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Test: Amines & Biomolecules (March 6) - NEET MCQ


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30 Questions MCQ Test - Test: Amines & Biomolecules (March 6)

Test: Amines & Biomolecules (March 6) for NEET 2024 is part of NEET preparation. The Test: Amines & Biomolecules (March 6) questions and answers have been prepared according to the NEET exam syllabus.The Test: Amines & Biomolecules (March 6) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Amines & Biomolecules (March 6) below.
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Test: Amines & Biomolecules (March 6) - Question 1

Which of the following carbohydrates are branched polymer of glucose?

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 1

The correct answer is option B.
Amylopectin is insoluble in water and constitutes about 80−85% of starch. It is a branched-chain polymer of −D− glucose units in which chain is formed by C1−C4 glycosidic linkage whereas branching occurs by C1−C6 glycosidic linkage. Glycogen: The carbohydrates are stored in the animal body as glycogen. It is also known as animal starch because its structure is similar to amylopectin and is rather more highly branched.

Test: Amines & Biomolecules (March 6) - Question 2

Which of the following statements is not true about glucose?

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 2

The correct answer is Option C.
Glucose is an aldohexose having structural formula.

Glucose on heating with HI produces n hexane.
C6H12O6 --HI→C6H14
Glucose does not give 2,4. DNP test due to its existence as cyclic structure shown below :

It is present in pyranose form, as shown below 

Pyranose means pyran (membered ring containing oxygen) like structure.

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Test: Amines & Biomolecules (March 6) - Question 3

Glycogen is a branched chain polymer of α-D-glucose units in which chain is formed by C1—C4 glycosidic linkage whereas branching occurs by the formation of C1-C6 glycosidic linkage. Structure of glycogen is similar to ______.

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 3

Glycogen is a branched chain polymer of αD glucose units in which chain is formed by C1−C4 glycosidic linkage whereas branchin occurs by the formation of C1−C6 glycosidic linkage. Structure of glycogen can be shown below similar to the sturcture amplopectin.

Test: Amines & Biomolecules (March 6) - Question 4

We can obtain ethylamine by Hoffmann bromamide reaction. The amide used in this reaction is:

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 4

The correct answer is option C
CH3​CH2​CONH2​ (A)⟶ CH3​ − CH2 ​− NH2​ (B)⟶ ​CH3​ − CH2 ​− OH
In the above sequence A & B respectively are Br2​/KOH and HNO2
The first step is Hoffmann bromamide degradation reaction in which an amide (propanamide) is converted to an amine  (ethylamine) containing one carbon atom less. The reagent A is bromine in presence of KOH. In the second step, aliphatic primary amine (ethyl amine) reacts with nitrous acid (reagent B) to form aliphatic primary alcohol (ethyl alcohol).
 

Test: Amines & Biomolecules (March 6) - Question 5

 When Primary amide is treated with an aqueous solution of KOH and bromine, it gives a primary amine. The name of the reaction is:

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 5

Hoffmann Bromamide reaction is Treatment of alkylamide with KOH and Bromine gas which converts it into alkylamine with one less carbon atom, this reaction is generally helpful in converting Carboxylic acids to amines with one less carbon atom . For reaction you may refer to internet but i can give you a hint .

 

Acetamide + KOH + Bromine gas —-> Alkylamine+ KBr + K2CO3 + H20 ( not sure about the products)

Test: Amines & Biomolecules (March 6) - Question 6

Which of the following reactions of glucose can be explained only by its cyclic structure?

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 6

Due to absence of free OH group at Ccyclic structure of glucose pentacetate cannot revert to open chain aldehydic form and hence cannot form an oxime. 

Test: Amines & Biomolecules (March 6) - Question 7

Sucrose (cane sugar) is a disaccharide. One molecule of sucrose on hydrolysis gives _________.

Test: Amines & Biomolecules (March 6) - Question 8

Dinucleotide is obtained by joining two nucleotides together by phosphodiester linkage. Between which carbon atoms of pentose sugars of nucleotides are these linkages present?

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 8

The correct answer is option A
Nucleotides are joined together by phosphodiester linkage between 5′ and 3′ carbon atoms of pentose sugar.
 

Test: Amines & Biomolecules (March 6) - Question 9

Structure of a disaccharide formed by glucose and fructose is given below. Identify anomeric carbon atoms in monosaccharide units.

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 9

The correct answer is option C
'a' carbon of glucose and 'b' carbon of fructose
Carbon adjacent to the oxygen atom in the cyclic structure of glucose or fructose is known as anomeric carbon. As shown in the structure above ‘a’ and ‘b’ are present adjacent to an oxygen atom. Both carbons differ in configurations of the hydroxyl group.

Test: Amines & Biomolecules (March 6) - Question 10

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 10

Options A is correct.
In lysine,the amino group is attached to alpha carbon which makes it alpha amino acid and it has more amino groups as compared to -COOH groups, thus basic.

Test: Amines & Biomolecules (March 6) - Question 11

Which reaction can be used for the direct conversion of amides into 10 amine ?

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 11

The correct answer is option A
Reduction with LiAlH4

 

Test: Amines & Biomolecules (March 6) - Question 12

Which of the following is NOT a culinary use of oil in the food industry?

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 12

 Flavor, texture and shortening are all major culinary uses of oil in the food industry.

Test: Amines & Biomolecules (March 6) - Question 13

In fibrous proteins, polypeptide chains are held together by ___________.

