Test: Case Study - CUET Humanities MCQ
15 Questions MCQ Test - Test: Case Study
Directions: Study the following information and answer the question.
We have two capacitors P and Q of same capacitance C and the separation between the plates of both the capacitors is 'd'. The area of each plate is 'A'. P is connected to a battery of potential difference V and it remains connected to the battery even after charging is over. There is an electric field E which exists between the plates of capacitor P. Capacitor Q is also connected to a battery of same potential V and is disconnected after the battery is full charged. Electric field in capacitor Q is E1. Before inserting the dielectric slab, energy stored in both the capacitors is U1. A dielectric slab having dielectric constant K = 5 is inserted in the both the capacitors. Energy stored in capacitor P after inserting the dielectric slab is U.
Q. If we increase the separation between the plates of P, what will happen to the electric field intensity (E) between the plates of capacitors?
We have two capacitors P and Q of same capacitance C and the separation between the plates of both the capacitors is 'd'. The area of each plate is 'A'. P is connected to a battery of potential difference V and it remains connected to the battery even after charging is over. There is an electric field E which exists between the plates of capacitor P. Capacitor Q is also connected to a battery of same potential V and is disconnected after the battery is full charged. Electric field in capacitor Q is E1. Before inserting the dielectric slab, energy stored in both the capacitors is U1. A dielectric slab having dielectric constant K = 5 is inserted in the both the capacitors. Energy stored in capacitor P after inserting the dielectric slab is U.
Directions: Study the following information and answer the question.
We have two capacitors P and Q of same capacitance C and the separation between the plates of both the capacitors is 'd'. The area of each plate is 'A'. P is connected to a battery of potential difference V and it remains connected to the battery even after charging is over. There is an electric field E which exists between the plates of capacitor P. Capacitor Q is also connected to a battery of same potential V and is disconnected after the battery is full charged. Electric field in capacitor Q is E1. Before inserting the dielectric slab, energy stored in both the capacitors is U1. A dielectric slab having dielectric constant K = 5 is inserted in the both the capacitors. Energy stored in capacitor P after inserting the dielectric slab is U.
Q. Charge is stored in capacitor Q. What will be charge on plates if a dielectric slab with dielectric constant K = 5 is inserted between the plates of capacitor Q?
We have two capacitors P and Q of same capacitance C and the separation between the plates of both the capacitors is 'd'. The area of each plate is 'A'. P is connected to a battery of potential difference V and it remains connected to the battery even after charging is over. There is an electric field E which exists between the plates of capacitor P. Capacitor Q is also connected to a battery of same potential V and is disconnected after the battery is full charged. Electric field in capacitor Q is E1. Before inserting the dielectric slab, energy stored in both the capacitors is U1. A dielectric slab having dielectric constant K = 5 is inserted in the both the capacitors. Energy stored in capacitor P after inserting the dielectric slab is U.
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Directions: Study the following information and answer the question.
A parallel plate capacitor having capacitance C is connected to an ideal battery, having potential difference V, for a very long time so that the capacitor becomes fully charged. Energy E is stored in the capacitor after full charging. Work is done by the battery W while charging the capacitor because the battery pulls the electrons from one plate to the other plate. During this charge transfer from one to another, there is some loss of energy in the form of heat (H). The battery is disconnected after full charging and is connected to the opposite polarity. Now, heat lost in this time while charging the capacitor is Q.
Q. Energy stored (E) in the capacitor after charging it the first time will be:
A parallel plate capacitor having capacitance C is connected to an ideal battery, having potential difference V, for a very long time so that the capacitor becomes fully charged. Energy E is stored in the capacitor after full charging. Work is done by the battery W while charging the capacitor because the battery pulls the electrons from one plate to the other plate. During this charge transfer from one to another, there is some loss of energy in the form of heat (H). The battery is disconnected after full charging and is connected to the opposite polarity. Now, heat lost in this time while charging the capacitor is Q.
