jx). When it is connected to load of ZL + R –jx, the power transferred is
In the given figure, the Thevenin's equivalent pair (voltage, impedance), as seen at the terminals P – Q, is given by
Two coupled inductors L1 = 0.2 H and L2 = 0.45 H have coefficient of coupling k = 0.8. The mutual inductance M is.
For maximum power transfer, according to maximum power transfer theorem, source impedance
The equivalent inductance of the given circuit between terminals a–b is equal to :
A series resonant circuit has an inductive reactance of 1000W, a capacitive reactance of 1000W and a resistance of 0. 1W. If the resonant frequency is 10 MHz, then the bandwidth of the circuit will be
The resistance 'R' looking into the terminals AB in the circuit shown in the figure will be
In the circuit shown in the figure, the power dissipated in 30W resistor will be maximum if the value of R is