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Numerics (Calculator Req.) - Italian MCQ


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21 Questions MCQ Test - Numerics (Calculator Req.)

Numerics (Calculator Req.) for Italian 2024 is part of Italian preparation. The Numerics (Calculator Req.) questions and answers have been prepared according to the Italian exam syllabus.The Numerics (Calculator Req.) MCQs are made for Italian 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Numerics (Calculator Req.) below.
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Numerics (Calculator Req.) - Question 1

if Numerical Reasoning Test - Algebra Question

what is the value of y?

Detailed Solution for Numerics (Calculator Req.) - Question 1

This numerical reasoning question has two important lessons: taking out the common factor and using the multiple-choice answers to your advantage.

To solve this problem, take out the common factor in the numerator and in the denominator in order to simplify the expression.

The result is:

. You know that

, thus

.

Multiply both sides by 2y and get 5=2y, which is reducible to y=2.5.

While this is a straightforward solution, taking a glance at the possible answers before solving can expedite the process even further. After taking out the common factor, a sharp eye could have noticed that the ratio between the numerator and the denominator is 2.5:y. This is easier to notice if you already know that 2.5 is one of the answers. Looking at the answers can be a helpful tool during numerical reasoning tests

Numerics (Calculator Req.) - Question 2

Numerical Reasoning Test - Gemoetry Question

What is the area of a parallelogram with a base length of 8 cm and a height of 5 cm?

Detailed Solution for Numerics (Calculator Req.) - Question 2

Geometry problems can often seem daunting at first, only because the solver is unaware of a certain basic rule that would clear it all up. In this case, you must realize that a parallelogram is simply a rectangle whose corner has been displaced. If you imagine cutting the polygon in the picture along the dashed line and moving the triangle to the right side, such that d and b are coinciding sides, you get a perfect rectangle.

We know the area of a rectangle is the product of the base and height, so parallelograms will work the same way: the area of a parallelogram equals the product of the length of the base and the corresponding height (i.e. the height that is perpendicular to the chosen base).

Substituting with the numbers from the question: 8 x 5 = 40.

Therefore, the area of the parallelogram is 40 cm2.

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Numerics (Calculator Req.) - Question 3

Which of the following functional groups is present in alcohols?

Detailed Solution for Numerics (Calculator Req.) - Question 3

Alcohols are organic compounds that contain the hydroxyl group (-OH) as their functional group. The hydroxyl group is characterized by the presence of an oxygen atom bonded to a hydrogen atom. This functional group gives alcohols their characteristic properties, such as the ability to undergo reactions like dehydration and esterification.

Numerics (Calculator Req.) - Question 4
In a fruit market, watermelon costs Rs 25 per fruit, mango costs Rs 20 per fruit, an apple costs Rs 15 per fruit, and orange costs Rs 10 per fruit. If Indu bought 2 watermelons, 5 mangoes, 3 apples, and some oranges and paid a bill of Rs 285, what was the number of oranges purchased by her?
Detailed Solution for Numerics (Calculator Req.) - Question 4

Given:

Watermelon costs = Rs. 25 per fruit

Mango costs =  Rs. 20 per fruit

An apple costs = Rs. 15 per fruit

Orange costs = Rs. 10 per fruit

If Indu bought 2 watermelons, 5 mangoes, 3 apples, and some oranges and paid a bill of Rs 285.

Let, Indu buy x orange.

2×25+5×20+3×15+x×10=28550+100+45+10x=28510x=28519510x=90

x=Rs9 per fruit

Hence, the correct answer is "9".

Numerics (Calculator Req.) - Question 5
If 45% percent of X is 60610, then what is the value of X?
Detailed Solution for Numerics (Calculator Req.) - Question 5

Given:

45% × X = 60610

Calculation:

According to the question,

45% × X = 60610

⇒ 45/100 × X = 606/10

⇒ X = 6060/45 

⇒ X = 134.67

∴ The correct answer is  134.67

Numerics (Calculator Req.) - Question 6
Find the number of proper divisors of 500.
Detailed Solution for Numerics (Calculator Req.) - Question 6

Given:

500

Formula:

Number of total divisors = ((a+1)(b+1)) where (a) and (b) are the exponents of the prime factors.
For proper divisors: Subtract 1 to exclude the number itself.

Solution:

Factor = (500=22×53)

((2+1)(3+1) - 1 = 11).