Directions: Study the following information and answer the question.
A parallel plate capacitor having capacitance C is connected to an ideal battery, having potential difference V, for a very long time so that the capacitor becomes fully charged. Energy E is stored in the capacitor after full charging. Work is done by the battery W while charging the capacitor because the battery pulls the electrons from one plate to the other plate. During this charge transfer from one to another, there is some loss of energy in the form of heat (H). The battery is disconnected after full charging and is connected to the opposite polarity. Now, heat lost in this time while charging the capacitor is Q.
Q. What will be the total work done 'W' by the battery?
Directions: Study the following information and answer the question.
Two small metal spheres of radii r1 and r2 carry charges q1 and q2, respectively, such that they have same polarity. Both the spheres are widely separated from each other so that Coulomb's force of interaction can be ignored. Both the spheres are connected by a metal wire. V1 and V2 are electrical potentials on spheres a and b, respectively. After connecting the metallic wire, the surface density on spheres 'a' and 'b' is σ1 and σ2. Both the spheres are made up of metal. Electric field inside the spheres is Ea and Eb. After connecting the spheres by the metal wire, potential inside the spheres is V3 and V4, respectively.
Q. Assertion: The ratio of potentials, V1/V2 , of both the spheres will be 1.
Reason: Their ratio will depend upon the radius.
Directions: Study the following information and answer the question.
Two small metal spheres of radii r1 and r2 carry charges q1 and q2, respectively, such that they have same polarity. Both the spheres are widely separated from each other so that Coulomb's force of interaction can be ignored. Both the spheres are connected by a metal wire. V1 and V2 are electrical potentials on spheres a and b, respectively. After connecting the metallic wire, the surface density on spheres 'a' and 'b' is σ1 and σ2. Both the spheres are made up of metal. Electric field inside the spheres is Ea and Eb. After connecting the spheres by the metal wire, potential inside the spheres is V3 and V4, respectively.
Q. Assertion: The charge on both the spheres lies on their surfaces before connecting them.
Reason: The charge on both the spheres lies outside the spheres since the electric field (Ea and Eb) inside both the metal spheres metallic sphere is zero.
Directions: Study the following information and answer the question.
The electric line of force points in the direction of electric field. The electric line of force may be straight or curved. In case, the electric line of force is a curve, then the direction of electric field at any point is given tangent to the electric line of force at the point. The strength of the electric line of force at any point is measured as the number of lines of force crossing a unit area held normal to the line of force at that point.
Reference - Modern's book, edition 2015, page no. 45
Q. Which of the following statements is true?
Directions: Study the following information and answer the question.
The electric line of force points in the direction of electric field. The electric line of force may be straight or curved. In case, the electric line of force is a curve, then the direction of electric field at any point is given tangent to the electric line of force at the point. The strength of the electric line of force at any point is measured as the number of lines of force crossing a unit area held normal to the line of force at that point.
Reference - Modern's book, edition 2015, page no. 45
Q. If we have uniform electric field and their lines of force, which of the following statements is true for the electric lines of force?
Directions: Study the following information and answer the question.
We have two capacitors P and Q of same capacitance C and the separation between the plates of both the capacitors is 'd'. The area of each plate is 'A'. P is connected to a battery of potential difference V and it remains connected to the battery even after charging is over. There is an electric field E which exists between the plates of capacitor P. Capacitor Q is also connected to a battery of same potential V and is disconnected after the battery is full charged. Electric field in capacitor Q is E1. Before inserting the dielectric slab, energy stored in both the capacitors is U1. A dielectric slab having dielectric constant K = 5 is inserted in the both the capacitors. Energy stored in capacitor P after inserting the dielectric slab is U.
Q. A dielectric slab of dielectric constant K = 5 is inserted between the plates of P. If U1 is the energy stored before the insertion of the dielectric slab, what will be the energy stored (U) after introducing the dielectric slab?
Directions: Study the following information and answer the question.