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 13

The correct answer are options B.
In fibrous proteins, polypeptide chains are held together by hydrogen and disulphide bonds, in parallel manner. Due to which fibre-like structure is obtained. Such proteins are generally known as fibrous proteins. These proteins are generally insoluble in water e.g., keratin, myosin.

Test: Amines & Biomolecules (March 6) - Question 14

To convert methyl cyanide to ethylamine we use:

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 14

LiAlH4 reduces all oxiginated functional groups to alcohol and all nitrogenated functional groups to amine thus cyanide is a nitrogenated functional group and to convert cyanide to amine LiAlH4 can be used.

Test: Amines & Biomolecules (March 6) - Question 15

Propanamide on treatment with bromine in an aqueous solution of sodium hydroxide gives:

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 15

Test: Amines & Biomolecules (March 6) - Question 16

Which of the following B group vitamins can be stored in our body?

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 16

The correct answer is option  D
Vitamin B12
The body has a limited capacity to store most of the B-group vitamins except B12 and folate, which are stored in the liver.

Test: Amines & Biomolecules (March 6) - Question 17

Carbohydrates are classified on the basis of their behaviour on hydrolysis and also as reducing or non-reducing sugar. Sucrose is a __________.

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 17

The correct answer is D. Both b and c.
One of the common disaccharides is sucrose which on hydrolysis gives an equimolar mixture of D−(+)− glucose and D−(−) fructose. These two monosaccharides are held together by a glycosidic linkage between Cl of α- glucose and C2 of β- fructose. Since the reducing groups of glucose and fructose are involved in glycosidic bond formation, sucrose is a non-reducing sugar.

Test: Amines & Biomolecules (March 6) - Question 18

Each polypeptide in a protein has amino acids linked with each other in a specific sequence. This sequence of amino acids is said to be ____________.

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 18

The primary structure of a protein refers to the sequence of amino acids in the polypeptide chain. The primary structure is held together by peptide bonds that are made during the process ofprotein biosynthesis.

Test: Amines & Biomolecules (March 6) - Question 19

Nucleic acids are the polymers of ______________.

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 19

Nucleotides are organic molecules that serve as the monomer units for forming the nucleic acid polymers deoxyribonucleic acid and ribonucleic acid, both of which are essential biomolecules within all life-forms on Earth.

Test: Amines & Biomolecules (March 6) - Question 20

Which of the following terms are correct about enzyme?

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 20

The correct answer is option A
Life is possible due to the coordination of various chemical reactions in living organisms. This occurs with the help of certain biocatalysts called enzymes. Almost all the enzymes are globular protein.

Test: Amines & Biomolecules (March 6) - Question 21

 Gabriel phthalimide synthesis is used in the preparation of :

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 21

The correct answer is option D
The chemical reaction used for transforming primary alkyl halides into primary amines is called Gabriel phthalimide synthesis. It uses potassium phthalimide. Therefore, Gabriel phthalimide synthesis is used in the preparation of 1o
amide.

Test: Amines & Biomolecules (March 6) - Question 22

Three cyclic structures of monosaccharides are given below which of these are anomers.
  

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 22

Structures (I and II) differ only in the position of OH at Cand hence are anomers. 

Test: Amines & Biomolecules (March 6) - Question 23

Which of the following are purine bases?

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 23

Correct answer is A. Guanine

Test: Amines & Biomolecules (March 6) - Question 24

Aniline can be prepared by:

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 24

Aniline is prepared commercially by the catalytic hydrogenation of nitrobenzene or by the action of ammonia on chlorobenzene. The reduction of nitrobenzene can also be carried out with iron borings in aqueous acid. A primary aromatic amine, aniline is a weak base and forms salts with mineral acids.

Test: Amines & Biomolecules (March 6) - Question 25

Which one of the following bases is not present in DNA?

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 25

Quinoline is an alkaloid, it is not present in DNA. DNA  has four nitrogen bases in adenine, guanine, cytosine and  thymine

Test: Amines & Biomolecules (March 6) - Question 26

 is a tertiary amine having IUPAC name as:

Test: Amines & Biomolecules (March 6) - Question 27

Proteins are found to have two different types of secondary structures viz. α-helix and β-pleated sheet structure. α-helix structure of protein is stabilised by :

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 27

In α-helix, hydrogen bonds are present between –NH group of one amino acid residue to the >C= O group of another aminoacid residue.

Test: Amines & Biomolecules (March 6) - Question 28

Three structures are given below in which two glucose units are linked. Which of these linkages between glucose units are between C1 and C4 and which linkages are between C1 and C6?

 

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 28

The correct answer is Option C.

(i)   The first structure is lactose, the linkage is (A) C1−C4 glycosidic linkage.
(ii)  The 2nd structure has C1−C6 linkages.
(iii) The 3rd structure has C1−C4 linkages.

Test: Amines & Biomolecules (March 6) - Question 29

Proteins can be classified into two types on the basis of their molecular shape i.e., fibrous proteins and globular proteins. Examples of globular proteins are :
(Multiple Answer Correct)

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 29

The correct answer is A .
The structure of protein which results when the chain of polypeptides coil around to give a spherical shape are known as globular protein. These proteins are soluble in water, e.g., insulin and albumin are globular protein.

Test: Amines & Biomolecules (March 6) - Question 30

Which of the following polymer is stored in the liver of animals?

Detailed Solution for Test: Amines & Biomolecules (March 6) - Question 30

If blood glucose levels become too low, glucagon (pancreatic hormone) is released, which causes the liver to convert the stored glycogen back into glucose, and release it into the bloodstream.

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