Numerics (Calculator Req.) - Question 7

A, B, and C completed a work costing Rs. 1800. A Work for 6 days, B for 4 days, and C for 9 days. If their daily wages are in the ratio of 5 : 6 : 4, how much amount will be received by A?

Detailed Solution for Numerics (Calculator Req.) - Question 7

Explanation:

Ratio of their daily wages = 5 : 6 : 4

Total wage = Rs. 1800

6 × 5x + 4 × 6x + 4 × 9x = 1800 [As A, B, C works for 6, 4, 9 days respectively]

Or, 90x = 1800

x=180090

Total amount of A = 1800×3090

 = Rs. 600

Numerics (Calculator Req.) - Question 8

The value of 12+13+14+15 is:

Detailed Solution for Numerics (Calculator Req.) - Question 8

Explanation:

Given:

12+13+14+15

=12+13+1215

=12+13+521

=12+16821

=12+2168

=115768

=68157

Numerics (Calculator Req.) - Question 9

The percentage profit earned by selling an article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280. At what price should the article be sold to make 25% profit?

Detailed Solution for Numerics (Calculator Req.) - Question 9

Explanation:

Let C.P. be Rs. x.

Then, 

1920xx×100=x1280x×100

1920x=x1280

2x=3200

x=1600

Required S.P. =125% of Rs. 1600

= Rs. (125100×1600)

= Rs. 2000

Numerics (Calculator Req.) - Question 10

Pratik travels 96 km at a speed of 16 km/hr using a bike, 124 km at 31 km/h by car and another 105 km at 7 km/h in horse cart. Then, find his average speed for the entire distance travelled?

Detailed Solution for Numerics (Calculator Req.) - Question 10

Explanation:

Speed =S=DT

Average Speed = Total distance travelled  Total time taken 

Total distance =96+124+105=325 km

Total Time =t1+t2+t3

=d1 s1+d2 s2+d3 s3

=9616+12431+1057

=25 hours

Average speed =32525

= 13 km/hr

Numerics (Calculator Req.) - Question 11

 P, Q and R are in a cycle race of 4500 meters. P cycles twice as fast as Q. R cycle 13rd as fast as Q. R completes the race in 45 minutes. Then where was Q from the finishing line when P finished the race?

Detailed Solution for Numerics (Calculator Req.) - Question 11

Explanation:

R cycles 13rd as fast as Q.

Speed of R = 13rd of Speed of Q.

 R takes 3 times more time than Q.

R needs 45 minutes to finish the race so Q takes 453=15 minutes to finish the race.

P is twice as fast as Q.

So, P takes half the time as Q =152=7.5 minutes.

 This means that when P reaches the finish line, Q is only half way.

So, Q is at half distance from finish line i.e., 45002

= 2250 m

Numerics (Calculator Req.) - Question 12

The incomes of A and B are in the ratio 3 : 2 and their expenditure are in the ratio 5 : 3. If each saves Rs. 1000, then, A's income can be:

Detailed Solution for Numerics (Calculator Req.) - Question 12

Explanation:

Let income of A and B be 3x and 2x respectively. 

Also, their expenditure is 5y and 3y.

Now, according to question,

3x - 5y = 1000 ------- (i) × 3

2x - 3y = 1000 ---------- (ii) × 5

9x - 15y - 10x + 15y = 3000 - 5000

Or, -x = -2000

x = 2000

Then, 

Income of A = 3x 

= 3 × 2000 

= Rs. 6000

Numerics (Calculator Req.) - Question 13

On a road three consecutive traffic lights change after 36,42 and 72 seconds respectively. If the lights are first switched on at 9:00 AM sharp, at what time will they change simultaneously?

Detailed Solution for Numerics (Calculator Req.) - Question 13

Explanation:

LCM of 36, 42 and 72,

36 = 2 × 2 × 3 × 3

42 = 2 × 3 × 7

72 = 2 × 2 × 2 × 3 × 3

LCM = 2 ×2 × 2 × 3 × 3 × 7 = 504 seconds.

LCM of 36, 42 and 72 is 504

So, the lights will change simultaneously after 8 minutes and 24 seconds.

Numerics (Calculator Req.) - Question 14

From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?

Detailed Solution for Numerics (Calculator Req.) - Question 14

Explanation:

Let S be the sample space.