We have two capacitors P and Q of same capacitance C and the separation between the plates of both the capacitors is 'd'. The area of each plate is 'A'. P is connected to a battery of potential difference V and it remains connected to the battery even after charging is over. There is an electric field E which exists between the plates of capacitor P. Capacitor Q is also connected to a battery of same potential V and is disconnected after the battery is full charged. Electric field in capacitor Q is E1. Before inserting the dielectric slab, energy stored in both the capacitors is U1. A dielectric slab having dielectric constant K = 5 is inserted in the both the capacitors. Energy stored in capacitor P after inserting the dielectric slab is U.
Q. What will be the potential difference between the plates of capacitor Q, when a dielectric slab of dielectric constant K = 5 is inserted between the plates of capacitors?
Directions: Study the following information and answer the question.
A parallel plate capacitor having capacitance C is connected to an ideal battery, having potential difference V, for a very long time so that the capacitor becomes fully charged. Energy E is stored in the capacitor after full charging. Work is done by the battery W while charging the capacitor because the battery pulls the electrons from one plate to the other plate. During this charge transfer from one to another, there is some loss of energy in the form of heat (H). The battery is disconnected after full charging and is connected to the opposite polarity. Now, heat lost in this time while charging the capacitor is Q.
Q. Amount of heat lost (H) in the charging process is
Directions: Study the following information and answer the question.
A parallel plate capacitor having capacitance C is connected to an ideal battery, having potential difference V, for a very long time so that the capacitor becomes fully charged. Energy E is stored in the capacitor after full charging. Work is done by the battery W while charging the capacitor because the battery pulls the electrons from one plate to the other plate. During this charge transfer from one to another, there is some loss of energy in the form of heat (H). The battery is disconnected after full charging and is connected to the opposite polarity. Now, heat lost in this time while charging the capacitor is Q.
Q. After re-connecting the same battery to the reverse polarity, what will be the heat lost (Q) in the charging process?
Directions: Study the following information and answer the question.
Two small metal spheres of radii r1 and r2 carry charges q1 and q2, respectively, such that they have same polarity. Both the spheres are widely separated from each other so that Coulomb's force of interaction can be ignored. Both the spheres are connected by a metal wire. V1 and V2 are electrical potentials on spheres a and b, respectively. After connecting the metallic wire, the surface density on spheres 'a' and 'b' is σ1 and σ2. Both the spheres are made up of metal. Electric field inside the spheres is Ea and Eb. After connecting the spheres by the metal wire, potential inside the spheres is V3 and V4, respectively.
Q. Assertion: The ratio of surface charge densities, σ1/σ2, of both the spheres a/b is 1.
Reason: Surface charge density is independent of radius.
Directions: Study the following information and answer the question.
Two small metal spheres of radii r1 and r2 carry charges q1 and q2, respectively, such that they have same polarity. Both the spheres are widely separated from each other so that Coulomb's force of interaction can be ignored. Both the spheres are connected by a metal wire. V1 and V2 are electrical potentials on spheres a and b, respectively. After connecting the metallic wire, the surface density on spheres 'a' and 'b' is σ1 and σ2. Both the spheres are made up of metal. Electric field inside the spheres is Ea and Eb. After connecting the spheres by the metal wire, potential inside the spheres is V3 and V4, respectively.
Q. Assertion: Electric potential (V3 and V4) inside both the spheres remains constant.
Reason: Electric field inside both the spheres is zero.
Directions: Study the following information and answer the question.
The electric line of force points in the direction of electric field. The electric line of force may be straight or curved. In case, the electric line of force is a curve, then the direction of electric field at any point is given tangent to the electric line of force at the point. The strength of the electric line of force at any point is measured as the number of lines of force crossing a unit area held normal to the line of force at that point.
Reference - Modern's book, edition 2015, page no. 45
Q. What will happen if we insert a free positive charge particle at some velocity and at certain angle in electric field?
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