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Test: Dual Nature of Radiation and Matter - 1 - CUET Humanities MCQ


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10 Questions MCQ Test - Test: Dual Nature of Radiation and Matter - 1

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Test: Dual Nature of Radiation and Matter - 1 - Question 1

In photoelectric effect, the electrons are ejected from metals if the incident light has a certain minimum

Detailed Solution for Test: Dual Nature of Radiation and Matter - 1 - Question 1

In photoelectric effect for a given photosensitive material, there exists a certain minimum cut-off frequency, called the threshold frequency, below which no emission of photoelectrons takes place, no matter how intense the light is.

Test: Dual Nature of Radiation and Matter - 1 - Question 2

An X-ray tube produces a continuous spectrum of radiation with its short-wavelength end at 0.33Å. What is the maximum energy (Planck's constant = 6.6 x 10-34 Js) of a photon in the radiation?

Detailed Solution for Test: Dual Nature of Radiation and Matter - 1 - Question 2

Energy will be maximum corresponding to the minimum wavelength.


or
E = 37500 eV
E = 37.5 keV

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Test: Dual Nature of Radiation and Matter - 1 - Question 3

A and B are two metals with threshold frequencies 1.8 x 1014 Hz and 2.2 × 1014 Hz, respectively. Two identical photons of energy 0.825 eV are incident on them. Then, the photoelectrons (take h = 6.6 × 10-34 J-s) are emitted by

Detailed Solution for Test: Dual Nature of Radiation and Matter - 1 - Question 3

Test: Dual Nature of Radiation and Matter - 1 - Question 4

Consider the following two statements A and B, and identify the correct answer.
A: For electrons, the value of specific charge depends upon the gas taken in the tube.
B: Increase in the intensity of incident radiation in photoelectric emission increases the number of photoelectrons.

Detailed Solution for Test: Dual Nature of Radiation and Matter - 1 - Question 4

Specific charge of electrons is independent of gas taken.
Increase in photo intensity increases the number of electrons.

Test: Dual Nature of Radiation and Matter - 1 - Question 5

The photoelectric threshold for a certain metal surface is 330 Å. What is the maximum kinetic energy of a photoelectron released, if any, by a radiation of wavelength 1100 Å?

Detailed Solution for Test: Dual Nature of Radiation and Matter - 1 - Question 5

Wavelength of incident radiation is λ = 1100 Å = 1100 x 10-10m. Therefore, frequency of incident radiation is 

Threshold wavelength is λ0 = 330 Å = 330 x 10-10 m. Therefore, threshold frequency is 

Since v < vn, no photoelectron is emitted.

Test: Dual Nature of Radiation and Matter - 1 - Question 6

If the energy of a photon corresponding to a wavelength of 6000Å is 3.32 × 10-19 J, the photon energy for a wavelength of 4000 Å will be

Detailed Solution for Test: Dual Nature of Radiation and Matter - 1 - Question 6

From Planck's quantum theory, light travels in the form of small bundles or packets of energy called photons. The energy of each photon is
E = hv = 
where h is Planck's constant, v is frequency, c is speed of light and  is wavelength.
Given,  = 6000 , E1 = 3.32 × 10-19 J,  = 4000 .
∴ 
⇒ 
⇒ E2 = × 3.32 × 10-19 J
= 4.98 × 10-19 J
 eV = 3.1 eV

Test: Dual Nature of Radiation and Matter - 1 - Question 7

When a light of wavelength 300 nm falls on a photoelectric emitter, the photoelectrons are just liberated. For another emitter, the light of wavelength 600 nm is sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is

Detailed Solution for Test: Dual Nature of Radiation and Matter - 1 - Question 7

Work function is given by 
Where  is the threshold wavelength.

Test: Dual Nature of Radiation and Matter - 1 - Question 8

Ultraviolet radiation of energy 6.2 eV falls on the surface of aluminium of work function 4.2 eV. What will be the K.E. of the fastest electron (in joule)?

Detailed Solution for Test: Dual Nature of Radiation and Matter - 1 - Question 8

K.E. of emitted electrons = radiation of energy - work function
= 6.2 eV - 4.2 eV = 2 eV = 2 x 1.6 x 10-19 J = 3 x 10-19 (approx.)

Test: Dual Nature of Radiation and Matter - 1 - Question 9

A metal whose work function is 3.3 eV is illuminated by light of wavelength 3 × 10-7 m. What is the stopping potential? (Planck's constant = 6.6 × 10-34 Js)

Detailed Solution for Test: Dual Nature of Radiation and Matter - 1 - Question 9

hv = hvo + Emax
Emax = eV0, where V0 is the stopping potential.
Therefore, 

Test: Dual Nature of Radiation and Matter - 1 - Question 10

The photoelectric effect is based on the law of conservation of

Detailed Solution for Test: Dual Nature of Radiation and Matter - 1 - Question 10

The photoelectric effect is based on the law of conservation of energy.
Energy of the emitted photon = Energy of the incident photon - Work Function

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