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Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - JEE MCQ


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30 Questions MCQ Test - Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics)

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Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 1

Direction (Q. Nos. 1-12) This section contains 12 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.

For the first order gaseous phase reaction, A → B + C

initial pressure is 200 mm and after 20 min, total pressure is 250 mm. Thus, half-life period is 

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 1







Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 2

For the elementary reaction (M → N), the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is

[JEE Advanced 2014]

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 2


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Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 3

For the reaction,

experimental data for the measured initial rates is given below.

Q.

The order of the reaction with respect of P,Q and R respectively is

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 3







Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 4

Reaction coordinate diagram for the reaction

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 4

 By Arrhenius equation




Given reaction is endothermic, ΔH = + 103.1kJ.
Thus, reaction-coordinate diagram is

Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 5

For a reaction, k = 1.2 x 103 mol-1 L s-1 and Ea = 2.0 x 102 kJ mol-1

When T→ ∞, Arrhenius pre-exponential factor is

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 5

By Arrhenius equation,


Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 6

Half-life period of the first order reaction is 100 days. After 144.3 days, concentration of the reactant is reduced to ......of the original value.

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 6






Thus, concentration is reduced to   of the initial value.

Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 7

For the following chemical equation, a first order reaction, A(g) → nB(g) total pressure of the system as a function of time is 

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 7







Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 8

What function of [X], plotted against time will give a straight line for a second order reaction?

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 8

For a second order reaction





Thus, (i) represents a straight line.
Hence,  when plotted against time
will give a straight line.

Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 9

The rate constant at 298 K for the reaction of and OH+ to form NH4OH is 4 .0 x 1010 M-1 s-1. Thus, rate constant for proton transfer to NH3 is

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 9








Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 10

For a reaction A → Product

[A]0 = Initial concentration, [A] = Concentration of the reactant A after time t.

Then

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 10

This represents a second order reaction







Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 11

For a second order reaction,

where and a and b are the initial concentrations of A and B. Reaction w ould be pseudo-unimolecular when

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 11




This represents unimolecular reaction.

Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 12

A certain reaction, A + B → Product

is first order w.r.t. each reactant with k = 5.0 x 10-3 M-1 s-1

then concentration of A remaining after 100 s is 

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 12


Thus, concentration of B almost remains constant and reaction is first order w.r.t. A only.



*Multiple options can be correct
Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 13

Direction (Q. Nos. 13-16) This section contains 4 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q.

Rate constant k varies with tem perature as given by the equation

Select the correct statement(s) about this equation.

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 13



(a) Unit of k is min-1, hence it is first order reaction thus (a) is correct.



Thus, (c) is correct.


Thus, (d) is correct.

*Multiple options can be correct
Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 14

Which is/are the graphical representation for the zeroth order reaction?

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 14


Thus, rate remains constant.
Thus, (a) is correct.

In (c), rate increases with time.

Hence log(x) varies as log(t) increases. Thus, (d) is also correct.

*Multiple options can be correct
Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 15

Select the correct staiement(s) about half-life period,

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 15

For zero order reaction














*Multiple options can be correct
Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 16

For the reaction,

In alkaline aqueous solution, the value of the second order (in BrC-), rate constant at 80°C in the rate law for   was found to be 0.056 L mol-1 s-1

Select the correct alternate reaction.

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 16








Thus, (b) is correct.
BrO- has been oxidised to  and has been reduced to Br-.
Thus, it is a redox as well as disproportionation reaction.
Thus, (c) and (d) are correct.

Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 17

Direction (Q. No. 17) Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.

Q. Rate law of the nth order reaction is given by

Match the different properties in Column I with their related values of half-life in Column II and select the correct answer from the codes given.

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 17
















Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 18

Direction (Q. Nos. 18-27) This section contains 5 paragraphs, each describing theory, experiments, data, etc. Ten questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage I

A 22.4 L flask contains 0.76 mm of O3 at 298 K. It reacts with oxygen atoms as 
O + O3 → 2O2, k = 1.5 x 107 L mol-1 s-1 at the rate of 0.15 mol L-1 s-1.