Then,

n(S)=52C2=(52×51)(2×1)=1326

Let E = event of getting 2 kings out of 4.

n(E)=4C2=(4×3)(2×1)=6

P(E)=n(E)n(S)=61326

=1221

Numerics (Calculator Req.) - Question 15

Vimal can do a piece of work in 20 days, Vimal and Kamal together can do in 12 days. If Kamal does the work only for half a day daily then in how many days the work will be completed?

Detailed Solution for Numerics (Calculator Req.) - Question 15

Explanation:

Vimal's 1 day work =120

Since, Vimal and Kamal can together complete in 12 days.

i.e. (Vimal + Kamal)'s 1 day work =112

Then,

Kamal's 1 day work,

=112120

260 

130

If Kamal Works only for half a day daily, then his 1 day work becomes 12×130=160

Therefore, 1 day work of both Vimal and Kamal,

=120+160 

460 

115

So, the work will be completed in 15 days.

Numerics (Calculator Req.) - Question 16

A group for outdoor games has to be formed out of 10 kids (4 boys and 6 girls). If the group should have more than 2 kids and the number of boys and girls should be equal in the group, then how many groups are possible?

Detailed Solution for Numerics (Calculator Req.) - Question 16

Explanation:

The possible cases can be:

  1. 4 boys and 4 girls
  2. 3 boys and 3 girls
  3. 2 boys and 2 girls

Ways of selecting of 4 boys out of 4=4C4=1

Ways of selecting of 3 boys out of 4=4C3=4

Ways of selecting of 2 boys out of 4=4C2=6

Ways of selecting of 4 girls out of 6=6C4=15

Ways of selecting of 3 girls out of 6=6C3=20

Ways of selecting of 2 girls out of 6=6C2=15

Total possible ways N=(1×15)+(4×20)+(6×15)

N=15+80+90=185

Numerics (Calculator Req.) - Question 17

The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is:

Detailed Solution for Numerics (Calculator Req.) - Question 17

Explanation:

Let P, Q and R represent their respective monthly incomes. 

Then, we have:

P + Q = (5050 x 2) = 10100 .... (i)

Q + R = (6250 x 2) = 12500 .... (ii)

P + R = (5200 x 2) = 10400 .... (iii)

Adding (i), (ii) and (iii), we get:  

2(P + Q + R) = 33000  or   P + Q + R = 16500 .... (iv)

Subtracting (ii) from (iv), we get 

P = 4000.

 P's monthly income = Rs. 4000.

Numerics (Calculator Req.) - Question 18

Sam purchased 20 dozens of toys at the rate of Rs. 375 per dozen. He sold each one of them at the rate of Rs. 33. What was his percentage profit?

Detailed Solution for Numerics (Calculator Req.) - Question 18

Explanation:

Cost Price of 1 toy = Rs. (37512)

= Rs. 31.25

Selling Price of 1 toy = Rs. 33

So, Gain = Rs. (33 - 31.25) 

= Rs. 1.75

Profit %=(1.7531.25×100)%

=285%

= 5.6%

Numerics (Calculator Req.) - Question 19

Each side of a cube is decreased by 25%. Find the ratio of the volume of the original cube and the resulting cube =?

Detailed Solution for Numerics (Calculator Req.) - Question 19

Explanation:

Let the side of cube = 10 cm

∴ Original volume = 10 × 10 × 10 = 1000 cm3

Now, side of new cube: 

= 10 - 25% of 10 = 7.5

∴ New volume = 7.5 × 7.5 × 7.5 = 421.875 cm3

∴ Required ratio:

=1000421.875

=1000000421875

=6427

=64:27

Numerics (Calculator Req.) - Question 20

The radius of the two concentric circles is 9 cm and 15 cm. If the chord of the greater circle be a tangent to the smaller circle, then the length of that chord is:

Detailed Solution for Numerics (Calculator Req.) - Question 20

Explanation:

BO=OC=15 cm

OD=9 cm

BD=15292

=24×6

=12 cm

BC=2×12

= 24 cm

Numerics (Calculator Req.) - Question 21

A hollow spherical metallic ball has an external diameter 6cm and is 12 cm thick. The volume of metal used in the ball is:

Detailed Solution for Numerics (Calculator Req.) - Question 21

Explanation:

External radius = 3 cm

Internal radius = (3 - 0.5) cm 

= 2.5 cm

Volume of the metal:

=[43×227×{(3)3(2.5)3}]cm3

=(43×227×918)cm3

=(1433)cm3

=4723 cm3

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