Q. 

What is the concentration of oxygen atoms needed to maintain this rate?

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 18




Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 19

Passage I

A 22.4 L flask contains 0.76 mm of O3 at 298 K. It reacts with oxygen atoms as 
O + O3 → 2O2, k = 1.5 x 107 L mol-1 s-1 at the rate of 0.15 mol L-1 s-1.

Q. 

What is the rate of formation oxygen (O2) under these conditions?

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 19




Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 20

Passage II

The complex ion of Fe2+ with the chelating agent diphyridyl (abbreviated as dipy) has been studied kinetically in both the forward and the reverse directions.


Q. 

Half-life of the reverse reaction is

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 20

For reverse reaction

It follows first order kinetics with rate constant.
 

Stability constant is obtained when rate of forward reaction
= rate of reverse reaction 

Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 21

Passage II

The complex ion of Fe2+ with the chelating agent diphyridyl (abbreviated as dipy) has been studied kinetically in both the forward and the reverse directions.


Q. 

Stability constant in terms of pk is

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 21

For reverse reaction

It follows first order kinetics with rate constant 


Stability constant is obtained when rate of forward reaction
= rate of reverse reaction


Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 22

Passage III

Also, t1 = t2 and [A]0 = [B]0 = a

Q. 

The ratio of the rates of these two reactions at the start of the reaction is

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 22










Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 23

Passage III

Also, t1 = t2 and [A]0 = [B]0 = a

Q. 

The ratio of the rates of these two reaction after a lapse of one half-life is

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 23










Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 24

Passage IV

The rate constant for the decomposition of ethylene oxide into CH4 and CO may be described by

Q. 

Energy of activation for this reaction is 

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 24






Unit of k indicates that reaction of first order. Rate constant at 670 K is

Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 25

Passage IV

The rate constant for the decomposition of ethylene oxide into CH4 and CO may be described by

Q. 

What is the rate constant at 670 K?

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 25






Unit of k indicates that reaction of first order. Rate constant at 670 K is

Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 26

Passage V

The following first order reaction is conducted in CCI4(l)at 45°.

An 80.0 g sample of N2O5(g)is dissolved inCCI4(l) and allowed to decompose at 450°C.

Q. 

Time taken for the quantity of N2O5 to be reduced to 2.5 g is

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 26

In CCI4(l), N2O5 and N2O4 are soluble. Hence, volume of O2 is only formed.









Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 27

Passage V

The following first order reaction is conducted in CCI4(l)at 45°.

An 80.0 g sample of N2O5(g)is dissolved inCCI4(l) and allowed to decompose at 450°C.

Q. 

Volume of O2 produced at STP at this point is

Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 27

InCCI4(l), N2O5 and N2O4 are soluble. Hence, volume of O2 is only formed.








*Answer can only contain numeric values
Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 28

Direction (Q. Nos. 28-37) This section contains 10 questions. When worked out will result in one integer from 0 to 9 (both inclusive).

The concentration of R in the reaction,

R→ P

was measured as a function of time and the following data is obtained :

Q. 

What is the order of reaction?

[IIT JEE 2010]


Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 28


Rate remains constant throughout thus, order = zero

*Answer can only contain numeric values
Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 29

For the reaction system,

volume is suddenly reduced to half its value by increasing the pressure on it. If the reaction is of first order w.r.t. O2 and the second order w.r.t. NO, the rate of reaction will increase ......times of its initial value.


Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 29


Thus, rate increases 8 times of its initial value.

*Answer can only contain numeric values
Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 30

For the reaction, 

Initial pressure of A and B are respectively 0.60 atm and 0.80 atm. At a time when pressure of C is 0.20 atm, ratio of initial rate and final rate is y. What is the value of y?


Detailed Solution for Revisal Problems (Past 13 Years) JEE Advanced (Chemical Kinetics) - Question 30





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